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Finding limits

Finding limits

Assessment

Presentation

Mathematics

10th - 12th Grade

Practice Problem

Medium

CCSS
HSF.IF.A.2, HSA.APR.A.1

Standards-aligned

Created by

Karine Ptak

Used 26+ times

FREE Resource

6 Slides • 6 Questions

1

Finding limits

by Karine Ptak

2

​Let's say we ask you to find a limit at a number...

  • ​your first line of defense would be to try and substitute the x-value into the function then...

    • ​if you get a number; that is the limit

    • ​if you get "undefined", you should try to get the limit by manipulating the function algebraically or by graphing and analyzing the graph

3

Multiple Choice

Question image

For example:  find the limit of the function in the picture by substituting 2 for x.  What y-value did you get for your limit?

1

undefined

2

0

3

4

4

-2

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Multiple Choice

Question image

For example:  find the limit of the function in the picture by substituting -4 for x.  What y-value did you get for your limit?

1

undefined

2

0

3

4

4

-2

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​The correct answer is that at -4 the function is undefined, so we need to manipulate it to get the limit

​Let's factor the denominator and see what happens

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​Factoring the denominator

media

7

Multiple Choice

Question image

Now evaluate the function at x = -4.  What do you get?

1

undefined

2

-4

3

-1/3

4

DNE

8

​Let's try another one...

​If you were to try step one, and substitute x = 1, you would get 0 in the denominator and the function would be undefined.

​Instead, we need to manipulate the numerator to hopefully eliminate x-1 from the denominator.

media

9

Multiple Choice

Question image

What is the conjugate of the numerator?

1

x+12\sqrt[]{x+1}-\sqrt[]{2}  

2

x+1+2\sqrt[]{x+1}+\sqrt[]{2}  

3

x1+2\sqrt[]{x-1}+\sqrt[]{2}  

4

x12\sqrt[]{x-1}-\sqrt[]{2}  

10

Multiple Choice

What is (x+12)(x+1+2)\left(\sqrt[]{x+1}-\sqrt[]{2}\right)\left(\sqrt[]{x+1}+\sqrt[]{2}\right)

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(x1)+2\left(x-1\right)+2  

2

(x1)2\left(x-1\right)-2  

3

(x+1)+2\left(x+1\right)+2  

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(x+1)2\left(x+1\right)-2  

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​Now that we have a new numerator...

​Now that the fraction is fully simplified, we can analyze the limit. In this case, the limit at 1 is 1, because that is what the

media

12

Multiple Choice

Question image

Try one on your own?  

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0

2

undefined

3

122\frac{1}{2\sqrt[]{2}}  

4

14\frac{1}{4}  

Finding limits

by Karine Ptak

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