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Review Substitution Method

Review Substitution Method

Assessment

Presentation

Mathematics

8th Grade

Practice Problem

Medium

CCSS
8.EE.C.8B, 7.EE.B.4A, 6.EE.A.3

+2

Standards-aligned

Created by

EDUARDO GORDIANO

Used 23+ times

FREE Resource

2 Slides • 15 Questions

1

Review Substitution Method

2

STEPS FOR USING SUBSTITUTION METHOD

  • ​Make sure AT LEAST ONE EQUATION is in the form of y = ......​

  • ​Substitute one equation into the other!

  • ​Solve for x!

  • ​Substitute your x value into an original equation to find your y value!

3

Multiple Choice

y = 5x

y = 2x + 3

Are either equation in the system above in the form of y =...?

1

Neither say y =..

2

Only the top equation says y =...

3

Only the bottom equation says = ...

4

Both equations are in the form of y =...

4

Multiple Choice

y = 5x

y = 2x + 3

We will substitute top equation into the bottom, what does the substitution look like?

1

y = y

2

y = 5x

3

5x = 2x + 3

4

y = 2x + 3

5

Multiple Choice

After substituting we end up with:

5x = 2x + 3

How do we start solving for x?

1

Variables are both sides, so let's move them together!

2

Move the +3 to the other side!

3

Wait for Mr. G to solve it...

6

Multiple Choice

After substituting we end up with:

5x = 2x + 3

Let's move variables! But how do we do it?

1

Move the bigger one, 5x, to the right side.

2

Move the + 3 to the left side

3

Move the smaller one, 2x, to the left side.

7

Multiple Choice

After substituting we end up with:

5x = 2x + 3

When we move 2x, do we flip the sign or keep it the same?

1

Flip the sign, make it -2x!

2

Keep it as 2x!

8

Multiple Choice

After moving 2x, we end up:

5x - 2x = 3

3x = 3

Solve for x

1

x = 3

2

x = 1

3

x = -3

4

x = -1

9

Multiple Choice

We know x = 1 and our original system is:

y = 5x

y = 2x + 3

Substitute x = 1 into either equation to solve for y.

1

y = 1

2

y = 5

3

y = 2

4

y = 3

10

Multiple Choice

Try solving this system on your own now:

y = 2x -2

y =3x

1

x = -2

y = -6

(-2,-6)

2

x = 6

y =2

(6,2)

3

x = 1

y = 6

(1,6)

4

x = 0

y = -2

(0,-2)

11

Multiple Choice

Lets try a new type of problem

y = 3x + 8

8x + 4y = 12

Are either equation in the system above in the form of y =...?

1

Neither say y =..

2

Only the top equation says y =...

3

Only the bottom equation says = ...

4

Both equations are in the form of y =...

12

Multiple Choice

Lets sub the top equation into the bottom one.

y = 3x + 8

8x + 4y = 12

What is the end result?

1

8x + 4y = 12

2

8x + 4y = 3x + 8

3

8x + 4(3x + 8) = 12

13

Multiple Choice

8x + 4(3x + 8) = 12

Lets deal with the 4(3x + 8)

After we distribute what do we end up with?

1

3

2

4x + 8

3

12x + 32

14

Multiple Choice

We end up with this!

8x + 12x + 32= 12

When we collect like terms what do we end up with?

1

12x + 32 = 12

2

20x + 32 = 12

3

8x + 32 = 12

15

Multiple Choice

We end up with this!

20x + 32 = 12

Solve this two step equation.

1

x = 20

2

x = -1

3

x = 5

16

Multiple Choice

We end up with x = -1

Sub it into the original equations to find y value

y = 3x + 8

8x + 4y = 12

1

y = 20

2

y = 5

3

y = 1

17

Multiple Choice

Try solving this system on your own now:

y = 2x + 1

3x + 4y = 26

1

(0,6)

2

(2,5)

3

(3,5)

Review Substitution Method

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