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GCF & Grouping

GCF & Grouping

Assessment

Presentation

Mathematics

9th - 12th Grade

Hard

CCSS
4.OA.B.4

Standards-aligned

Created by

Michelle Wilson

Used 10+ times

FREE Resource

13 Slides • 14 Questions

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Multiple Choice

What are all of the factors of 12?

1

1 and 12

2

1, 2, 3, 4, & 6

3

1, 2, 3, 4, 6, & 12

4

1, 2, 3, 4, 6, 10, & 12

5

12, 24, 36, 48, 72 , 84...

6

Multiple Choice

Which pair of numbers has a GCF of 8?

1

8, 36

2

40, 80

3

16, 56

4

24, 42

7

Multiple Choice

What is the GCF of 12 and 30?

1

2

2

4

3

6

4

8

5

12

8

Multiple Choice

Find the GCF of 64 and 144
1

8

2

6

3

16

4

2

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Multiple Choice

What is the GCF of 18k and 15k3
1

3k2

2

3k3

3

3k

4

5k

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Multiple Choice

What is the GCF of

24xy2, 36x3y5z, and 18x2y3z224xy^2,\ 36x^3y^5z,\ and\ 18x^2y^3z^2  

1

6xy26xy^2  

2

6x3y5z26x^3y^5z^2  

3

12xyz12xyz  

4

12xy212xy^2  

14

Multiple Choice

Factor out the GCF


3x3 + 9x

1

3x (x2 + 3)

2

3x ( x3 + 9)

3

x (3x2 + 9)

4

3x (x3 + 3x)

15

Multiple Choice

Factor by GCF:
6m2 + 16m
1

2(3m2 + 8m)

2

2m(3m + 8)

3

2m(3m - 8m)

4

not factorable

16

Multiple Choice

Factor:
10a4+16a+10a2
1

2a(5a3+8+5a)

2

2a4(5a+8a2+5a3)

3

2a4(10+16a+40a2)

4

3a3(5+8a+a2)

17

Multiple Choice

Factor
-64a4b - 96ab3 + 8a
1

-8a(8a3b + 12b3 - a)

2

-8ab(8a3 - 12b2 - 1)

3

8a(8a3b - 12b2 + 1)

4

-8a(8a3b + 12b3 - 1)

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Multiple Choice

Factor by grouping: x34x24x+16x^3-4x^2-4x+16  

1

(x+4)(x+2)\left(x+4\right)\left(x+2\right)  

2

(x4)(x24)\left(x-4\right)\left(x^2-4\right)  

3

(x+4)(x24)\left(x+4\right)\left(x^2-4\right)  

4

(x4)(x2)\left(x-4\right)\left(x-2\right)  

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Multiple Choice

Factor by grouping:

x3+7x22x14x^3+7x^2-2x-14  

1

(x22)(x7)\left(x^2-2\right)\left(x-7\right)  

2

(x2+2)(x+7)\left(x^2+2\right)\left(x+7\right)  

3

(x2+2)(x7)\left(x^2+2\right)\left(x-7\right)  

4

(x22)(x+7)\left(x^2-2\right)\left(x+7\right)  

25

Multiple Choice

What is the factored form of 5n310n2+3n65n^3-10n^2+3n-6  ?

1

(5n2+3)(n2)\left(5n^2+3\right)\left(n-2\right)  

2

(5n23)(n2)\left(5n^2-3\right)\left(n-2\right)  

3

(5n3+3)(n2)\left(5n^3+3\right)\left(n-2\right)  

4

10n(n26)10n\left(n^2-6\right)  

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