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Pre-Calculus Review: Equations and Formulas

Pre-Calculus Review: Equations and Formulas

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Education

•

12th Grade

•

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Created by

April Smith

Used 3+ times

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7 Slides • 15 Questions

1

Quadratic Equation:
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Quadratic Formula:

2

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3

Multiple Select

X intercepts are also called....

1

Solutions

2

Parabolas

3

Roots

4

Puppies

4

Multiple Choice

Given a graph, how can you find the "solutions" to a quadratic?

1

Copy off neighbor

2

Plug into calculator

3

Solutions are where the quadratic crosses the x axis

4

Magic 8 Ball

5

Multiple Choice

How many solutions do quadratics have?

1

2

2

At least 2

3

infinite

4

1

6

Multiple Select

Question image

What are the green dots called?

1

roots

2

vertex

3

solutions

4

x intercepts

7

Multiple Choice

Question image

What are the x- intercepts?

1

(0,0) and (0,4)

2

(0,0) and (4,0)

3

y= 0

4

x= 2

8

Multiple Choice

Question image

Use the graph to determine the solutions.

1

-1 and -3

2

1 and -3

3

1 and 3

4

-1 and 3

9

The standard form of a quadratic equation is ax2+bx+c

What are the values for a, b and c in the following quadratic equation?

3x2+5x-1

10

Multiple Choice

Determine the values of
a, b, and c for
the quadratic equation: 
4x2 – 8x = 3
*remember right side should =0
1
a = 4, b = -8, c = 3
2
a = 4, b =-8, c =-3
3
a = 4, b = 8, c = 3
4
a = 4, b = 8, c = -3

11

Multiple Choice

Identify a, b, and c in: x2−6x+14

1

a=3,b=5,c=9

2

a=1,b=-6,c=14

3

a=1,b=-6,c=-14

4

a=1,b=6,c=14

12

Multiple Choice

Determine the values of a, b, and c for the quadratic equation:

4x2 – 8x = 3

1

a = 4, b = -8, c = 3

2

a = 4, b =-8, c =-3

3

a = 4, b = 8, c = 3

4

a = 4, b = 8, c = -3

13

Distance Formula
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14

Multiple Choice

How is the distance formula correctly written:

1

d = (y1 − y2)2 −(x2 − x1)2 d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ -\left(x_{2\ }-\ x_1\right)^2}\

2

d = (x2 − x1)2 + (y2 − y1 )2d\ =\ \sqrt{\left(x_{2\ }-\ x_1\right)^2\ +\ \left(y_{2_{\ }}-\ y_1\ \right)^2}

3

d = (y1 − y 2)2 + (x2 − x1)2d\ =\ \sqrt{\left(y_{1\ }-\ y\ _2\right)^2\ +\ \left(x_{2\ }-\ x_1\right)}^2

4

d = (x)2− (y)2\sqrt{\left(x\right)^2-\ \left(y\right)^2}

15

Multiple Choice

A(3,1) B(-2,-1) written correctly is:

1

(−2−3)2 + (−1−1)2\sqrt{\left(-2-3\right)^2\ +\ \left(-1-1\right)^2}

2

(1−3)2 + (−1−2)2\sqrt{\left(1-3\right)^2\ +\ \left(-1-2\right)^2}

3

(−2−3)2 − (−1−1)2\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}

4

(−2−3)2 − (−1−1)2\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}

16

Multiple Choice

Find the distance between the points (4, 3) and (0, 6).

1

3

2

4

3

5

4

7

17

Point Slope Form

y-y1= m(x - x1)

media

18

y-y1= m(x - x1)

m= 2

(1, 6)


m is your slope

1 is your x value

6 is your y value




Plug in your values


y- 6= 2(x - 1)

19

Multiple Choice

m= 5


(2, 4)

1

y - 2= 5(x - 4)

2

y - 4= 5(x - 2)

3

y- 5 = 4(x - 2)

4

y - 2 = 4(x - 5)

20

Multiple Choice

Which of these represents point-slope form of a linear equation?
1

y - y1 = m(x - x1)

2

Ax + By = C

3

y = mx + b

4

y=kx

21

y - y1= m(x - x1)

When your COORDINATE has a negative value, you must change it to positive.


m=5

(-1, 2)


y - 2 = 5(x + 1)


Notice how at the end it was +1 because it was -1 as the x value.

22

Multiple Choice

Write the equation in point-slope form of the line that passes through the given point and has the given slope:

(-2, -1); m= -3

1

y + 1 = -3(x - 2)

2

y + 1 = -3(x + 2)

3

y - 1 = 3(x - 1)

4

y + 2 = -3(x + 1)

pattern-tertiary
Quadratic Equation:
media
Quadratic Formula:

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