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9.1 The Ellipse

9.1 The Ellipse

Assessment

Presentation

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Mathematics

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11th Grade

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Easy

Created by

Larry Cooper

Used 1+ times

FREE Resource

19 Slides • 17 Questions

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​9.1 The Ellipse
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Multiple Choice

Planets orbit the Sun in a shape called a(n)...#30

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circle

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ellipse

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focus

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perihelion

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Multiple Choice

Which of the following represents and equation of an ellipse? #34

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x2=16yx^2=16y

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x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

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x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

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xb2+ya2=1\frac{x}{b^2}+\frac{y}{a^2}=1

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Multiple Choice

The line containing the center and foci. #20

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Major Axis

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Minor Axis

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Vertices

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Co-Vertices

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Multiple Choice

An ellipse centered at the origin has a vertical major axis length of 8 units and a horizontal minor axis length of 4. What is the equation of the ellipse? #23

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x24+y216=1\frac{x^2}{4}+\frac{y^2}{16}=1  

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x216+y24=1\frac{x^2}{16}+\frac{y^2}{4}=1  

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x216+y264=1\frac{x^2}{16}+\frac{y^2}{64}=1  

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x264+y216=1\frac{x^2}{64}+\frac{y^2}{16}=1  

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Multiple Select

Which of the following equations represents an ellipse? #33

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(x+1)24+(y−2)29=1\frac{\left(x+1\right)^2}{4}+\frac{\left(y-2\right)^2}{9}=1

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x225+y29=1\frac{x^2}{25}+\frac{y^2}{9}=1

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(x+1)2+4(y−2)2=16\left(x+1\right)^2+4\left(y-2\right)^2=16

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(x−3)24−(y+2)29=1\frac{\left(x-3\right)^2}{4}-\frac{\left(y+2\right)^2}{9}=1

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Multiple Choice

In an ellipse, what is the length of the major axis? #35

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a

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2a

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b

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2b

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Multiple Choice

Question image

Find the standard equation of the given ellipse. #3

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Multiple Choice

Question image

What are the co-vertices of the given ellipse? #4

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(5, −4) and (5, 2)\left(5,\ -4\right)\ and\ \left(5,\ 2\right)

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(−2, −1) and (12, −1)\left(-2,\ -1\right)\ and\ \left(12,\ -1\right)  

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(−1, −2) and (−1, 12)\left(-1,\ -2\right)\ and\ \left(-1,\ 12\right)

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(−4, 5) and (2, 5)\left(-4,\ 5\right)\ and\ \left(2,\ 5\right)

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Multiple Choice

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What is the center of the ellipse? #5

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(0, 0)

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(1, 5)

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(1, 0)

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(0, 1)

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Multiple Choice

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What are the vertices of the ellipse? #7

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(0, 0)

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(7, 1) and (-1, 1)

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(3, -5) and (3, 7)

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(3, 1)

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Multiple Choice

What is the center, a and b values for the following equation: x2 + 4y2 + 16x - 80y + 320 = 0 #8

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(-8, 10); a = 12, b = 6

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(-8, 10); a = 6, b = 12

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(8, -10); a = 12, b = 6

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(8, -10); a = 6, b = 12

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Multiple Choice

Question image

Find the standard equation of the given ellipse. #17

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Multiple Choice

Question image

The graph of an ellipse is shown. Which equation represents this ellipse? #24

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(x−1)216+(y+1)236=1\frac{\left(x-1\right)^2}{16}+\frac{\left(y+1\right)^2}{36}=1

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(x−1)236+(y+1)216=1\frac{\left(x-1\right)^2}{36}+\frac{\left(y+1\right)^2}{16}=1

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(x+1)216+(y−1)236=1\frac{\left(x+1\right)^2}{16}+\frac{\left(y-1\right)^2}{36}=1

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(x+1)236+(y−1)216=1\frac{\left(x+1\right)^2}{36}+\frac{\left(y-1\right)^2}{16}=1

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Multiple Choice

Question image

The graph of an ellipse is shown. Which equation represents this ellipse? #25

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(x+3)29+(y−2)225=1\frac{\left(x+3\right)^2}{9}+\frac{\left(y-2\right)^2}{25}=1

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(x−3)225+(y+2)29=1\frac{\left(x-3\right)^2}{25}+\frac{\left(y+2\right)^2}{9}=1

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(x−3)29+(y+2)225=1\frac{\left(x-3\right)^2}{9}+\frac{\left(y+2\right)^2}{25}=1

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(x+3)225+(y−2)29=1\frac{\left(x+3\right)^2}{25}+\frac{\left(y-2\right)^2}{9}=1

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Multiple Choice

Write an equation for the ellipse with each set of characteristics. Then answer the question. Vertices ( 4, 3), (4, - 9) Length of the minor axis is 8. What is the center of this ellipse? #19

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(4, 6)

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( - 4, 3)

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(6, 4)

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(4, -3)

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Multiple Choice

Write an equation for the ellipse with each set of characteristics. Then answer the question. Vertices ( -7, -3), (13, - 3) foci ( - 5, -3 ), (11, -3). What is the a and b value of the ellipse? #21

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a = 10 , b = 6

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a = 6 , b = 10

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a = 36 , b = 100

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a = 100 , b = 36

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Multiple Choice

Write the equation of an ellipse that has a major axis of 12 units in length, with foci at  (±5, 0)\left(\pm5,\ 0\right)  . #29

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(x−5)236+(y+5)211=1\frac{\left(x-5\right)^2}{36}+\frac{\left(y+5\right)^2}{11}=1  

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x211+y236=1\frac{x^2}{11}+\frac{y^2}{36}=1  

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x236+y211=1\frac{x^2}{36}+\frac{y^2}{11}=1  

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(x+5)211+(y−5)236=1\frac{\left(x+5\right)^2}{11}+\frac{\left(y-5\right)^2}{36}=1  

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