Search Header Logo
Unit 7 Lesson 7.3: Special Right Triangles

Unit 7 Lesson 7.3: Special Right Triangles

Assessment

Presentation

Mathematics

9th Grade

Practice Problem

Medium

CCSS
8.G.B.8, HSG.SRT.C.8, HSG.CO.C.10

Standards-aligned

Created by

Chelsey Zeiders

Used 10+ times

FREE Resource

21 Slides • 7 Questions

1

media

Unit 7 Lesson 7.3:

Special Right

Triangles

MT: Solving Applied Problems & Modeling in Geometry

2

ISOSCELES RIGHT TRIANGLES

The "45°-45°-90°" Triangle

In this triangle, the following must be true:

  1. Both legs must be CONGRUENT.

  2. Both acute angles must be CONGRUENT (45°​).

  3. The hypotenuse will always be LARGER than the legs.​

media

​Leg1

​Leg2

Hypotenuse

45°

45°

3

ISOSCELES RIGHT TRIANGLES

Since the 45°-45°-90° triangle is special, it comes with something called a CONSTANT RATIO.

This ratio represents EVERY 45°-45°-90° triangle IN THE WORLD.

Ratio:

x : x : x√2

leg1 leg2 hypotenuse

media

4

ISOSCELES RIGHT TRIANGLES

x : x : x√2

leg1 leg2 hypotenuse

That "x" can represent ANY NUMBER IN THE WORLD as long as it isn't:

  • zero

  • negative​

media

5

ISOSCELES RIGHT TRIANGLES

Follow these steps to find the missing sides​:

STEP 1: Write down the constant ratio. ​

STEP 2: Write the value of given side UNDERNEATH its constant ratio.

STEP 3: Use the patterns/shortcuts to fill in the other sides.

Patterns and shortcuts are given during the next example.

6

ISOSCELES RIGHT TRIANGLES

Example:

​Given the triangle to the right, find the value of the legs.

STEP 1: Write down the constant ratio.

media
media

7

ISOSCELES RIGHT TRIANGLES

Example:

​Given the triangle to the right, find the value of the legs.

STEP 2: Write down given value underneath its constant ratio.

media
media

8

ISOSCELES RIGHT TRIANGLES

Example:

​Given the triangle to the right, find the value of the legs.

​​

STEP 3: Use patterns/shortcuts to fill in other missing sides.

media

9

ISOSCELES RIGHT TRIANGLES

SHORTCUTS: If given a leg FIRST, follow these steps to find the hypotenuse:

  1. Add a √​2 to the end of the leg's value

  2. Simplify if necessary.

​​

SHORTCUTS: If given the hypotenuse FIRST, follow these steps to find the legs:

  1. Divide the hypotenuse by 2.

  2. Add a √​2 to the end of the value.

  3. Simplify if necessary.

media
media

10

FACTORING ROOTS

Sometimes a root can be simplified MORE than it already is. In other words, sometimes theres a root within a root.

To simplify a root, you FACTOR the value with hopes of finding a PERFECT ROOT (a factor that will simplify to a whole number.

Follow these steps:

  1. Find all factor pairs of the value.

  2. Cross out any factor pair including the number 1.

  3. Find a pair where at least ONE is the perfect root.

  4. Rewrite the original root.

  5. Simplify if necessary.

11

FACTORING ROOTS

Follow these steps:

  1. Find all factor pairs of the value.

  2. Cross out any factor pair including the number 1.

  3. Find a pair where at least ONE is the perfect root.

  4. Rewrite the original root.

  5. Simplify.

media

12

Multiple Choice

Question image

Determine the length of the hypotenuse for the given 45-45-90 triangle:

1

6 26\ \sqrt[]{2}  

2

2 22\ \sqrt[]{2}  

3

4 34\ \sqrt[]{3}  

4

3 23\ \sqrt[]{2}  

13

Multiple Choice

Question image

Determine the length of the legs for the given 45-45-90 triangle:

1

  16 616\ \sqrt[]{6}  

2

  32 632\ \sqrt[]{6}  

3

16 216\ \sqrt[]{2}    

4

32 232\ \sqrt[]{2}  

14

Multiple Choice

Question image

Determine the length of the hypotenuse for the given 45-45-90 triangle:

1

  4 54\ \sqrt[]{5}  

2

  8 58\ \sqrt[]{5}  

3

  8 108\ \sqrt[]{10}  

4

8 38\ \sqrt[]{3}    

15

Multiple Choice

Question image

Determine the length of the legs for the given 45-45-90 triangle:

1

13 22\frac{13\ \sqrt[]{2}}{2}     

2

26 1026\ \sqrt[]{10}   

3

13 1013\ \sqrt[]{10}  

4

13 102\frac{13\ \sqrt[]{10}}{2}  

16

HALF OF AN EQUILATERAL TRIANGLE

The "30°-60°-90°" Triangle

In this triangle, the following must be true:

  1. The legs can NEVER be congruent.

  2. The long leg is also referred to as the ALTITUDE.

  3. The hypotenuse will always be LARGER than the legs.​

media

​Leg 1

​Leg 2

Hypotenuse

45°

45°

17

media

HALF OF AN EQUILATERAL TRIANGLE

Since the 30°-60°-90° triangle is special, it comes with something called a CONSTANT RATIO.

This ratio represents EVERY 30°-60°-90° triangle IN THE WORLD.

Ratio:

x : x√3 : 2x

short leg long leg hypotenuse

18

media

HALF OF AN EQUILATERAL TRIANGLE

x : x√3 : 2x

short leg long leg hypotenuse

That "x" can represent ANY NUMBER IN THE WORLD as long as it isn't:

  • zero

  • negative​

The long leg is also known as:

  • altitude

  • height​

19

Follow these steps to find the missing sides​:

STEP 1: Write down the constant ratio. ​

STEP 2: Write the value of given side UNDERNEATH its constant ratio.

STEP 3: Use the patterns/shortcuts to fill in the other sides.

Patterns and shortcuts are given during the next example.

HALF OF AN EQUILATERAL TRIANGLE

20

HALF OF AN EQUILATERAL TRIANGLE

Example:

​Given the triangle to the right, find the value of the long leg & hypotenuse.

STEP 1: Write down the constant ratio.

media
media

21

HALF OF AN EQUILATERAL TRIANGLE

Example:

​Given the triangle to the right, find the value of the long leg & hypotenuse.

STEP 2: Write the value of given side UNDERNEATH its constant ratio.

media
media

22

HALF OF AN EQUILATERAL TRIANGLE

Example:

​Given the triangle to the right, find the value of the long leg & hypotenuse.

STEP 3: Use patterns/shortcuts to fill in other missing sides.

media

23

HALF OF AN EQUILATERAL TRIANGLE

SHORTCUTS: If given the short leg FIRST, follow these steps to find the others:

  1. Add a √​3 to the end of the short leg's value to find the long leg. Simplify if necessary.

  2. Multiply the short leg by 2 to find the hypotenuse.

media

24

HALF OF AN EQUILATERAL TRIANGLE

SHORTCUTS: If given the long leg FIRST, follow these steps to find the others:

  1. Divide the long leg by 3, then add another √3 to the end to find the short leg. Simplify if necessary.

  2. Multiply the short leg by 2 to find the hypotenuse.

media

25

HALF OF AN EQUILATERAL TRIANGLE

SHORTCUTS: If given the hypotenuse FIRST, follow these steps to find the legs:

  1. Divide the hypotenuse by 2 to find the short leg.

  2. Add a √​3 to the end of the short leg's value to find the long leg. Simplify if necessary.

media

26

Multiple Choice

Question image

Determine the length of the long leg & the hypotenuse for the given 30-60-90 triangle:

1

LL = 14 214\ \sqrt[]{2}  

HYP = 14 314\ \sqrt[]{3}  

2

LL = 14 314\ \sqrt[]{3}  

HYP = 14 214\ \sqrt[]{2}  

3

LL = 14 314\ \sqrt[]{3}  

HYP = 2828  

4

LL = 14 214\ \sqrt[]{2}  

HYP = 2828  

27

Multiple Choice

Question image

Determine the length of the short leg & the hypotenuse for the given 30-60-90 triangle:

1

SL = 99  

HYP = 1818  

2

SL = 2727  

HYP = 5454  

3

SL = 3 33\ \sqrt[]{3}  

HYP = 6 36\ \sqrt[]{3}  

4

SL = 9 69\ \sqrt[]{6}  

HYP = 18 618\ \sqrt[]{6}  

28

Multiple Choice

Question image

Determine the length of the short leg & the long leg for the given 30-60-90 triangle:

1

SL = 4 64\ \sqrt[]{6}  

LL = 12 212\ \sqrt[]{2}  

2

SL = 88  

LL = 8 38\ \sqrt[]{3}  

3

SL = 8 28\ \sqrt[]{2}  

LL = 8 68\ \sqrt[]{6}  

4

SL = 2 22\ \sqrt[]{2}  

LL = 2 62\ \sqrt[]{6}  

media

Unit 7 Lesson 7.3:

Special Right

Triangles

MT: Solving Applied Problems & Modeling in Geometry

Show answer

Auto Play

Slide 1 / 28

SLIDE