
2.2 c: Limiting Reactant
Presentation
•
Science, Chemistry
•
10th Grade - University
•
Practice Problem
•
Easy
Erin Hannan
Used 18+ times
FREE Resource
11 Slides • 3 Questions
1
Limiting Reactant
2.2 c: explore the concept of the mole and relate this to Avogadro’s constant to describe, calculate and manipulate masses, chemical amounts and numbers of particles in: (ACSCH007, ACSCH039)
– moles of elements and compounds 𝑛 = 𝑚 /𝑀𝑀 (n = chemical amount in moles, m = mass in grams, MM = molar mass in gmol-1 ) Stoichiometry
– percentage composition calculations and empirical formulae
– limiting reagent reactions
2
What we will cover
definition
limiting reactant
theoretical yield
actual yield
percent yield
calculations
example questions
3
An analogy about limiting reactants
To make 5 pancakes you need:
1 cup of flour
2 eggs
1/2 tsp of baking powder
Say you have 3 cups of flour, 10 eggs, and 4 tsp of flour. How many pancakes can you make?
4
Only 15 pancakes.
The 3 cups of flour = the limiting reactant
And 15 pancakes is the theoretical yield
Imagine we then accidentally burn 3 of the pancakes, we would only have 12. This is the percentage yield
So our percentage yield = (12/15) x 100 = 80%
5
Example: LR from initial mole values
Ti + 2Cl2 --> TiCl4
Given 1.8 mol of titanium and 3.2 mol of chlorine, what is the limiting reactant of the reaction, and the theoretical yield of TiCl4 in moles?
Cl2 must be the limiting reactant, because it produces the least amount of product.
1.6 moles is the theoretical yield.
6
Open Ended
Consider the reaction:
2 Al + 3 Cl2 --> 2 AlCl3
If you begin with 0.552 mol of aluminium, and 0.887 mol of chlorine, what is the limiting reactant and theoretical yield of AlCl3 in moles?
7
Solution
8
Example: LR from initial masses
Consider the reaction and reactant masses given below
9
Open Ended
Ammonia is synthesised by the reaction:
2 NO + 5 H2 --> 2 NH3 + 2H2O
What maximum amount of ammonia in grams can be synthesised from 45.8g of NO and 12.4g of H2?
10
Solution:
11
12
Open Ended
Consider the reaction:
Cu2O + C --> 2 Cu + CO
When 11.5g of C are reacted with 114.5g of Cu2O, 87.4g of Cu are obtained. Find the limiting reactant, the theoretical yield, and the percentage yield.
13
Solution
14
What we will cover next
Concentration of solutions and molarity
Limiting Reactant
2.2 c: explore the concept of the mole and relate this to Avogadro’s constant to describe, calculate and manipulate masses, chemical amounts and numbers of particles in: (ACSCH007, ACSCH039)
– moles of elements and compounds 𝑛 = 𝑚 /𝑀𝑀 (n = chemical amount in moles, m = mass in grams, MM = molar mass in gmol-1 ) Stoichiometry
– percentage composition calculations and empirical formulae
– limiting reagent reactions
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