Search Header Logo
Quadratic Formula and Discriminant

Quadratic Formula and Discriminant

Assessment

Presentation

Mathematics

9th Grade

Medium

CCSS
HSA-REI.B.4B, HSN.CN.C.7

Standards-aligned

Created by

Kimberlee Joy

Used 3+ times

FREE Resource

1 Slide • 11 Questions

1

media
media
media

Rational Solutions

Irrational Solutions

Imaginary Solutions

2

Multiple Choice

Solve Using the Quadratic Formula
 x2 + 4x - 40 = -8
1
-10 & -4
2
-4 & 10
3
-8 & 4
4
8 & -4

3

Multiple Choice

Determine the values of
a, b, and c for
the quadratic equation: 
4x2 – 8x = 3
1
a = 4, b = -8, c = 3
2
a = 4, b =-8, c =-3
3
a = 4, b = 8, c = 3
4
a = 4, b = 8, c = -3

4

Multiple Choice

What does the discriminant tell us?
1
The maximum or minimum
2
The y-intercept
3
The number and type of solutions
4
The axis of symmetry

5

Multiple Choice

The formula to determine how many solutions a quadratic equation is called the discriminant which is...

1

aX2 + bX + c

2

b - 4ac

3

b2 - 4ac

4

b2 + 4ac

6

Multiple Choice

If the discriminant is negative, you will have....

1

two real solutions

2

two irrational solutions

3

no real solution

4

one solution

7

Multiple Choice

Use the discriminant to determine the number of solutions the following quadratic equation has.

6x2 − 2x − 3 = 0

1

76 Two Solutions

2

29 Two Solutions

3

68 Two Solutions

4

none of these

8

Multiple Choice

Solve using the Quadratic Formula:
5x2+3x1=05x^2+3x-1=0

1

x=3±295x=\frac{3\pm\sqrt{29}}{5}  

2

x=85 or x=25x=\frac{8}{5}\ or\ x=-\frac{2}{5}  

3

x=3±2910x=\frac{-3\pm\sqrt{29}}{10}  

4

No real solutions

9

Multiple Choice

Solve by using a method of your choice:

k2 − 12k + 23 = 0

1

{6 + √13, 6 - √13}

2

{-6 + √13, -6 - √13}

3

{6 + √59, 6 - √59}

4

{-6 + √59, -6 - √59}

10

Multiple Choice

Simplify √-4
1
2i
2
-2i
3
2
4
4i

11

Multiple Choice

For 2x2  4x + 3 = 0, which is correct?For\ 2x^2\ -\ 4x\ +\ 3\ =\ 0,\ which\ is\ correct?  

1

4 ±16 4(2)(3)2(2)\frac{4\ \pm\sqrt{-16\ -4\left(2\right)\left(3\right)}}{2\left(2\right)}  

2

4 ±16 4(2)(3)2(2)\frac{-4\ \pm\sqrt{16\ -4\left(2\right)\left(3\right)}}{2\left(2\right)}  

3

4±164(2)(3)4\frac{4\pm\sqrt{16-4\left(2\right)\left(3\right)}}{4}  

4

4±404\frac{4\pm\sqrt{40}}{4}  

12

Multiple Choice

Solve

2x2+4x +10=02x^2+4x\ +10=0  

Simplify answers

1

4 ±8i-4\ \pm8i  

2

1±2i-1\pm2i  

3

4 ±8i4\frac{-4\ \pm8i}{4}  

4

±8i\pm8i  

media
media
media

Rational Solutions

Irrational Solutions

Imaginary Solutions

Show answer

Auto Play

Slide 1 / 12

SLIDE