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Factor by Grouping

Factor by Grouping

Assessment

Presentation

•

Mathematics

•

9th Grade

•

Practice Problem

•

Hard

•
CCSS
7.EE.A.1, HSA-REI.B.4B, 8.EE.C.7B

Standards-aligned

Created by

Carson Costa

Used 20+ times

FREE Resource

8 Slides • 7 Questions

1

Factor by Grouping

2

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3

Factor by Grouping

A polynomial can be factored by grouping only if these conditions exist:

  • There are 4 or more terms

  • Terms have common factors that can be grouped together

  • There are two common factors that are identical or additive inverses of each other​

​

ax + bx + ay + by = (ax + bx) + (ay + by)

= x(a + b) + y(a + b)

= (x + y)(a + b)​

Some text here about the topic of discussion

4

media

Step 1: Group terms with common factors

​

Step 2: Factor the GCF from each group

​

Step 3: Distributive Property​​

​

4qr + 8r + 3q +6

5

Multiple Choice

rn + 5n - r - 5

1

(r - 1)(5 + n)

2

(r + 5)(n - 1)

3

r(n + 5n - 6)

4

5r(n - 1)

6

Multiple Choice

3np + 15p - 4n - 20

1

(3p + 5)(n - 4)

2

3p - 4(n + 5)

3

(3p - 4)(n + 5)

4

3p - 4 + n + 5

7

​Additive Inverse

two values, when ​added together, that cancel out

​

the additive inverse of 2ab is -2ab​

8

media

Step 1: Group terms with common factors

​

Step 2: Factor the GCF from each group

​

Step 3: Additive Inverse

​

Step 4: Distributive Property​

​

2mk - 12m + 42 - 7k

9

Multiple Choice

Which of these is an example of additive inverse?

1

-6a + 6ab

2

12xy - 6xy

3

20x - 15x - 5x

4

-6x + 2x - 4x

10

Multiple Choice

c - 2cd + 8d - 4

1

c - 4(1 - 2d)

2

(c - 1)(2d - 4)

3

(c + 4) - (2d - 1)

4

(c - 4)(1 - 2d)

11

3(0) =

​

0(2 - 2) =

​

-312(0) =

​

0(0.25) =​

If a product of two factors is 0, at least one of the factors MUST be 0

​

For any real numbers a and b, if ab = 0, then a = 0, b = 0, or both​

​Zero Product Property:

Solve Equations by Factoring

12

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Step 1: Get 0 on one side of the equation​

​

Step 2: Zero Product Property

​

Step 3: Solve each equation using inverse operations (remember first semester!)​

​

Answer: Write your answer in terms of solutions or roots.​​

(2d + 6)(3d - 15) = 0

13

media

Step 1: Get 0 on one side of the equation​

​

Step 2: Zero Product Property

​

Step 3: Solve each equation using inverse operations (remember first semester!)​

c2 = 3c

14

Fill in the Blanks

Solve by factoring:

x2 = -10x

Type answer...

15

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