
Trigo Differentiation Basics
Presentation
•
Mathematics
•
12th Grade
•
Practice Problem
•
Medium
Thavarajah Selvarajah
Used 13+ times
FREE Resource
8 Slides • 34 Questions
1
Trigo Differentiation Basics
by Thavarajah Selvarajah
2
3
RULE 1
4
RULE 2
​
5
6
LEVEL 1
DIFFERENTIATION USING RULE 1 AND RULE 2
7
Multiple Choice
Given y=tanx , dxdy=?
sec2x
sin2x
sec2w
1
8
Multiple Choice
dwd(tanw)=?
sin2w
sec2x
sec2w
1
9
Multiple Choice
Given y=−cosecx . Find dxdy
cosecx cot x
−cosecxcotx
sec2w
−sinx1
10
Multiple Choice
Given y=−43cosecx . Find dxdy
−cosecx cotx
cosecxcotx
43cosecxcotx
−43cosecxcotx
11
Multiple Choice
Given y=54cotx . What is dxdy?
−54cosec2x
54cosec2x
cosec2x
−cosec2x
12
Multiple Choice
Given y=−54cotx . What is dxdy?
−54cosec2x
54cosec2x
cosec2x
−cosec2x
13
Multiple Choice
y=cosx−sinx, dxdy=?
sinx−cosx
−sinx−cosx
sec2w
sinx+cosx
14
Multiple Choice
Given y=−sinx+cosx . What is dxdy=?
−cosx−sinx
cosx−sinx
−cosx+sinx
cosx+sinx
15
Multiple Choice
Given y=−sinx−cosx . What is dxdy=?
−cosx−sinx
cosx−sinx
−cosx+sinx
cosx+sinx
16
Multiple Choice
y=2sinx−3cotx
dxd(y)=dxd(2sinx)−dxd(3cotx)
p = q+r
What is p?
1
dxdy
y
dydx
17
Multiple Choice
y=2sinx−3cotx
dxd(y)=dxd(2sinx)−dxd(3cotx)
p = q+r
What is q?
2sinx
cosx
−2cosx
2cos x
18
Multiple Choice
y=2sinx−3cotx
dxd(y)=dxd(2sinx)−dxd(3cotx)
p = q+r
What is r?
−3cosec2x
3cosec2x
cosec2x
−cosec2x
19
Multiple Choice
Given y=−3cosx−4tanx . What is dxdy=?
−3sinx−4sec2x
3sinx−4sec2x
−sinx−sec2x
sinx−sec2x
20
Multiple Choice
Given y=−45cotx−3secx . What is dxd(−45cotx−3secx)
−45cosec2x−3secxtanx
45cosec2x−3secxtanx
−45cosec2x+3secxtanx
45cosec2x+3secxtanx
21
LEVEL 2
Combining trigo with weapons of Differentiation
22
23
Multiple Choice
y=cosxsinx .
What is the SUITABLE WEAPON we use to find dxdy
Product rule
Quotient rule
Direct
Chain Rule
24
Multiple Choice
y=sinx1 .
What is the SUITABLE WEAPON we use to find dxdy
Product rule
Quotient rule
Power Rule
Direct
25
Multiple Choice
y=cosecxsinx .
What is the SUITABLE WEAPON we use to find dxdy
Product rule
Quotient rule
Power Rule
Direct
26
Multiple Choice
y=sinx1 .
What is the SUITABLE WEAPON we use to find dxdy
Product rule
Quotient rule
Power Rule
Direct
27
Multiple Choice
y=secx .
What is the SUITABLE WEAPON we use to find dxdy
Product rule
Quotient rule
Power Rule
Direct
28
Multiple Choice
y=sinxcos x ,
dxdy=r(sinx)p−(cosx)q .
What is p?
−cosx
cosx
−sinx
sinx
29
Multiple Choice
y=sinxcos x ,
dxdy=r(sinx)p−(cosx)q .
What is q?
−cosx
cosx
−sinx
sinx
30
Multiple Choice
y=sinxcos x ,
dxdy=r(sinx)p−(cosx)q .
What is r?
cos2x
cosx
sinx
sin2x
31
Multiple Choice
y=cosxsin x ,
dxdy=r(cosx)p−(sinx)q .
What is p?
−cosx
cosx
−sinx
sinx
32
Multiple Choice
y=cosxsin x ,
dxdy=r(cosx)p−(sinx)q .
What is q?
−cosx
cosx
−sinx
sinx
33
Multiple Choice
y=cosxsin x ,
dxdy=r(cosx)p−(sinx)q .
What is r?
cos2x
cosx
sin2x
sinx
34
Multiple Choice
y=(cosx1)
dxd(y)=(cosx)−1
p=r(cosx)q(s)
What is r?
1
-1
35
Multiple Choice
y=cosx1
dxd(y)=(cosx)−1
p=r(cosx)q(s)
What is q?
0
-1
-2
2
36
Multiple Choice
y=cosx1
dxd(y)=(cosx)−1
p=r(cosx)q(s)
What is s?
cosx
sinx
−sinx
−cosx
37
Multiple Select
Given y=cosx1 , find dxdy
tanxsecx
cos2xsinx
sinxsec2x
cos2x1
38
Multiple Choice
Given y=2cosecxsinx , find dxdy
−2cosecxcotx
2
0
2cosecxcosx
39
Multiple Choice
Given y=sinxtanx , find dxdy
sinx+sinxsec2x
−sinx+sinxsec2x
cosxsec2x
sinx+sinxsecx
40
Multiple Choice
Given y=xsinx , find dxdy
cosx
xcosx+sinx
sinx−xcosx
xsinx+cosx
41
Multiple Choice
Given y=1−sinxcosx , find dxdy
1−sinx1
(1−sinx)21−sin2x+cos2x
(1−sinx)2cosx
1−sinx
42
Multiple Choice
Given y=2cosx+3cosecx , find dxdy
2sinx+3cosecxcotx
−2sinx+3cotxcosecx
−2sinx−3cosecxcotx
−sinx−cosecxcotx
Trigo Differentiation Basics
by Thavarajah Selvarajah
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