
Differentiation of trigonometric function
Presentation
•
Mathematics
•
KG
•
Practice Problem
•
Medium
Emmanuel Ogbone
Used 5+ times
FREE Resource
4 Slides • 12 Questions
1
Differentiation deals with rates of change. That is how one quantity varies with respect to another quantity. The rate of change of y with respect to x for a straight line is constant. However, this is different for a curve. Differentiating a function y = f (x) gives a gradient function written as dy/dx or f-1 (x).
2
3
4
5
Multiple Choice
dyd(sinx)
cosx
−cosx
sin−1x
sinx1
sinxcosx
6
Multiple Choice
dyd(cosx)
−sinx
sinx
cos−1x
cosx1
−sinxcosx
7
Multiple Choice
dyd(tanx)
sec2x
−sec2x
tan−1x
tanx1
secx
8
Multiple Choice
dyd(secx)
secxtanx
−secxtanx
sec−1x
secx1
cscxcotx
9
Multiple Choice
dyd(2sinx+x3)
2cosx+3x2
−2cosx+3x2
2cosx+4x4
2cosx+2x2
−2cosx+2x2
10
Multiple Choice
dyd(−3cosx−4x2)
3sinx−8x
−3sinx−8x
3sinx−4x
3sinx−12x3
−3sinx−4x
11
Multiple Choice
Find dxdy of y = ln (6x+1)
6x+11
6x+16
6x1
6
12
Multiple Choice
Find dy/dx for y=e6x
e6x
6e6x
e6x−1
6xe6x−1
13
Multiple Choice
Find dy/dx for y= cos 4x
dy/dx = -4 sin 4x
dy/dx=sin 4x
dy/dx = - 4 cos 4x
dy/dx = 4 sin 4x
14
Multiple Choice
find the expression for the derivative of the following expression: −5 cos x
5 sin x
−5 sin x
5 cos x
−5 cos x
15
Multiple Choice
find the expression for the derivative of the following expression: 2 sin (4−3x)
−6 cos (4−3x)
6 cos (4−3x)
2 cos (4−3x)
−2 cos (4−3x)
16
Multiple Choice
If y = esecx then dxdy=
secxtanx.esecx
esecx
esecx.tanx
secx.esecx−1
Differentiation deals with rates of change. That is how one quantity varies with respect to another quantity. The rate of change of y with respect to x for a straight line is constant. However, this is different for a curve. Differentiating a function y = f (x) gives a gradient function written as dy/dx or f-1 (x).
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