Search Header Logo
Trigo Differentiation Basics

Trigo Differentiation Basics

Assessment

Presentation

Mathematics

12th Grade

Practice Problem

Medium

Created by

Thavarajah Selvarajah

Used 13+ times

FREE Resource

8 Slides • 34 Questions

1

Trigo Differentiation Basics

by Thavarajah Selvarajah

2

media
media

3

RULE 1

4

RULE 2

5

media

6

LEVEL 1

DIFFERENTIATION USING RULE 1 AND RULE 2

7

Multiple Choice

Given y=tanxy=\tan x  , dydx=?\frac{\text{d}y}{\text{d}x}=?  

1

sec2x\sec^2x  

2

sin2x\sin^2x  

3

sec2w\sec^2w  

4

1

8

Multiple Choice

ddw(tanw)=?\frac{\text{d}}{\text{d}w}\left(\tan w\right)=?  

1

sin2w\sin^2w  

2

sec2x\sec^2x  

3

sec2w\sec^2w  

4

1

9

Multiple Choice

Given  y=cosecxy=-\operatorname{cosec}x  . Find  dydx\frac{dy}{dx}  

1

cosecx cot x\operatorname{cosec}x\ \cot\ x  

2

cosecxcotx-\operatorname{cosec}x\cot x  

3

sec2w\sec^2w  

4

1sinx-\frac{1}{\sin x}  

10

Multiple Choice

Given  y=34cosecxy=-\frac{3}{4}\operatorname{cosec}x  . Find  dydx\frac{dy}{dx}  

1

cosecx cotx-\operatorname{cosec}x\ \cot x  

2

cosecxcotx\operatorname{cosec}x\cot x  

3

34cosecxcotx\frac{3}{4}\operatorname{cosec}x\cot x  

4

34cosecxcotx-\frac{3}{4}\operatorname{cosec}x\cot x

11

Multiple Choice

Given y=45cotxy=\frac{4}{5}\cot x  . What is dydx?\frac{dy}{dx}?  

1

45cosec2x-\frac{4}{5}\operatorname{cosec}^2x  

2

45cosec2x\frac{4}{5}\operatorname{cosec}^2x  

3

cosec2x\operatorname{cosec}^2x  

4

cosec2x-\operatorname{cosec}^2x  

12

Multiple Choice

Given y=45cotxy=-\frac{4}{5}\cot x  . What is dydx?\frac{dy}{dx}?  

1

45cosec2x-\frac{4}{5}\operatorname{cosec}^2x  

2

45cosec2x\frac{4}{5}\operatorname{cosec}^2x  

3

cosec2x\operatorname{cosec}^2x  

4

cosec2x-\operatorname{cosec}^2x  

13

Multiple Choice

y=cosxsinx, dydx=?y=\cos x-\sin x,\ \frac{\text{d}y}{\text{d}x}=?  

1

sinxcosx\sin x-\cos x

2

sinxcosx-\sin x-\cos x  

3

sec2w\sec^2w  

4

sinx+cosx\sin x+\cos x

14

Multiple Choice

Given  y=sinx+cosxy=-\sin x+\cos x  . What is  dydx=?\frac{dy}{dx}=?  

1

cosxsinx-\cos x-\sin x  

2

cosxsinx\cos x-\sin x

3

cosx+sinx-\cos x+\sin x

4

cosx+sinx\cos x+\sin x

15

Multiple Choice

Given  y=sinxcosxy=-\sin x-\cos x  . What is  dydx=?\frac{dy}{dx}=?  

1

cosxsinx-\cos x-\sin x  

2

cosxsinx\cos x-\sin x

3

cosx+sinx-\cos x+\sin x

4

cosx+sinx\cos x+\sin x

16

Multiple Choice

y=2sinx3cotxy=2\sin x-3\cot x  

           ddx(y)=ddx(2sinx)ddx(3cotx)\frac{\text{d}}{\text{d}x}\left(y\right)=\frac{\text{d}}{\text{d}x}\left(2\sin x\right)-\frac{\text{d}}{\text{d}x}\left(3\cot x\right)  

p       =   q+rp\ \ \ \ \ \ \ =\ \ \ q+r              

What is  p?p?  

1

11  

2

dydx\frac{dy}{dx}  

3

yy  

4

dxdy\frac{\text{d}x}{\text{d}y}  

17

Multiple Choice

y=2sinx3cotxy=2\sin x-3\cot x  

           ddx(y)=ddx(2sinx)ddx(3cotx)\frac{\text{d}}{\text{d}x}\left(y\right)=\frac{\text{d}}{\text{d}x}\left(2\sin x\right)-\frac{\text{d}}{\text{d}x}\left(3\cot x\right)  

p       =   q+rp\ \ \ \ \ \ \ =\ \ \ q+r                         

What is  q?q?  

1

2sinx2\sin x  

2

cosx\cos x  

3

2cosx-2\cos x  

4

2cos x\text{2cos x}  

18

Multiple Choice

y=2sinx3cotxy=2\sin x-3\cot x  

           ddx(y)=ddx(2sinx)ddx(3cotx)\frac{\text{d}}{\text{d}x}\left(y\right)=\frac{\text{d}}{\text{d}x}\left(2\sin x\right)-\frac{\text{d}}{\text{d}x}\left(3\cot x\right)  

p       =   q+rp\ \ \ \ \ \ \ =\ \ \ q+r                         

What is  r?r?  

1

3cosec2x-3\operatorname{cosec}^2x   

2

3cosec2x3\operatorname{cosec}^2x  

3

cosec2x\operatorname{cosec}^2x  

4

cosec2x-\operatorname{cosec}^2x  

19

Multiple Choice

Given  y=3cosx4tanxy=-3\cos x-4\tan x  . What is  dydx=?\frac{dy}{dx}=?  

1

3sinx4sec2x-3\sin x-4\sec^2x  

2

3sinx4sec2x3\sin x-4\sec^2x

3

sinxsec2x-\sin x-\sec^2x

4

sinxsec2x\sin x-\sec^2x

20

Multiple Choice

Given y=54cotx3secxy=-\frac{5}{4}\cot x-3\sec x  . What is ddx(54cotx3secx)\frac{d}{dx}\left(-\frac{5}{4}\cot x-3\sec x\right)  

1

54cosec2x3secxtanx-\frac{5}{4}\operatorname{cosec}^2x-3\sec x\tan x  

2

54cosec2x3secxtanx\frac{5}{4}\operatorname{cosec}^2x-3\sec x\tan x

3

54cosec2x+3secxtanx-\frac{5}{4}\operatorname{cosec}^2x+3\sec x\tan x

4

54cosec2x+3secxtanx\frac{5}{4}\operatorname{cosec}^2x+3\sec x\tan x

21

​LEVEL 2

Combining trigo with weapons of Differentiation

22

media

23

Multiple Choice

y=cosxsinxy=\cos x\sin x  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Direct

4

Chain Rule

24

Multiple Choice

y=1sinxy=\frac{1}{\sin x}  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Power Rule

4

Direct

25

Multiple Choice

y=cosecxsinxy=\operatorname{cosec}x\sin x  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Power Rule

4

Direct

26

Multiple Choice

y=1sinxy=\frac{1}{\sin x}  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Power Rule

4

Direct

27

Multiple Choice

y=secxy=\sec x  .

What is the SUITABLE WEAPON we use to find dydx\frac{\text{d}y}{\text{d}x}  

1

Product rule

2

Quotient rule

3

Power Rule

4

Direct

28

Multiple Choice

y=cos x sinxy=\frac{\cos\ x\ }{\sin x}  ,                      

dydx=(sinx)p(cosx)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\sin x\right)p-\left(\cos x\right)q}{r}  .

What is  p?p?  

1

cosx-\cos x  

2

cosx\cos x  

3

sinx-\sin x  

4

sinx\sin x  

29

Multiple Choice

y=cos x sinxy=\frac{\cos\ x\ }{\sin x}  ,

dydx=(sinx)p(cosx)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\sin x\right)p-\left(\cos x\right)q}{r}  .

What is  q?q?  

1

cosx-\cos x  

2

cosx\cos x  

3

sinx-\sin x  

4

sinx\sin x  

30

Multiple Choice

y=cos x sinxy=\frac{\cos\ x\ }{\sin x}  ,                      

dydx=(sinx)p(cosx)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\sin x\right)p-\left(\cos x\right)q}{r}  .

What is  r?r?  

1

cos2x\cos^2x  

2

cosx\cos x  

3

sinx\sin x  

4

sin2x\sin^2x  

31

Multiple Choice

y=sin x cosxy=\frac{\sin\ x\ }{\cos x}  ,

dydx=(cosx)p(sinx)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\cos x\right)p-\left(\sin x\right)q}{r}  .

What is  p?p?  

1

cosx-\cos x  

2

cosx\cos x  

3

sinx-\sin x  

4

sinx\sin x  

32

Multiple Choice

y=sin x cosxy=\frac{\sin\ x\ }{\cos x}  ,                       

dydx=(cosx)p(sinx)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\cos x\right)p-\left(\sin x\right)q}{r}  .

What is  q?q?  

1

cosx-\cos x  

2

cosx\cos x  

3

sinx-\sin x  

4

sinx\sin x  

33

Multiple Choice

y=sin x cosxy=\frac{\sin\ x\ }{\cos x}  ,

dydx=(cosx)p(sinx)qr\frac{\text{d}y}{\text{d}x}=\frac{\left(\cos x\right)p-\left(\sin x\right)q}{r}  .

What is  r?r?  

1

cos2x\cos^2x  

2

cosx\cos x  

3

sin2x\sin^2x  

4

sinx\sin x  

34

Multiple Choice

y=(1cosx)y=\left(\frac{1}{\cos x}\right)  

ddx(y)=(cosx)1\frac{\text{d}}{\text{d}x}\left(y\right)=\left(\cos x\right)^{-1}  

p=r(cosx)q(s)p=r\left(\cos x\right)^q\left(s\right)  

What is r?r?  

1

1

2

-1

35

Multiple Choice

y=1cosxy=\frac{1}{\cos x}  

ddx(y)=(cosx)1\frac{\text{d}}{\text{d}x}\left(y\right)=\left(\cos x\right)^{-1}  

p=r(cosx)q(s)p=r\left(\cos x\right)^q\left(s\right)  

What is q?q?  

1

0

2

-1

3

-2

4

2

36

Multiple Choice

y=1cosxy=\frac{1}{\cos x}  

ddx(y)=(cosx)1\frac{\text{d}}{\text{d}x}\left(y\right)=\left(\cos x\right)^{-1}  

p=r(cosx)q(s)p=r\left(\cos x\right)^q\left(s\right)  

What is s?s?  

1

cosx\cos x  

2

sinx\sin x  

3

sinx-\sin x  

4

cosx-\cos x  

37

Multiple Select

Given  y=1cosxy=\frac{1}{\cos x}  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

tanxsecx\tan x\sec x  

2

sinxcos2x\frac{\sin x}{\cos^2x}  

3

sinxsec2x\sin x\sec^2x  

4

1cos2x\frac{1}{\cos^2x}  

38

Multiple Choice

Given  y=2cosecxsinxy=2\operatorname{cosec}x\sin x  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

2cosecxcotx-2\operatorname{cosec}x\cot x  

2

22  

3

00  

4

2cosecxcosx2\operatorname{cosec}x\cos x  

39

Multiple Choice

Given  y=sinxtanxy=\sin x\tan x  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

sinx+sinxsec2x\sin x+\sin x\sec^2x  

2

sinx+sinxsec2x-\sin x+\sin x\sec^2x  

3

cosxsec2x\cos x\sec^2x  

4

sinx+sinxsecx\sin x+\sin x\sec^{ }x

40

Multiple Choice

Given  y=xsinx y=x\sin x\  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

cosx\cos x  

2

xcosx+sinxx\cos x+\sin x  

3

sinxxcosx\sin x-x\cos x  

4

xsinx+cosxx\sin x+\cos x  

41

Multiple Choice

Given  y=cosx1sinxy=\frac{\cos x}{1-\sin x}  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

11sinx\frac{1}{1-\sin x}  

2

1sin2x+cos2x(1sinx)2\frac{1-\sin^2x+\cos^2x}{\left(1-\sin x\right)^2}  

3

cosx(1sinx)2\frac{\cos x}{\left(1-\sin x\right)^2}  

4

1sinx1-\sin x  

42

Multiple Choice

Given  y=2cosx+3cosecxy=2\cos x+3\operatorname{cosec}x  , find  dydx\frac{\text{d}y}{\text{d}x}  

1

2sinx+3cosecxcotx2\sin x+3\operatorname{cosec}x\cot x   

2

2sinx+3cotxcosecx-2\sin x+3\cot x\operatorname{cosec}x  

3

2sinx3cosecxcotx-2\sin x-3\operatorname{cosec}x\cot x

4

sinxcosecxcotx-\sin x-\operatorname{cosec}x\cot x

Trigo Differentiation Basics

by Thavarajah Selvarajah

Show answer

Auto Play

Slide 1 / 42

SLIDE