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Review 6.4-6.5

Review 6.4-6.5

Assessment

Presentation

Mathematics

9th - 11th Grade

Easy

Created by

Adrian Navarro

Used 3+ times

FREE Resource

1 Slide • 9 Questions

1

Review 6.4-6.5

Sum and difference, double angle and Half- angle​.

By Adrian Navarro

2

Multiple Choice

What does sin ( u + v ) =

1

sinucosv-cosusinv

2

sinucosv+cosusinv

3

cosucosv - sinusinv

4

cosucosv + sinusinv

3

Multiple Choice

Now find the exact value of

sin ( 60 + 45 )

1

6+24\frac{\sqrt[]{6}+\sqrt[]{2}}{4}  

2

3+24\frac{\sqrt[]{3}+2}{4}  

3

232-\sqrt[]{3}  

4

Multiple Choice

What does sin(2u) =

1

2sin u cos u

2

sin u + cos u

3

3sinu

4

2sin u 2 cos u

5

Multiple Select

Solve

sin2x + cos x = 0

1

cos x = 0\cos\ x\ =\ 0  

x = π2, 3π2x\ =\ \frac{\pi}{2},\ \frac{3\pi}{2}  

2

sin x = 12\sin\ x\ =\ -\frac{1}{2}  

x = 7π6, 11π6x\ =\ \frac{7\pi}{6},\ \frac{11\pi}{6}  

3

sin x = 0\sin\ x\ =\ 0  

x = 0, πx\ =\ 0,\ \pi  

4

cos x = 12\cos\ x\ =\ \frac{1}{2}  

6

Multiple Choice

What does

cos u2=\cos\ \frac{u}{2}=  

1

±1+cosu2\pm\sqrt[]{\frac{1+\cos u}{2}}  

2

±1cosu2\pm\sqrt[]{\frac{1-\cos u}{2}}  

3

1cos usin u\frac{1-\cos\ u}{\sin\ u}  

7

Multiple Choice

Use the half-angle formula to determine cos ( 165 ).

1

2+32-\frac{\sqrt[]{2+\sqrt[]{3}}}{2}  

2

232\frac{\sqrt[]{2-\sqrt[]{3}}}{2}  

3

2+3-\sqrt[]{2+\sqrt[]{3}}  

4

23\sqrt[]{2-\sqrt[]{3}}  

8

Open Ended

If you are given sin u = 35, and  u is between  3π2<u < 2π-\frac{3}{5},\ and\ \ u\ is\ between\ \ \frac{3\pi}{2}<u\ <\ 2\pi  What do you need to make?

9

Multiple Choice

Find sin 2u given sin u = 35, and  u is between  3π2<u < 2π-\frac{3}{5},\ and\ \ u\ is\ between\ \ \frac{3\pi}{2}<u\ <\ 2\pi  

1

2425-\frac{24}{25}  

2

1516\frac{15}{16}  

3

2019\frac{20}{19}  

10

Open Ended

What do you need to know in order to be successful for the next Quiz/Test?

Review 6.4-6.5

Sum and difference, double angle and Half- angle​.

By Adrian Navarro

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