Search Header Logo
Distance

Distance

Assessment

Presentation

Mathematics

University

Practice Problem

Easy

Created by

Azi Saban

Used 2+ times

FREE Resource

13 Slides • 6 Questions

1

media

Slide - 7

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Objective 1 Use the Distance Formula

2

media
media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 8

Example 1: Finding the Distance
Between Two Points (1 of 2)

Find the distance d between the points (2, 1) and (6, 6).

Solution:

First plot the points (2, 1) and
(6, 6) and connect them with a
straight line.

To find the length d, begin by
drawing a horizontal line from
(2, 1) to (6, 1) and a vertical
line from (6, 1) to (6, 6), forming
a right triangle, as shown.

3

media
media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 9

Example 1: Finding the Distance
Between Two Points (2 of 2)

One leg of the triangle is of length 4

6

2 = 4)

(since

and the other is of length 5

6

1 = 5).

(since

By the Pythagorean Theorem,
the square of the distance d that
we seek is

2

2

2

= 4 + 5 = 16 + 25 = 41

d

=

41

6.40

d

4

media
media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 10

Theorem 1

Distance Formula

The distance between two points 1

1

1

)

P

x , y

and

2

2

2

1

2

)

( ,

),

,

, denoted by

is

P

x y

d P P

2

2

1 2

2

1

2


= (

) =

(

) + (

)

,

(1)

d P P

x

x

y

y

Illustration of the
Distance Formula


= (


= (

5

media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 11

Example 2: Finding the Length
of a Line Segment

Find the length of the line segment between the points

1

2
( –1, 4)

(5, 3).

P

P

and

Solution:

The length of the line segment is the distance between
the points
1

1

1

2

2

2
( ,

)

( 1, 4)

(

,

)

(5, 3).

P

x y

P

x y

=

= −

=

=

and

Using the distance formula
with

1

1

2
1,

4,

5,

x

y

x

= −

=

=

and

2
3,=y

the length d is

2

2

2

1

2

1

2

2

2

2

=

(

) + (

)

=

(5

( 1)) + (3

4)

=

6 + ( 1) =

36 +1

=

37

6.08.

d

x

x

y

y

− −

media

6

media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 12

Example 3: Using Algebra to Solve
Geometry Problems (1 of 5)

Consider the three points A = (−4, 2), B = (1, 2),
and C = (0, 4).

(a) Plot each point and form the triangle ABC.

(b) Find the length of each side of the triangle.

(c) Verify that the triangle is a right triangle.

(d) Find the area of the triangle.

7

media
media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 13

Example 3: Using Algebra to Solve
Geometry Problems (2 of 5)

Solution:

(a) The figure shows points A, B, C, and triangle
ABC.

8

media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 14

Example 3: Using Algebra to Solve
Geometry Problems (3 of 5)

(b) To find the length of each side of the triangle,
use the distance formula.

2

2

( , )

[1 ( 4)]

(2

2)

25

0

25

5

d A B =

− −

+

=

+

=

=

2

2

( , )

(0 1)

(4

2)

1

4

5

d B C =

+

=

+

=

2

2

( , )

[0

( 4)]

(4

2)

16

4

20

2 5

d A C =

− −

+

=

+

=

=

9

media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 15

Example 3: Using Algebra to Solve
Geometry Problems (4 of 5)

(c) If the sum of the squares of the lengths of two of
the sides equals the square of the length of the third
side, the triangle is a right triangle. Looking at the
figure, we conjecture that the angle at vertex C might
be a right angle.

2

2

2

( , )

( , )

( , )

d A C

d B C

d A B

+

=

 

2

2
2

2 5

5

5

+

=

20

5

25

+

=

Triangle ABC is
a right triangle.

media

10

media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 16

Example 3: Using Algebra to Solve
Geometry Problems (5 of 5)

(d) Because the right angle is at vertex C, the sides
AC and BC form the base and height of the triangle.
Its area is

(

)(

)

1

1
Area

(Base)(Height)

2 5

5

5 square units
2

2
=

=

=

media

11

media

Slide - 17

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Objective 2 Use the Midpoint Formula

12

media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 18

Theorem 2

Midpoint Formula

The midpoint M = (x, y) of the line segment from

(

)

(

)
1

1

1

2

2

2
=

,

=

,

to

is

P

x y

P

x

y

(

)
1

2

1

2
+

+
=

,

=

,
2

2


(2)
x

x

y

y
M

x y

media

13

media

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Slide - 19

Example 4: Finding the Midpoint
of a Line Segment

Find the midpoint of a line segment from

1

2
( 6,2)

(4, 6).

and

P

P

Solution:

Apply the midpoint formula using
1

1
6,

2,

= −

=

x

y

2

2
4,

6.

and

=

=

x

y

Then the coordinates of the midpoint M are

1

2
6

4
1
2

2

+

− +
=

=

= −
x

x
x

and

1

2
2

6
4
2

2

y

y
y
+

+
=

=

=

That is,
(

)
= –1, 4 .

M

media

14

Open Ended

Question image

Find the distance between P1 ad P2

15

Open Ended

The midpoint of the line segment from P1 to P2 is (- 1, 4). If P1 = (- 3, 6), what is P2?

16

Open Ended

Question image

A major league baseball “diamond” is actually a square 90 feet on a side (see the figure). What is the distance directly from home plate to second base (the diagonal of the square)?

17

Open Ended

Refer to the major league problem, overlay a rectangular coordinate system on a major league baseball diamond so that the origin is at home plate, the positive x-axis lies in the direction from home plate to first base, and the positive y-axis lies in the direction from home plate to third base. What are the coordinates of first base, second base, and third base? Use feet as the unit of measurement.

18

Open Ended

Refer to previous question, If the center fielder is located at (310, 15), how far is it from the center fielder to third base?

19

Open Ended

Refer to previous question, If the center fielder is located at (300, 300), how far is it from the center fielder to third base?

media

Slide - 7

Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved

Objective 1 Use the Distance Formula

Show answer

Auto Play

Slide 1 / 19

SLIDE