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4/30 Alg2: Review of Zeros and Theorems of Polynomials

4/30 Alg2: Review of Zeros and Theorems of Polynomials

Assessment

Presentation

Mathematics

11th Grade

Practice Problem

Hard

CCSS
HSF-IF.C.7C, HSA.APR.B.3, HSA.APR.B.2

+1

Standards-aligned

Created by

Kourtney Kukowski

Used 9+ times

FREE Resource

2 Slides • 9 Questions

1

Zeros of Polynomials and Theorems About Polynomials

Let's review 3-5 and 3-6 for our test next week!

Slide image

2

Multiple Choice

Question image

Which of the following is NOT a zero of the polynomial?

1

(0, 0)

2

(-3, 0)

3

(1, 0)

4

(4, 0)

3

Multiple Choice

Which of the following is NOT a zero of the polynomial?

 f(x)=x(x1)(x+7)f\left(x\right)=x\left(x-1\right)\left(x+7\right)  

1

x = 0

2

x = -1

3

x = 1 

4

x = -7

4

Multiple Choice

Which of the following is NOT a zero of the polynomial?

 f(x)=(x5)(x+2)(x+6)f\left(x\right)=\left(x-5\right)\left(x+2\right)\left(x+6\right)  

1

x = 0

2

x = -1

3

x = 1 

4

x = -7

5

Multiple Choice

Question image

Describe the behavior of the graph of the function at its zero x = 1.

 f(x)=x(x+4)(x1)4f\left(x\right)=x\left(x+4\right)\left(x-1\right)^4  

1

The multiplicity of x =1 is 4, so the function crosses the x‑axis.

2

The multiplicity of x =1 is 4, so the graph has a turning point on the x-axis.

6

Multiple Choice

Question image

Describe the behavior of the graph of the function at its zero x = 1.

 f(x)=(x2+9)(x1)5(x+2)2f\left(x\right)=\left(x^2+9\right)\left(x-1\right)^5\left(x+2\right)^2  

1

The multiplicity of x =1 is 5, so the function crosses the x‑axis.

2

The multiplicity of x =1 is 5, so the graph has a turning point on the x-axis.

7

Multiple Choice

Question image

This function has 3 zeros in the set of complex numbers, but it only looks like it has a zero at x = 2. How can this be?

1

x = 2 is the real solution, there are 2 other complex solutions.

2

The first option.

3

The second option.

4

The third option.

8

Multiple Choice

Question image

Use the attachment to help you.

According to the Rational Root Theorem, which of the following is NOT a possible solution to the polynomial?

 P(x)=4x37x+5P\left(x\right)=4x^3-7x+5  

1

 55  

2

 12-\frac{1}{2}  

3

 23\frac{2}{3}  

4

 54\frac{5}{4}  

9

Multiple Choice

Question image

Use the attachment to help you.

According to the Rational Root Theorem, which of the following is NOT a possible solution to the polynomial?

 P(x)=7x4x2+5x6P\left(x\right)=7x^4-x^2+5x-6  

1

 66  

2

 17-\frac{1}{7}  

3

 27\frac{2}{7}  

4

 54\frac{5}{4}  

10

Multiple Choice

Question image

According to the Fundamental Theorem of Algebra, how many roots exist for the following polynomial?


 P(x)=5x76x3+17x219P\left(x\right)=5x^7-6x^3+17x^2-19  

1

5

2

7

3

19

4

None

11

Slide image

Complete your exit ticket and you are finished for the day!

Zeros of Polynomials and Theorems About Polynomials

Let's review 3-5 and 3-6 for our test next week!

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