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Turunan Trigonometri

Turunan Trigonometri

Assessment

Presentation

Mathematics

12th Grade

Medium

Created by

Ari Sujati

Used 24+ times

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11 Slides • 9 Questions

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Turunan Trigonometri

by Ari Sujati

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Multiple Choice

Diketahui fungsi trigonometri f(x)=sinxcos xf\left(x\right)=\sin x\cos\ x , maka  f(x)f'\left(x\right)  adalah...

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cos xsin x\cos\ x\sin\ x  

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2sinxcosx-2\sin x\cos x  

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sinxcosx\sin x\cos x  

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1

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cos2xsin2x\cos^2x-\sin^2x  

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Multiple Choice

Diketahui fungsi turunan trigonometri f(x)=2sin3xcos4xf\left(x\right)=2\sin3x\cos4x  , maka  f(0)f'\left(0\right)  adalah...

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12-\frac{1}{2}  

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12\frac{1}{2}  

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122\frac{1}{2}\sqrt{2}  

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123\frac{1}{2}\sqrt{3}  

14

Multiple Choice

Diketahui fungsi turunan trigonometri f(x)=2sinx3cos x f\left(x\right)=\frac{2\sin x}{3\cos\ x}\  maka  f(x)f'\left(x\right)  adalah...

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12cos2x\frac{1}{2\cos^2x}  

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23cos2x\frac{2}{3\cos^2x}  

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32cos2x\frac{\sqrt{3}}{2\cos^2x}  

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1cos2x\frac{1}{\cos^2x}  

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cos2x\cos^2x  

15

Multiple Choice

Diketahui fungsi turunan trigonometri f(x)=4cos2xsin 4xf\left(x\right)=\frac{4\cos2x}{\sin\ 4x}  , maka  f(π4)f'\left(\frac{\pi}{4}\right)  adalah...

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123-\frac{1}{2}\sqrt{3}  

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3-\sqrt{3}  

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00  

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1-1  

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123\frac{1}{2}\sqrt{3}  

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Multiple Choice

Diketahui fungsi turunan trigonometri f(x)=sin(2xπ2)cos(3xπ)f\left(x\right)=\frac{\sin\left(2x-\frac{\pi}{2}\right)}{\cos\left(3x-\pi\right)}  , maka  f(π3)f'\left(\frac{\pi}{3}\right)  adalah...

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3-\sqrt{3}  

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123-\frac{1}{2}\sqrt{3}  

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00  

4

123\frac{1}{2}\sqrt{3}  

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3\sqrt{3}  

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Multiple Choice

Diketahui fungsi turunan trigonometri f(x)=sin3xf\left(x\right)=\sin^3x , maka  f(x)f'\left(x\right)  adalah... 

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cos3x\cos^3x  

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3sinxcosx3\sin x\cos x  

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undefined 

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sin2xcosx\sin^2x\cos x  

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sinxcosx\sin x\cos x  

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Multiple Choice

Diketahui fungsi trigonometri f(x)=2cos5(2xπ)f\left(x\right)=2\cos^5\left(2x-\pi\right) , maka  f(23π)f'\left(\frac{2}{3}\pi\right)  adalah...

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583-\frac{5}{8}\sqrt{3}  

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98-\frac{9}{8}  

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00  

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98\frac{9}{8}  

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458\frac{45}{8}  

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Multiple Choice

Diketahui fungsi trigonometri f(x)=sin4xf\left(x\right)=\sin4x  , maka  f(x)f''\left(x\right)  adalah...

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4cos4x4\cos4x  

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4sin4x4\sin4x  

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16sin4x-16\sin4x  

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16cos4x-16\cos4x  

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8sin4x8\sin4x  

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Multiple Choice

Diketahui fungsi trigonometri f(x)=2sin4x+3cosxf\left(x\right)=2\sin4x+3\cos x , maka  f(π4)f''\left(\frac{\pi}{4}\right)  adalah... 

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122\frac{1}{2}\sqrt{2}  

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322\frac{3}{2}\sqrt{2}  

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00  

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322-\frac{3}{2}\sqrt{2}  

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122-\frac{1}{2}\sqrt{2}  

Turunan Trigonometri

by Ari Sujati

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