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Midterm Review- Algebra 2

Midterm Review- Algebra 2

Assessment

Presentation

Mathematics

12th Grade

Easy

Created by

Hana Specht

Used 2+ times

FREE Resource

35 Slides • 26 Questions

1

Factoring GCF, Difference of Squares, and Trinomials Review

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2

Factoring a GCF

Review

3

Steps to Factor Using the GCF

  • Find the GCF of the numbers (use Desmos if you need).

  • Find the GCF of the variables. If a variable is in EVERY term, use the one with the smallest exponent.

  • Write the GCF in front of parentheses.

  • Divide each term in the problem by the GCF (dividing the coefficients and subtracting the exponents), and write the remainder inside the parentheses.

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4

Multiple Choice

Factor:
5a2155a^2-15  

1

5(a215)5\left(a^2-15\right)  

2

5a(a15)5a\left(a-15\right)  

3

5(a23)5\left(a^2-3\right)  

4

5a(a3)5a\left(a-3\right)  

5

Multiple Choice

12c220a212c^2-20a^2  

Factor:

1

2(6c210a2)2\left(6c^2-10a^2\right)  

2

4(3c25a2)4\left(3c^2-5a^2\right)  

3

2a2c2(610)2a^2c^2\left(6-10\right)  

4

4(ca)2(35)4\left(ca\right)^2\left(3-5\right)  

6

Multiple Choice

Factor the polynomial.

   50x3+60x26050x^3+60x^2-60  

1

    5(10x3+12x212)5\left(10x^3+12x^2-12\right)  

2

    10(5x3+6x26)10\left(5x^3+6x^2-6\right)  

3

    10x(5x3+6x26)10x\left(5x^3+6x^2-6\right)  

4

    10x(5x2+6x6)10x\left(5x^2+6x-6\right)  

7

Multiple Choice

Factor the polynomial.

       77x921x7+49x577x^9-21x^7+49x^5  

1

        7x5(11x43x2+7)7x^5\left(11x^4-3x^2+7\right)  

2

        7x5(11x53x2+7)7x^5\left(11x^5-3x^2+7\right)  

3

        7(11x93x7+7x5)7\left(11x^9-3x^7+7x^5\right)  

4

        7x(11x83x6+7x4)7x\left(11x^8-3x^6+7x^4\right)  

8

Factoring Difference of Squares

Review

9

Steps to Factor with Difference of Squares

  • Check to make sure you have a difference of squares! You should have two perfect squares separated by a subtraction sign.

  • Take the square root of each term.

  • Write your two factors using the rule: a2-b2 = (a+b)(a-b).

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10

Multiple Choice

x2 - 9
1
(x + 3) (x - 3)
2
(x - 3) (x - 3)
3
(x + 3) (x - 6)
4
Can't factor using Diff. of Squares

11

Multiple Choice

4a2 - 25
1
(2a + 5) (2a - 5)
2
(2a - 5) (2a - 5)
3
(x + 5) (x - 5)
4
Can't factor using Diff. of Squares

12

Multiple Choice

4m2 + 49
1
(2m + 7) (2m - 7)
2
(2m - 7) (2m - 7)
3
(m + 7) (m - 7)
4
Can't factor using Diff. of Squares

13

Factoring a Trinomial with a=1

Review

14

Steps to Factoring Trinomial (a=1)

  • Trinomial: ax2+bx+c

    Goal: Find factors of c that add up to b.

  • Use the graphic organizer flow chart to figure out the signs of the numbers.

  • If needed, make a table of possible factors that multiply to your c value. Find the pair that add up to b.

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15

Multiple Choice

Factor completely.
k2 -2k - 24
1
(k+4)(k-6)
2
(k+4)(k+6)
3
(k+6)(k-1)
4
(k-4)(k+6)

16

Multiple Choice

Factor completely: x2-6x+8
1
(x-2)(x-4)
2
(x-1)(x-8)
3
(x+2)(x+4)
4
(x+1)(x+8)

17

Multiple Choice

Factor completely: x2-13x+40
1
(x-5)(x-8)
2
(x+5)(x+8)
3
(x-4)(x-10)
4
(x-2)(x-20)

18

Steps to Factor a GCF out First

  • Factor the GCF following the same methods as before (find the GCF of the numbers, of the variables, the divide it from each term)

  • If what is left in parentheses is a difference of squares, factor what is in parentheses using that method. Write the GCF in front.

  • If what is left in parentheses is a trinomial, factor what is in parentheses using that method. Write the GCF in front.

19

GCF with Difference of Squares

1. Factor out GCF

2. Factor remaining difference of squares

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20

GCF with Trinomial (a=1)

1. Factor out GCF

2. Factor remaining trinomial

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21

Multiple Choice

125x25125x^2-5  



Factor out the GCF first. Then, factor using another method.

1

5(3x+4)(3x4)5\left(3x+4\right)\left(3x-4\right)  

2

5(5x+1)(5x1)5\left(5x+1\right)\left(5x-1\right)  

3

(5x1)2\left(5x-1\right)^2  

4

5(25x+1)25\left(25x+1\right)^2  

22

Multiple Choice

Factor completely.
3x- 9x -120
1
3(x - 8)(x + 5)
2
3(x + 8)(x - 5)
3
(3x + 8)(x - 5)
4
(3x - 8)(x + 5)

23

Factoring when a>1

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Watch this video for a review: https://www.youtube.com/watch?v=z-80Tlx0jEc

24

Multiple Choice

Factor:
 2m² + 3m - 9
1
2(m + 3)(m - 3)
2
(2m - 3)²
3
(m + 3)(2m - 3)
4
(2m + 3)(m - 3)

25

Multiple Choice

Factor Completely:  6x² + 5x - 6
1
6(x + 1)(x - 6)
2
(6x + 6)(x - 1)
3
(2x - 3)(3x + 2)
4
(3x - 2)(2x + 3)

26

Multiple Choice

Factor
3v2 - 4v - 7
1
(3v-7)(v+1)
2
3(v-7)(v-1)
3
(3v+1)(v-9)
4
(3v+1)(v-10)

27

Solving Quadratics by Square Roots

Review

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28

To solve quadratic equations, we use inverse (opposite) operations

29

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30

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31

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32

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34

​Day 2

​Remember:

​Complex numbers are written in the form a + bi, where a and b are real numbers; a is the real part and bi is the imaginary part.

35

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36

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37

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38

Complex Numbers

Learning Target: I can simplify expressions with complex numbers.

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39

Adding Complex Numbers

  • When adding complex numbers

    -Add real parts together

    -Add imaginary parts together

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40

Multiple Choice

Find the Sum

3i + 2i

1

5i

2

5i2

3

6i

4

-5

41

Subtracting Complex Numbers

  • Distribute the negative

  • Add real parts together

    Add imaginary parts together

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42

Multiple Choice

Simplify:

3 + 2i + 4i + 6

1

9 + 6i

2

7i + 8

3

9 + 6i2

4

9 - 6i

43

Multiple Choice

Simplify:

4 + 7i - 3 - 2i

1

1 + 5i

2

7 + 9i

3

1 + 9i

4

-1 + 5i

44

Complete the Square

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45

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46

Find the c value by completing the square

  • b divided by 2

  • then square it

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The Quadratic Formula

a guided tour...

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Goal #1:

I can identify a, b, and c when given a quadratic equation.

51

Match

What are the values of a, b, and c for the quadratic:

x2+7x+8x^2+7x+8

a =

b =

c =

1

7

8

52

Match

What are the values of a, b, and c for the quadratic:

11  2x +17x211\ -\ 2x\ +17x^2

a =

b =

c =

17

-2

11

53

Match

What are the values of a, b, and c for the quadratic:

13x2+86x-13x^2+8-6x

a =

b =

c =

-13

-6

8

54

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Goal #2:

I can substitute a, b, and c into the quadratic formula.

55

Labelling

Drag and drop the values of a, b, and c into the quadratic formula for:

x2+14x32x^2+14x-32

tip: values without ( ) go into the formula first, values with ( ) go in second.

Drag labels to their correct position on the image

-32

(14)

(1)

14

1

56

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Goal #3:

I can simplify what is underneath the radical (called the discriminant).

57

Math Response

Simplify:

(5)24(1)(5)\sqrt[]{\left(-5\right)^2-4\left(1\right)\left(5\right)}

Type answer here
Deg°
Rad

58

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Goal #4:

I can solve for the zeroes of a function using the quadratic formula.

59

Multiple Choice

Solve using the Quadratic Formula:

3x2+7x+5-3x^2+7x+5

1

x = 7±1096x\ =\ \frac{-7\pm\sqrt[]{109}}{-6}

2

x =3±i13114x\ =\frac{3\pm i\sqrt[]{131}}{14}

3

x = 5±1096x\ =\ \frac{-5\pm\sqrt[]{109}}{-6}

60

Multiple Choice

Solve using the Quadratic Formula:

2x214x+202x^2-14x+20

1

x = {2, 5}x\ =\ \left\{2,\ 5\right\}

2

x =2±2 28128x\ =\frac{-2\pm2\ \sqrt[]{281}}{28}

3

x = 5±4 2x\ =\ -5\pm4\ \sqrt[]{2}

61

Multiple Choice

Solve using the Quadratic Formula:

x2+4x+9x^2+4x+9

1

x = 9±652x\ =\ \frac{9\pm\sqrt[]{65}}{2}

2

x =1±1458x\ =\frac{-1\pm\sqrt[]{145}}{8}

3

x = 2±i 5x\ =\ -2\pm i\ \sqrt[]{5}

Factoring GCF, Difference of Squares, and Trinomials Review

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