
Review Substitution Method
Presentation
•
Mathematics
•
8th Grade
•
Practice Problem
•
Medium
+2
Standards-aligned
EDUARDO GORDIANO
Used 24+ times
FREE Resource
2 Slides • 15 Questions
1
Review Substitution Method
2
STEPS FOR USING SUBSTITUTION METHOD
Make sure AT LEAST ONE EQUATION is in the form of y = ......
Substitute one equation into the other!
Solve for x!
Substitute your x value into an original equation to find your y value!
3
Multiple Choice
y = 5x
y = 2x + 3
Are either equation in the system above in the form of y =...?
Neither say y =..
Only the top equation says y =...
Only the bottom equation says = ...
Both equations are in the form of y =...
4
Multiple Choice
y = 5x
y = 2x + 3
We will substitute top equation into the bottom, what does the substitution look like?
y = y
y = 5x
5x = 2x + 3
y = 2x + 3
5
Multiple Choice
After substituting we end up with:
5x = 2x + 3
How do we start solving for x?
Variables are both sides, so let's move them together!
Move the +3 to the other side!
Wait for Mr. G to solve it...
6
Multiple Choice
After substituting we end up with:
5x = 2x + 3
Let's move variables! But how do we do it?
Move the bigger one, 5x, to the right side.
Move the + 3 to the left side
Move the smaller one, 2x, to the left side.
7
Multiple Choice
After substituting we end up with:
5x = 2x + 3
When we move 2x, do we flip the sign or keep it the same?
Flip the sign, make it -2x!
Keep it as 2x!
8
Multiple Choice
After moving 2x, we end up:
5x - 2x = 3
3x = 3
Solve for x
x = 3
x = 1
x = -3
x = -1
9
Multiple Choice
We know x = 1 and our original system is:
y = 5x
y = 2x + 3
Substitute x = 1 into either equation to solve for y.
y = 1
y = 5
y = 2
y = 3
10
Multiple Choice
Try solving this system on your own now:
y = 2x -2
y =3x
x = -2
y = -6
(-2,-6)
x = 6
y =2
(6,2)
x = 1
y = 6
(1,6)
x = 0
y = -2
(0,-2)
11
Multiple Choice
Lets try a new type of problem
y = 3x + 8
8x + 4y = 12
Are either equation in the system above in the form of y =...?
Neither say y =..
Only the top equation says y =...
Only the bottom equation says = ...
Both equations are in the form of y =...
12
Multiple Choice
Lets sub the top equation into the bottom one.
y = 3x + 8
8x + 4y = 12
What is the end result?
8x + 4y = 12
8x + 4y = 3x + 8
8x + 4(3x + 8) = 12
13
Multiple Choice
8x + 4(3x + 8) = 12
Lets deal with the 4(3x + 8)
After we distribute what do we end up with?
3
4x + 8
12x + 32
14
Multiple Choice
We end up with this!
8x + 12x + 32= 12
When we collect like terms what do we end up with?
12x + 32 = 12
20x + 32 = 12
8x + 32 = 12
15
Multiple Choice
We end up with this!
20x + 32 = 12
Solve this two step equation.
x = 20
x = -1
x = 5
16
Multiple Choice
We end up with x = -1
Sub it into the original equations to find y value
y = 3x + 8
8x + 4y = 12
y = 20
y = 5
y = 1
17
Multiple Choice
Try solving this system on your own now:
y = 2x + 1
3x + 4y = 26
(0,6)
(2,5)
(3,5)
Review Substitution Method
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