Statistika (3) Ukuran Penyebaran Data

Multiple Choice

Rumus menentukan rentang/jangkauan data adalah  $$R=$$ ....

• $$X_{\max}-X_{\min}$$  

• $$Q_3-Q_1$$  

• $$\frac{1}{2}\left(Q_3-Q_1\right)$$  

• $$\frac{1}{n}\sum_{n=1}^n\left|x_i-\overline{x}\right|$$  

Multiple Choice

Rumus menentukan rentang antar kuartil/hamparan data adalah  $$H=$$ ....

• $$X_{\max}-X_{\min}$$  

• $$Q_3-Q_1$$  

• $$\frac{1}{2}\left(Q_3-Q_1\right)$$  

• $$\frac{1}{n}\sum_{n=1}^n\left|x_i-\overline{x}\right|$$  

Multiple Choice

Rumus menentukan simpangan kuartil data adalah  $$Q_d=$$ ....

• $$X_{\max}-X_{\min}$$  

• $$Q_3-Q_1$$  

• $$\frac{1}{2}\left(Q_3-Q_1\right)$$  

• $$\frac{1}{n}\sum_{n=1}^n\left|x_i-\overline{x}\right|$$  

Multiple Choice

Rumus menentukan simpangan rata-rata data adalah  $$SR=$$ ....

• $$\sqrt{\frac{1}{n}\sum_{n=1}^n\left(x_i-\overline{x}\right)^2}$$  

• $$\frac{1}{n}\sum_{n=1}^n\left(x_i-\overline{x}\right)$$  

• $$\frac{1}{n}\sum_{n=1}^n\left(x_i-\overline{x}\right)^2$$  

• $$\frac{1}{n}\sum_{n=1}^n\left|x_i-\overline{x}\right|$$  

Multiple Choice

Rumus menentukan ragam (varians) data adalah  $$s^2=$$ ....

• $$\sqrt{\frac{1}{n}\sum_{n=1}^n\left(x_i-\overline{x}\right)^2}$$  

• $$\frac{1}{n}\sum_{n=1}^n\left(x_i-\overline{x}\right)$$  

• $$\frac{1}{n}\sum_{n=1}^n\left(x_i-\overline{x}\right)^2$$  

• $$\frac{1}{n}\sum_{n=1}^n\left|x_i-\overline{x}\right|$$  

Multiple Choice

Rumus menentukan simpangan baku (standar deviasi) data adalah  $$s=$$ ....

• $$\sqrt{\frac{1}{n}\sum_{n=1}^n\left(x_i-\overline{x}\right)^2}$$  

• $$\frac{1}{n}\sum_{n=1}^n\left(x_i-\overline{x}\right)$$  

• $$\frac{1}{n}\sum_{n=1}^n\left(x_i-\overline{x}\right)^2$$  

• $$\frac{1}{n}\sum_{n=1}^n\left|x_i-\overline{x}\right|$$  

Multiple Choice

Metode menentukan simpangan baku (standar deviasi) dari data; $$2,3,4$$ adalah ....

• $$s^2=\frac{\left(2-3\right)^2+\left(3-3\right)^2+\left(4-3\right)^2}{3}$$  

• $$s^2=\frac{\left(2+3\right)^2-\left(3+3\right)^2-\left(4+3\right)^2}{3}$$  

• $$s=\sqrt{\frac{\left(2-3\right)^2+\left(3-3\right)^2+\left(4-3\right)^2}{3}}$$  

• $$s=\sqrt{\frac{\left(2+3\right)^2-\left(3+3\right)^2-\left(4+3\right)^2}{3}}$$