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Unit: Volume Review Part 1

Unit: Volume Review Part 1

Assessment

Presentation

Mathematics

8th Grade

Easy

CCSS
HSG.GMD.A.3, HSG.C.B.5, 7.G.B.6

+1

Standards-aligned

Created by

Christopher Mullen

Used 3+ times

FREE Resource

6 Slides • 22 Questions

1

Unit: Volume Review Part 1

Cylinders, Cone, Pyramids, and Spheres

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2

Cylinder Formula

  • Volume - V=Bh or V =  πr2×h\pi r^2\times h  

  • B = Area of base, h = height

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3

Multiple Choice

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Find the volume to the nearest hundredth using 3.14 instead of Pi.
1
418.00 cm3
2
139.33 cm3
3
130.62 cm3
4
1671.98 cm3

4

Multiple Choice

Question image

What is the exact volume of the cylinder?

1

72π m3

2

144π m3

3

150π m3

4

452.16m3

5

Multiple Choice

Find the Height of the cylinder when given the following: Volume = 9375π , Radius = 25.

1

15

2

375

3

35

4

18

6

Cone Formula's

  • V =  13Bh\ \frac{1}{3}Bh  or  V=13πr2×hV=\frac{1}{3}\pi r^2\times h  

  •  SA = Surface Area     R = Radius     l = slant height

     SA = πr2 + πrlSA\ =\ \pi r^2\ +\ \pi rl  

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7

Multiple Choice

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Find the volume to the nearest hundredth using 3.14 instead of Pi.  r = 2ft  h = 3ft

 V=\frac{1}{3}\pi r^2\times h  

1

12.56 ft3

2

37.68 ft3

3

18.84 ft3

4

6.28 ft3

8

Multiple Choice

Question image

What is the Height of a cone with a volume of 432π and a base area of 16π ?


 V = 13BhV\ =\ \frac{1}{3}Bh  

1

27

2

54

3

81

4

9

9

Multiple Choice

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What is the area of the base of a cone with a volume of 96⫪ in^3 and a height of 24 in.?
 V=\ \frac{1}{3}Bh  

1

2

32π

3

4

12π

10

Multiple Choice

Question image

Find the total surface area of the cone. Round to the nearest tenth.

 SA=πr2+πrl  

  

1

37.7 m²

2

50.3 m²

3

75.4 m²

4

25.1 m²

11

Multiple Choice

Question image

Find the total surface area of the cone. Don't forget to divide the diameter by 2 to find the radius. Round to the nearest tenth.

 SA=πr2+πrl  

1

1158.5 sq. m

2

1287.2 sq. m

3

1007.9 sq. m

4

1462 sq. m

12

Pyramid Formula's

  •  V=13BhV=\frac{1}{3}Bh                                     B = area of the base , h = height

  •  SA=B +LA SA=B\ +LA\                          B= area of base LA = Lateral face area, 4 x the area of a triangle  (12bh)\left(\frac{1}{2}bh\right)  

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13

Multiple Choice

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Calculate the volume of the square pyramid in the picture. Round to the nearest whole number if necessary.
height = 4 m and the square base edge length is 4 m.


 V=13BhV=\frac{1}{3}Bh  

1

21 m3

2

64 m3

3

32 m3

4

11 m3

14

Multiple Choice

Question image

Calculate the volume of the pyramid in the picture. Round to the nearest whole number if necessary.


 V =13BhV\ =\frac{1}{3}Bh  

1

216 yd3

2

108 yd3

3

72 yd3

4

36 yd3

15

Multiple Choice

Question image

The volume of a pyramid is 120 cubic inches, the area of base is 50 squared inches, What is the height?

 V = 13BhV\ =\ \frac{1}{3}Bh  

1

1.3 in

2

7.2 in

3

2 in

4

2.4 in

16

Multiple Choice

Question image

What is the total surface area of the pyramid in square centimeters?


 SA=B +LASA=B\ +LA  

1

45.5 cm^2

2

60.2 cm2cm^2

3

37.45 cm^2

4

105.7 cm^2

17

Multiple Choice

Question image

Find the surface area of the square pyramid in the picture.

 SA = B+LASA\ =\ B+LA  

1

15m2

2

16m2

3

18m2

4

20m2

18

Sphere Formula's

  •  V= 43πr3V=\ \frac{4}{3}\pi r^3  

  •  SA = 4πr2SA\ =\ 4\pi r^2  

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19

Multiple Choice

Question image

Find the volume of the sphere. Use 3.14 for π\pi .  Round to nearest tenth.


 V=43πr3V=\frac{4}{3}\pi r^3  

1

78.5 m3m^3  

2

392.5 m3m^3  

3

523.3  m3m^3  

4

62.8  m3m^3  

20

Multiple Choice

Question image

Find the Volume of the Sphere, use 3.14 instead of  π\pi  : Diameter = 12 ft

 V=\frac{4}{3}\pi r^3  

1

904.32 ft^3  

2

7,234.56  ft^3  

3

150.72  ft^3  

4

602.88 ft3ft^3  

21

Multiple Choice

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Find the surface area of a sphere with a diameter of 10 cm, leave in terms of π.

1

40π   cm^2  

2

400π   cm^2  

3

100π  cm2cm^2  

4

200π   cm^2  

22

Multiple Choice

Question image

What is the surface area of the sphere with a radius 5cm. Leave in terms of π.


SA=4πr²

1

40π cm²

2

100π cm²

3

400π cm²

4

625π cm²

23

Multiple Choice

Find the radius of a sphere with a surface area of  484π cm2484\pi\ cm^2  .


 SA = 4πr2SA\ =\ 4\pi r^2  

1

r = 13cm

2

r=11cm

3

r =9cm

4

r = 14 cm

24

Circle formula's

  •  C = 2πr or C = πdC\ =\ 2\pi r\ or\ C\ =\ \pi d  

  •  A=πr2A=\pi r^2  

  •  Arc length = n°360×2πr Arc\ length\ =\ \frac{n\degree}{360}\times2\pi r\   

  •  Sector area = n°360 × πr2Sector\ area\ =\ \frac{n\degree}{360}\ \times\ \pi r^2  

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25

Multiple Choice

Question image

Find the arc length. Leave your answer in terms of π.

1

7/4π

2

7/2π

3

1/8π

4

45π

26

Multiple Choice

Question image

What is the area of the shaded sector?

1

339.12 in2

2

113.04 in2

3

339.29 in2

4

None of the above

27

Multiple Choice

Question image

In circle O, the radius is 4, and the arc length is 4.2 feet. Find the measure of the angle to the nearest degree.

1

90 °\degree

2

60 \degree

3

55 \degree

4

113 \degree

28

Multiple Choice

Question image

An arc of a circle has a length of  2.5π2.5\pi cm, and a radius of 9 cm. What is the sector area. 

1

 59π cm2\frac{5}{9}\pi\ cm^2  

2

 274π cm2\frac{27}{4}\pi\ cm^2  

3

 454π cm2\frac{45}{4}\pi\ cm^2  

4

 173π cm2\frac{17}{3}\pi\ cm^2  

Unit: Volume Review Part 1

Cylinders, Cone, Pyramids, and Spheres

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