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Ln Differentiation

Ln Differentiation

Assessment

Presentation

Mathematics

12th Grade

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Created by

Thavarajah Selvarajah

Used 16+ times

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10 Slides • 14 Questions

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Ln Differentiation

by Thavarajah Selvarajah

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cant recall how to differentiate ln?​

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LEVEL 1

DIRECT

LOG DIFFERENTIATION

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Multiple Select

Given  y=ln (3x). dydx=?y=\ln\ \left(3x\right).\ \frac{dy}{dx}=?  

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13x\frac{1}{3x}  

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1x\frac{1}{x}  

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33x\frac{3}{3x}  

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Multiple Choice

y=3ln(x2+3x1). dydx=?y=-3\ln\left(x^2+3x-1\right).\ \frac{dy}{dx}=?  

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3x2+3x1\frac{-3}{x^2+3x-1}  

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2x+3x2+3x1\frac{2x+3}{x^2+3x-1}  

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6x9x2+3x1\frac{-6x-9}{x^2+3x-1}  

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1x2+3x1\frac{1}{x^2+3x-1}  

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Multiple Choice

y=ln2+xy=\ln\sqrt[]{2+x}  .  dydx=?\frac{dy}{dx}=?  

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12+x\frac{1}{\sqrt[]{2+x}}  

2

12(2+x)\frac{1}{2\left(2+x\right)}  

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2+x\sqrt[]{2+x}  

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12ln(2+x)12\frac{1}{2}\ln\left(2+x\right)^{-\frac{1}{2}}  

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​LEVEL 2

LOG DIFFERENTIATION RULES

​AND

​USE OF SEVERAL WEAPONS

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Multiple Choice

Given  y=(ln 2x)3y=\left(\ln\ 2x\right)^3  . What is the BEST WEAPON to find dydx=?\frac{dy}{dx}=?  

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Power Rule

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Quotient Rule

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Product Rule

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Chain Rule

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Direct

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Multiple Choice

Given  y=(ln 2x)3. dydx=?y=\left(\ln\ 2x\right)^3.\ \frac{dy}{dx}=?  

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3(ln2x)23\left(\ln2x\right)^2  

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3(ln2x)2(1x)3\left(\ln2x\right)^2\left(\frac{1}{x}\right)  

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3(ln2x)2(12x)3\left(\ln2x\right)^2\left(\frac{1}{2x}\right)  

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Multiple Choice

Given y=2xln 3x.y=2x\ln\ 3x.  What is the BEST WEAPON to find dydx=?\frac{dy}{dx}=?  

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Power rule

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Product Rule

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Quotient Rule

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Chain Rule

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Direct

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Multiple Choice

Given y=2xln 3x,  dydx=?y=2x\ln\ 3x,\ \ \frac{dy}{dx}=?  

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2ln3x+22\ln3x+2  

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2ln3x+232\ln3x+\frac{2}{3}  

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2(1x)2\left(\frac{1}{x}\right)  

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2xln3x+2x2x\ln3x+\frac{2}{x}  

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Multiple Choice

Given  y=e2xlnxy=\frac{e^{2x}}{\ln x}  . What is  dydx=?\frac{dy}{dx}=?  

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e2xx2e2xlnx(lnx)2\frac{\frac{e^{2x}}{x}-2e^{2x}\ln x}{\left(\ln x\right)^2}  

2

2e2xe2xx(lnx)2\frac{2e^{2x}-\frac{e^{2x}}{x}}{\left(\ln x\right)^2}  

3

2e2x1x\frac{2e^{2x}}{\frac{1}{x}}  

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e2xe2xx(lnx)2\frac{e^{2x}-\frac{e^{2x}}{x}}{\left(\ln x\right)^2}

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​LEVEL 3

law of log + differentiation 

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Multiple Choice

Given  y=ln(5x31)2(x2+1)y=\ln\left(5x^3-1\right)^2\left(\sqrt[]{x^2+1}\right)  . Which shows the correct use of law of log and ready to obtain yy'  ?

1

y=ln(5x31)2+lnx2+1y=\ln\left(5x^3-1\right)^2+\ln\sqrt[]{x^2+1}  

2

y=2ln(5x31)+lnx2+1y=2\ln\left(5x^3-1\right)^{ }+\ln\sqrt[]{x^2+1}

3

y=2ln(5x31)+12ln(x2+1)y=2\ln\left(5x^3-1\right)^{ }+\frac{1}{2}\ln\left(x^2+1\right)

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y=ln(5x31)2+ln(x2+1)12y=\ln\left(5x^3-1\right)^2+\ln\left(x^2+1\right)^{\frac{1}{2}}

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Multiple Choice

Given y=ln(x2(x2+2)2)y=\ln\left(\frac{\sqrt[]{x-2}}{\left(x^2+2\right)^2}\right)  .Which shows the correct use of law of log and READY to obtain yy'  ?

1

y=lnx2ln(x2+2)2y=\ln\sqrt[]{x-2}-\ln\left(x^2+2\right)^2  

2

y=lnx22ln(x2+2)y=\ln\sqrt[]{x-2}-2\ln\left(x^2+2\right)^{ }

3

y=12ln(x2)2ln(x2+2)y=\frac{1}{2}\ln\left(x-2\right)-2\ln\left(x^2+2\right)^{ }

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y=12ln(x2)+2ln(x2+2)y=\frac{1}{2}\ln\left(x-2\right)+2\ln\left(x^2+2\right)^{ }

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Multiple Choice

Given  y=ln(x21x2(12x3)).y=\ln\left(\frac{x^2-1}{x^2\left(1-2x^3\right)}\right).  Which shows the correct use of law of log and READY to obtain yy'  ?

1

y=ln(x21)ln[x2(12x3)]y=\ln\left(x^2-1\right)-\ln\left[x^2\left(1-2x^3\right)\right]

2

y=ln(x21)ln(x2)+ln(12x3)y=\ln\left(x^2-1\right)-\ln\left(x^2\right)+\ln\left(1-2x^3\right)

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y=ln(x21)ln(x2)ln(12x3)y=\ln\left(x^2-1\right)-\ln\left(x^2\right)-\ln\left(1-2x^3\right)

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y=ln(x21)2ln(x)ln(12x3)y=\ln\left(x^2-1\right)-2\ln\left(x^{ }\right)-\ln\left(1-2x^3\right)

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Multiple Choice

Given  y=ln(5x31)2(x2+1)y=\ln\left(5x^3-1\right)^2\left(\sqrt[]{x^2+1}\right) . What is  dydx=?\frac{dy}{dx}=?  

1

2(15x25x31)+12(2xx2+1)2\left(\frac{15x^2}{5x^3-1}\right)+\frac{1}{2}\left(\frac{2x}{x^2+1}\right)  

2

2(15x31)+12(1x2+1)2\left(\frac{1}{5x^3-1}\right)+\frac{1}{2}\left(\frac{1}{x^2+1}\right)  

3

15x25x31+2xx2+1\frac{15x^2}{5x^3-1}+\frac{2x}{x^2+1}  

4

30x210x32+x12x2+12\frac{30x^2}{10x^3-2}+\frac{x}{\frac{1}{2}x^2+\frac{1}{2}}  

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Multiple Choice

Given y=ln(x2(x2+2)2)y=\ln\left(\frac{\sqrt[]{x-2}}{\left(x^2+2\right)^2}\right) . dydx=?\frac{dy}{dx}=?  

1

1x21x2+2\frac{1}{x-2}-\frac{1}{x^2+2}  

2

1x22xx2+2\frac{1}{x-2}-\frac{2x}{x^2+2}  

3

12(1x2)2(2xx2+2)\frac{1}{2}\left(\frac{1}{x-2}\right)-2\left(\frac{2x}{x^2+2}\right)  

4

12x44x2x2+4\frac{1}{2x-4}-\frac{4x}{2x^2+4}  

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Multiple Choice

Given  y=ln(x21x2(12x3)).y=\ln\left(\frac{x^2-1}{x^2\left(1-2x^3\right)}\right). What is  dydx=?\frac{dy}{dx}=?  

1

1x212(1x)112x3\frac{1}{x^2-1}-2\left(\frac{1}{x}\right)-\frac{1}{1-2x^3}  

2

2xx212(1x)6x212x3\frac{2x}{x^2-1}-2\left(\frac{1}{x}\right)-\frac{6x^2}{1-2x^3}  

3

2xx212(1x)+6x212x3\frac{2x}{x^2-1}-2\left(\frac{1}{x}\right)+\frac{6x^2}{1-2x^3}  

4

2xx211x+6x212x3\frac{2x}{x^2-1}-\frac{1}{x}+\frac{6x^2}{1-2x^3}  

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Ln Differentiation

by Thavarajah Selvarajah

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