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Trigo Differentiation Basics

Trigo Differentiation Basics

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•

Mathematics

•

12th Grade

•

Practice Problem

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Created by

Thavarajah Selvarajah

Used 15+ times

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8 Slides • 34 Questions

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Trigo Differentiation Basics

by Thavarajah Selvarajah

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media
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​RULE 1

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​RULE 2

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​LEVEL 1

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DIFFERENTIATION USING RULE 1 AND RULE 2

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Multiple Choice

Given y=tan⁡xy=\tan x  , dydx=?\frac{\text{d}y}{\text{d}x}=?  

1

sec⁡2x\sec^2x  

2

sin⁡2x\sin^2x  

3

sec⁡2w\sec^2w  

4

1

8

Multiple Choice

ddw(tan⁡w)=?\frac{\text{d}}{\text{d}w}\left(\tan w\right)=?  

1

sin⁡2w\sin^2w  

2

sec⁡2x\sec^2x  

3

sec⁡2w\sec^2w  

4

1

9

Multiple Choice

Given  y=−cosec⁡xy=-\operatorname{cosec}x  . Find  dydx\frac{dy}{dx}  

1

cosec⁡x cot⁡ x\operatorname{cosec}x\ \cot\ x  

2

−cosec⁡xcot⁡x-\operatorname{cosec}x\cot x  

3

sec⁡2w\sec^2w  

4

−1sin⁡x-\frac{1}{\sin x}  

10

Multiple Choice

Given  y=−34cosec⁡xy=-\frac{3}{4}\operatorname{cosec}x  . Find  dydx\frac{dy}{dx}  

1

−cosec⁡x cot⁡x-\operatorname{cosec}x\ \cot x  

2

cosec⁡xcot⁡x\operatorname{cosec}x\cot x  

3

34cosec⁡xcot⁡x\frac{3}{4}\operatorname{cosec}x\cot x  

4

−34cosec⁡xcot⁡x-\frac{3}{4}\operatorname{cosec}x\cot x

11

Multiple Choice

Given y=45cot⁡xy=\frac{4}{5}\cot x  . What is dydx?\frac{dy}{dx}?  

1

−45cosec⁡2x-\frac{4}{5}\operatorname{cosec}^2x  

2

45cosec⁡2x\frac{4}{5}\operatorname{cosec}^2x  

3

cosec⁡2x\operatorname{cosec}^2x  

4

−cosec⁡2x-\operatorname{cosec}^2x  

12

Multiple Choice

Given y=−45cot⁡xy=-\frac{4}{5}\cot x  . What is dydx?\frac{dy}{dx}?  

1

−45cosec⁡2x-\frac{4}{5}\operatorname{cosec}^2x  

2

45cosec⁡2x\frac{4}{5}\operatorname{cosec}^2x  

3

cosec⁡2x\operatorname{cosec}^2x  

4

−cosec⁡2x-\operatorname{cosec}^2x  

13

Multiple Choice

y=cos⁡x−sin⁡x, dydx=?y=\cos x-\sin x,\ \frac{\text{d}y}{\text{d}x}=?  

1

sin⁡x−cos⁡x\sin x-\cos x

2

−sin⁡x−cos⁡x-\sin x-\cos x  

3

sec⁡2w\sec^2w  

4

sin⁡x+cos⁡x\sin x+\cos x

14

Multiple Choice

Given  y=−sin⁡x+cos⁡xy=-\sin x+\cos x  . What is  dydx=?\frac{dy}{dx}=?  

1

−cos⁡x−sin⁡x-\cos x-\sin x  

2

cos⁡x−sin⁡x\cos x-\sin x

3

−cos⁡x+sin⁡x-\cos x+\sin x

4

cos⁡x+sin⁡x\cos x+\sin x

15

Multiple Choice

Given  y=−sin⁡x−cos⁡xy=-\sin x-\cos x  . What is  dydx=?\frac{dy}{dx}=?  

1

−cos⁡x−sin⁡x-\cos x-\sin x  

2

cos⁡x−sin⁡x\cos x-\sin x

3

−cos⁡x+sin⁡x-\cos x+\sin x

4

cos⁡x+sin⁡x\cos x+\sin x

16

Multiple Choice

y=2sin⁡x−3cot⁡xy=2\sin x-3\cot x  

           ddx(y)=ddx(2sin⁡x)−ddx(3cot⁡x)\frac{\text{d}}{\text{d}x}\left(y\right)=\frac{\text{d}}{\text{d}x}\left(2\sin x\right)-\frac{\text{d}}{\text{d}x}\left(3\cot x\right)  

p       =   q+rp\ \ \ \ \ \ \ =\ \ \ q+r              

What is  p?p?  

1

11  

2

dydx\frac{dy}{dx}  

3

yy  

4

dxdy\frac{\text{d}x}{\text{d}y}  

17

Multiple Choice

y=2sin⁡x−3cot⁡xy=2\sin x-3\cot x  

           ddx(y)=ddx(2sin⁡x)−ddx(3cot⁡x)\frac{\text{d}}{\text{d}x}\left(y\right)=\frac{\text{d}}{\text{d}x}\left(2\sin x\right)-\frac{\text{d}}{\text{d}x}\left(3\cot x\right)  

p       =   q+rp\ \ \ \ \ \ \ =\ \ \ q+r                         

What is  q?q?  

1

2sin⁡x2\sin x  

2

cos⁡x\cos x  

3

−2cos⁡x-2\cos x  

4

2cos x\text{2cos x}  

18

Multiple Choice

y=2sin⁡x−3cot⁡xy=2\sin x-3\cot x  

           ddx(y)=ddx(2sin⁡x)−ddx(3cot⁡x)\frac{\text{d}}{\text{d}x}\left(y\right)=\frac{\text{d}}{\text{d}x}\left(2\sin x\right)-\frac{\text{d}}{\text{d}x}\left(3\cot x\right)  

p       =   q+rp\ \ \ \ \ \ \ =\ \ \ q+r                         

What is  r?r?  

1

−3cosec⁡2x-3\operatorname{cosec}^2x   

2

3cosec⁡2x3\operatorname{cosec}^2x  

3

cosec⁡2x\operatorname{cosec}^2x  

4

−cosec⁡2x-\operatorname{cosec}^2x  

19

Multiple Choice

Given  y=−3cos⁡x−4tan⁡xy=-3\cos x-4\tan x  . What is  dydx=?\frac{dy}{dx}=?  

1

−3sin⁡x−4sec⁡2x-3\sin x-4\sec^2x  

2

3sin⁡x−4sec⁡2x3\sin x-4\sec^2x

3

−sin⁡x−sec⁡2x-\sin x-\sec^2x

4

sin⁡x−sec⁡2x\sin x-\sec^2x

20

Multiple Choice

Given y=−54cot⁡x−3sec⁡xy=-\frac{5}{4}\cot x-3\sec x  . What is ddx(−54cot⁡x−3sec⁡x)\frac{d}{dx}\left(-\frac{5}{4}\cot x-3\sec x\right)  

1

−54cosec⁡2x−3sec⁡xtan⁡x-\frac{5}{4}\operatorname{cosec}^2x-3\sec x\tan x  

2

54cosec⁡2x−3sec⁡xtan⁡x\frac{5}{4}\operatorname{cosec}^2x-3\sec x\tan x

3

−54cosec⁡2x+3sec⁡xtan⁡x-\frac{5}{4}\operatorname{cosec}^2x+3\sec x\tan x

4

54cosec⁡2x+3sec⁡xtan⁡x\frac{5}{4}\operatorname{cosec}^2x+3\sec x\tan x

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​LEVEL 2

​Combining trigo with weapons of Differentiation

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media

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Multiple Choice

y=cos⁡xsin⁡xy=\cos x\sin x  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Direct

4

Chain Rule

24

Multiple Choice

y=1sin⁡xy=\frac{1}{\sin x}  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Power Rule

4

Direct

25

Multiple Choice

y=cosec⁡xsin⁡xy=\operatorname{cosec}x\sin x  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Power Rule

4

Direct

26

Multiple Choice

y=1sin⁡xy=\frac{1}{\sin x}  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Power Rule

4

Direct

27

Multiple Choice

y=sec⁡xy=\sec x  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Power Rule

4

Direct

28

Multiple Choice

y=cos⁡ x sin⁡xy=\frac{\cos\ x\ }{\sin x}  ,                      

dydx=(sin⁡x)p−(cos⁡x)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\sin x\right)p-\left(\cos x\right)q}{r}  .

What is  p?p?  

1

−cos⁡x-\cos x  

2

cos⁡x\cos x  

3

−sin⁡x-\sin x  

4

sin⁡x\sin x  

29

Multiple Choice

y=cos⁡ x sin⁡xy=\frac{\cos\ x\ }{\sin x}  ,

dydx=(sin⁡x)p−(cos⁡x)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\sin x\right)p-\left(\cos x\right)q}{r}  .

What is  q?q?  

1

−cos⁡x-\cos x  

2

cos⁡x\cos x  

3

−sin⁡x-\sin x  

4

sin⁡x\sin x  

30

Multiple Choice

y=cos⁡ x sin⁡xy=\frac{\cos\ x\ }{\sin x}  ,                      

dydx=(sin⁡x)p−(cos⁡x)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\sin x\right)p-\left(\cos x\right)q}{r}  .

What is  r?r?  

1

cos⁡2x\cos^2x  

2

cos⁡x\cos x  

3

sin⁡x\sin x  

4

sin⁡2x\sin^2x  

31

Multiple Choice

y=sin⁡ x cos⁡xy=\frac{\sin\ x\ }{\cos x}  ,

dydx=(cos⁡x)p−(sin⁡x)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\cos x\right)p-\left(\sin x\right)q}{r}  .

What is  p?p?  

1

−cos⁡x-\cos x  

2

cos⁡x\cos x  

3

−sin⁡x-\sin x  

4

sin⁡x\sin x  

32

Multiple Choice

y=sin⁡ x cos⁡xy=\frac{\sin\ x\ }{\cos x}  ,                       

dydx=(cos⁡x)p−(sin⁡x)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\cos x\right)p-\left(\sin x\right)q}{r}  .

What is  q?q?  

1

−cos⁡x-\cos x  

2

cos⁡x\cos x  

3

−sin⁡x-\sin x  

4

sin⁡x\sin x  

33

Multiple Choice

y=sin⁡ x cos⁡xy=\frac{\sin\ x\ }{\cos x}  ,

dydx=(cos⁡x)p−(sin⁡x)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\cos x\right)p-\left(\sin x\right)q}{r}  .

What is  r?r?  

1

cos⁡2x\cos^2x  

2

cos⁡x\cos x  

3

sin⁡2x\sin^2x  

4

sin⁡x\sin x  

34

Multiple Choice

y=(1cos⁡x)y=\left(\frac{1}{\cos x}\right)  

ddx(y)=(cos⁡x)−1\frac{\text{d}}{\text{d}x}\left(y\right)=\left(\cos x\right)^{-1}  

p=r(cos⁡x)q(s)p=r\left(\cos x\right)^q\left(s\right)  

What is r?r?  

1

1

2

-1

35

Multiple Choice

y=1cos⁡xy=\frac{1}{\cos x}  

ddx(y)=(cos⁡x)−1\frac{\text{d}}{\text{d}x}\left(y\right)=\left(\cos x\right)^{-1}  

p=r(cos⁡x)q(s)p=r\left(\cos x\right)^q\left(s\right)  

What is q?q?  

1

0

2

-1

3

-2

4

2

36

Multiple Choice

y=1cos⁡xy=\frac{1}{\cos x}  

ddx(y)=(cos⁡x)−1\frac{\text{d}}{\text{d}x}\left(y\right)=\left(\cos x\right)^{-1}  

p=r(cos⁡x)q(s)p=r\left(\cos x\right)^q\left(s\right)  

What is s?s?  

1

cos⁡x\cos x  

2

sin⁡x\sin x  

3

−sin⁡x-\sin x  

4

−cos⁡x-\cos x  

37

Multiple Select

Given  y=1cos⁡xy=\frac{1}{\cos x}  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

tan⁡xsec⁡x\tan x\sec x  

2

sin⁡xcos⁡2x\frac{\sin x}{\cos^2x}  

3

sin⁡xsec⁡2x\sin x\sec^2x  

4

1cos⁡2x\frac{1}{\cos^2x}  

38

Multiple Choice

Given  y=2cosec⁡xsin⁡xy=2\operatorname{cosec}x\sin x  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

−2cosec⁡xcot⁡x-2\operatorname{cosec}x\cot x  

2

22  

3

00  

4

2cosec⁡xcos⁡x2\operatorname{cosec}x\cos x  

39

Multiple Choice

Given  y=sin⁡xtan⁡xy=\sin x\tan x  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

sin⁡x+sin⁡xsec⁡2x\sin x+\sin x\sec^2x  

2

−sin⁡x+sin⁡xsec⁡2x-\sin x+\sin x\sec^2x  

3

cos⁡xsec⁡2x\cos x\sec^2x  

4

sin⁡x+sin⁡xsec⁡x\sin x+\sin x\sec^{ }x

40

Multiple Choice

Given  y=xsin⁡x y=x\sin x\  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

cos⁡x\cos x  

2

xcos⁡x+sin⁡xx\cos x+\sin x  

3

sin⁡x−xcos⁡x\sin x-x\cos x  

4

xsin⁡x+cos⁡xx\sin x+\cos x  

41

Multiple Choice

Given  y=cos⁡x1−sin⁡xy=\frac{\cos x}{1-\sin x}  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

11−sin⁡x\frac{1}{1-\sin x}  

2

1−sin⁡2x+cos⁡2x(1−sin⁡x)2\frac{1-\sin^2x+\cos^2x}{\left(1-\sin x\right)^2}  

3

cos⁡x(1−sin⁡x)2\frac{\cos x}{\left(1-\sin x\right)^2}  

4

1−sin⁡x1-\sin x  

42

Multiple Choice

Given  y=2cos⁡x+3cosec⁡xy=2\cos x+3\operatorname{cosec}x  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

2sin⁡x+3cosec⁡xcot⁡x2\sin x+3\operatorname{cosec}x\cot x   

2

−2sin⁡x+3cot⁡xcosec⁡x-2\sin x+3\cot x\operatorname{cosec}x  

3

−2sin⁡x−3cosec⁡xcot⁡x-2\sin x-3\operatorname{cosec}x\cot x

4

−sin⁡x−cosec⁡xcot⁡x-\sin x-\operatorname{cosec}x\cot x

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Trigo Differentiation Basics

by Thavarajah Selvarajah

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