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CIE Coordinated Science: 7.2 Redox

CIE Coordinated Science: 7.2 Redox

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Chemistry, Science

9th - 10th Grade

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Created by

Ricardo Echeverria-Valda

Used 6+ times

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9 Slides • 15 Questions

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CIE Coordinated Science: 7.2 Redox

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​Take a look at your notes from C4 stoichiometry and C5 electricity & chemistry, remind yourself of the following:

  • ​Chemical formulae

  • ​Ionic charges

  • ​OILRIG

  • ​Half-equations

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CIE Coordinated Science: 7.2 Redox

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CIE Coordinated Science: 7.2 Redox

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​Page 39 of the CIE 0654 syllabus

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CIE Coordinated Science: 7.2 Redox

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CIE Coordinated Science: 7.2 Redox

​How to identify redox reactions and how to find the reducing or oxidising agent.

6

Multiple Choice

When a substance is oxidised it will:

1

Gain electrons

2

Gain protons

3

Lose electrons

4

Lose protons

7

Fill in the Blank

Electrons are _____ charged

8

Multiple Choice

The oxidizing agent is the substance that:

1

Gains protons

2

Loses protons

3

Gains electrons

4

Loses electrons

9

Fill in the Blank

If a substance was reduced the electrons will be on the ____ side of the half reaction

10

Fill in the Blank

C5 Electricity & Chemistry: Which electrode gains mass in an electrochemical cell?

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CIE Coordinated Science: 7.2 Redox

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​1. Assign oxidation numbers (charges) to reactant atom.

​Cu = +2

​O = -2

​H2 = 0

Copper(II) Oxide - Roman numerals tell us the charge which gives us the oxidation state.

Hydrogen - this is the natural state of H which means the oxidation state = 0.

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CIE Coordinated Science: 7.2 Redox

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2. Assign oxidation numbers (charges) to product atoms:

​Cu = 0

​O = -2

​H2 = +1

Copper - elements are always 0.

Hydrogen - is always +1 unless bonded to a metal .

​Oxygen - is always -2.

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CIE Coordinated Science: 7.2 Redox

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3. Compare the oxidation state changes:

​Cu: +2 to 0

​Reduction - number decreases

​H: 0 to +1

​Oxidation - number increases

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CIE Coordinated Science: 7.2 Redox

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4. Identify the reducing and oxidising agents.

​Cu: +2 to 0

​Reduction - number decreases

This is the OXIDISING AGENT

​H: 0 to +1

​Oxidation - number increases

​This is the REDUCING AGENT

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Multiple Choice

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Defined as the gain of electrons.

1

oxidation

2

redox

3

reduction

4

LEO GER

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Multiple Choice

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Cl2 + 2e- --> 2Cl - is an example of:

1

a chemical reaction

2

redox

3

oxidation

4

reduction

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Multiple Choice

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An increase in oxidation number.

1

more acidic

2

reduction

3

less basic

4

oxidation

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Multiple Choice

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Substance that oxidises another substance by accepting its electrons.

1

reducing agent

2

oxidation number

3

combustion

4

oxidising agent

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Multiple Choice

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Which is the correct half-equation of this reaction: 2Na + Cl2 --> 2NaCl 

1

Cl2 + e- --> 2Cl-

2

2Cl - e- --> Cl2

3

Na --> Na+ + e-

4

Na+ + Cl--> NaCl

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Multiple Choice

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What is the reducing agent here: N2 + 3H2 --> 2NH3

1

N2

2

H2

3

NH3

4

2NH3

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Multiple Choice

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Substance that reduces another substance by losing electrons.

1

reducing agent

2

half-reaction

3

electronegative atom

4

oxidizing agent

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Multiple Choice

Question image
1

A

2

B

3

C

4

D

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Multiple Choice

Question image
1

A

2

B

3

C

4

D

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Multiple Choice

Question image
1

A

2

B

3

C

4

D

CIE Coordinated Science: 7.2 Redox

media

​Take a look at your notes from C4 stoichiometry and C5 electricity & chemistry, remind yourself of the following:

  • ​Chemical formulae

  • ​Ionic charges

  • ​OILRIG

  • ​Half-equations

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