
(P1T4Q2) Integration By Parts [CLASS//QUIZIZZ]
Presentation
•
Mathematics
•
12th Grade
•
Practice Problem
•
Medium
Jan García
Used 6+ times
FREE Resource
3 Slides • 17 Questions
1
(P1T4Q2) Integration By Parts [CLASS//QUIZIZZ]
2
Integrate
3
Math Response
∫ln(x)⋅x3dx
Step 1.1: Choose "u"
(use LIATE)
u=___
4
Math Response
∫ln(x)⋅x3dx
Step 1.2: Choose "dv"
dv=___dx
5
Math Response
∫ln(x)⋅x3dx
Step 2.1: Calculate "du"
du=___dx
6
Math Response
∫ln(x)⋅x3dx
Step 2.2: Calculate "v"
v=___
7
Reorder
Reorder the following:
What's the formula for Integration by Parts?
u
v
−∫v
du
8
Multiple Choice
uv−∫vdu
Step 3.1: Substitute in the formula
(ln(x))(4x4)−∫(4x4)(x1dx)
(ln(x))(x3)−∫(x1)(2x2dx)
9
Multiple Choice
(ln(x))(4x4)−∫(4x4)(x1dx)
Step 3.2: Simplification
4x4⋅ln(x)−41∫x4dx
4x4−ln(x)−4∫x4dx
10
Multiple Choice
4x4⋅ln(x)−41∫x4dx
Step 3.3: Solving the remaining integral
4x4⋅ln(x)−41(5x5+C)
4x4⋅ln(x)−41(4x3+C)
11
Math Response
4x4⋅ln(x)−41(5x5+C)
Step 3.4: Write down the final answer
∫ln(x)⋅x3dx= _____+C
12
Integrate
13
Math Response
∫8x⋅cos(2x)dx
Step 1.1: Choose "u"
(use LIATE)
u=___
14
Math Response
∫8x⋅cos(2x)dx
Step 1.2: Choose "dv"
dv=___dx
15
Math Response
∫8x⋅cos(2x)dx
Step 2.1: Calculate "du"
du=___dx
16
Math Response
∫8x⋅cos(2x)dx
Step 2.2: Calculate "v"
(you may have to use U-Substitution)
v=___
17
Multiple Choice
uv−∫vdu
Step 3.1: Substitute in the formula
(8x)(2sin(2x))−∫(2sin(2x))(8dx)
(8)(2sin(2x))−∫(2sin(2x))(8xdx)
18
Multiple Choice
(8x)(2sin(2x))−∫(2sin(2x))(8dx)
Choose the correct answer:
Step 3.2: Simplification
4x⋅sin(2x)−4∫sin(2x)dx
4x⋅sin(2x)+4x∫cos(2x)dx
19
Multiple Choice
4x⋅sin(2x)−4∫sin(2x)dx
Choose the correct answer:
Step 3.3: Solving the remaining integral
(you may have to use U-Substitution)
4x⋅sin(2x)−4(−2cos(2x)+C)
4x⋅sin(2x)−4(2cos(2x)+C)
20
Math Response
4x⋅sin(2x)−4(−2cos(2x)+C)
Step 3.4: Write down the final answer
∫8x⋅cos(2x)dx= _____+C
(P1T4Q2) Integration By Parts [CLASS//QUIZIZZ]
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