
Recap on Parabola, Vertex and Axis of Symmetry
Presentation
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Mathematics
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•
Practice Problem
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Easy
Solomon Abalaka
Used 2+ times
FREE Resource
21 Slides • 35 Questions
1
Curved Graphs
Plotting Parabola
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Objectives
Construct a table of values for quadratic
Plot the graph of a parabola from a table of values
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What is a parabola?
A parabola is a smooth U-shaped curve.
An equation of the form y = ax2 + bx + c will graph to give a parabola.
This lesson concentrates on parabolas of the form y = ax2 + c.
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Read the equation of a parabola
You can draw a quick sketch of a parabola using the information from its equation, y = ax2 + c.
The coefficient of x2, a, tells you the DIRECTION and WIDTH of the parabola.
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Read the equation of a parabola
You can draw a quick sketch of a parabola using the information from its equation, y = ax2 + c.
The constant value, c, in the equation of a parabola, tells you the y-intercept. Changing the constant term c moves the curve up or down the axis.
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The axis of symmetry and vertex
The axis of symmetry is the line along which the graph can be folded so that both halves of the parabola overlap.
The vertex is the point at which the parabola turns.
For y = ax2 + c, the axis of symmetry is the y-axis (x = 0)
For y = ax2 + c, the vertex is the y-intercept (0,c).
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The domain and range
The domain represents the possible x values of the parabola and the range gives the possible y values
For the parabola y = x2 + 2:
the domain is: all real values of x
the range is: y ≥ 2
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Describing a parabola (1)
Concave up
x-intercepts = –8 and 8 y-intercept = –1
Minimum = –1
Domain: all real x Range: y ≥ –1
Vertex: (0, –1)
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Describing a parabola (2)
Concave down
x-intercepts = –5 and 5 y-intercept = 7
Maximum = 7
Domain: all real x Range: y ≤ 7
Vertex: (0, 7)
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Describing a parabola (3)
Concave up
No x-intercepts , y-intercept = 2
Minimum = 2
Domain: all real x Range: y ≥ 2
Vertex: (0, 2)
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Describing a parabola (4)
Concave down
x-intercepts s = - V5 and V5, y-intercept = 5
Maximum = 5
Domain: all real x Range: y ≤ 5
Vertex: (0, 5)
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Multiple Choice
If graph f is y = x2, what will the graph of g (red curve) be?
y = 3x2
y= - 3x2
y = 1/3 x2
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Multiple Choice
Which of the following is true about the graph?
maximum = -4
minimum = -4
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Multiple Choice
Which of the following is true about the graph?
y-intercept = -4
y-intercept = -2 and 2
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Multiple Choice
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Multiple Choice
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Multiple Choice
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Multiple Choice
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Multiple Choice
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Multiple Choice
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Multiple Choice
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Multiple Choice
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Multiple Choice
y = x2 - 6x + 11?
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Multiple Choice
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Multiple Choice
Does the equation Up or or down?
Y = -3x2 +7x - 2
up
down
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Multiple Choice
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Multiple Choice
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Multiple Choice
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Multiple Choice
Which equation is in standard form?
y=a(x-h)2+k
y=ax2+bx+c
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Multiple Choice
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Multiple Choice
f(x)=ax2+bx+c
Quadratic Function
Linear Function
Polynomial
Trinomial
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Multiple Choice
Where the minimum or maximum value of a quadratic function occurs
Vertex of a Parabola
Axis of Symentry
Parent Function
Quadratic
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Quadratic Functions
● Using Vertex Form
● Using Standard Form
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Quadratic Functions
● Using Vertex Form
● Using Standard Form
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Quadratic Functions
● Using Vertex Form
● Using Standard Form
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Multiple Choice
Write the vertex form of the equation that has the indicated vertex and passes through the given point.
Vertex (-1,4); point (1,0)
f(x)=a(x−h)2+k
f(x)=−(x+1)2+4
f(x)=(x+1)2+4
f(x)=−(x+4)2+1
f(x)=−(x+1)2
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Multiple Choice
Write the vertex form of the equation that has the indicated vertex and passes through the given point.
Vertex (-2,-1); point (0,3)
f(x)=a(x−h)2+k
f(x)=−(x+1)2+3
f(x)=(x+2)2−1
f(x)=−(x+5)2+7
f(x)=(x−3)2
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Multiple Choice
Write the vertex form of the equation that has the indicated vertex and passes through the given point.
Vertex (-2,5); point (0,9)
f(x)=a(x−h)2+k
f(x)=(x+5)2+2
f(x)=(x−5)2
f(x)=(x+2)2−5
f(x)=(x+2)2+5
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Multiple Choice
If given the equation y = 3(x + 5)2 - 4, what is the vertex of the parabola?
(5,-4)
(-5,-4)
(-15, 4)
(15, -4)
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Vertex Form of a Quadratic Function
​
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Learning Objectives
Determine the vertex of a quadratic function
Graph a quadratic function in vertex form
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Multiple Select
Check all of the equations that are in standard form
y=2x+1
y=x2+4x−9
y=4(x−5)2+3
y=x2+9
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Multiple Select
Select all equations that are in vertex form
y=x2+5x
y=3(x+4)2−1
y=−(x+3)2−2
y=(x+3)(x−2)
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Fill in the Blanks
Vertex form gives you the
Type answer...
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Multiple Choice
If given the equation y = 3(x + 5)2 - 4, what is the vertex of the parabola?
(5,-4)
(-5,-4)
(-15, 4)
(15, -4)
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Steps to graphing a quadratic equation in Vertex Form
Identify the vertex (h,k)
Select 2 more x's close to one side of the vertex to plug into the equation.
Reflect those two points to the other side of the axis of symmetry
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Poll
Did you read the previous slide?
Yes
No
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Multiple Choice
You already have that the equation y = 3(x + 5)2 - 4 has a vertex at (-5, -4). Click on the image to enlarge. The next step is to pick 2 x's close to the axis of symmetry and on the same side of the axis of symmetry. What would you pick
-6 and -7
-6 and -4
-5 and -6
-5 and -7
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Poll
If you plug in -6 and -7 for x you'll get the two points which are now graphed. When a graph has an axis of symmetry, it means the graph is same on both sides. Do you see that you could reflect the new points across the axis of symmetry to get two more points on the other side? Click on image to make it larger.
Yes
No
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Open Ended
Here's what your graph should look like. What questions do you have? Click on the image to view the graph.
55
Multiple Choice
Sketch the graph of the following function
56
Multiple Choice
Sketch the graph of the following function
Curved Graphs
Plotting Parabola
Show answer
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