

Midterm Review- Algebra 2
Presentation
•
Mathematics
•
12th Grade
•
Easy
Hana Specht
Used 2+ times
FREE Resource
35 Slides • 26 Questions
1
2
Review
3
Find the GCF of the numbers (use Desmos if you need).
Find the GCF of the variables. If a variable is in EVERY term, use the one with the smallest exponent.
Write the GCF in front of parentheses.
Divide each term in the problem by the GCF (dividing the coefficients and subtracting the exponents), and write the remainder inside the parentheses.
4
Multiple Choice
Factor:
5a2−15
5(a2−15)
5a(a−15)
5(a2−3)
5a(a−3)
5
Multiple Choice
12c2−20a2
Factor:
2(6c2−10a2)
4(3c2−5a2)
2a2c2(6−10)
4(ca)2(3−5)
6
Multiple Choice
Factor the polynomial.
50x3+60x2−60
5(10x3+12x2−12)
10(5x3+6x2−6)
10x(5x3+6x2−6)
10x(5x2+6x−6)
7
Multiple Choice
Factor the polynomial.
77x9−21x7+49x5
7x5(11x4−3x2+7)
7x5(11x5−3x2+7)
7(11x9−3x7+7x5)
7x(11x8−3x6+7x4)
8
Review
9
Check to make sure you have a difference of squares! You should have two perfect squares separated by a subtraction sign.
Take the square root of each term.
Write your two factors using the rule: a2-b2 = (a+b)(a-b).
10
Multiple Choice
11
Multiple Choice
12
Multiple Choice
13
Review
14
Trinomial: ax2+bx+c
Goal: Find factors of c that add up to b.
Use the graphic organizer flow chart to figure out the signs of the numbers.
If needed, make a table of possible factors that multiply to your c value. Find the pair that add up to b.
15
Multiple Choice
k2 -2k - 24
16
Multiple Choice
17
Multiple Choice
18
Factor the GCF following the same methods as before (find the GCF of the numbers, of the variables, the divide it from each term)
If what is left in parentheses is a difference of squares, factor what is in parentheses using that method. Write the GCF in front.
If what is left in parentheses is a trinomial, factor what is in parentheses using that method. Write the GCF in front.
19
1. Factor out GCF
2. Factor remaining difference of squares
20
1. Factor out GCF
2. Factor remaining trinomial
21
Multiple Choice
125x2−5
Factor out the GCF first. Then, factor using another method.
5(3x+4)(3x−4)
5(5x+1)(5x−1)
(5x−1)2
5(25x+1)2
22
Multiple Choice
3x2 - 9x -120
23
24
Multiple Choice
2m² + 3m - 9
25
Multiple Choice
26
Multiple Choice
3v2 - 4v - 7
27
Review
28
29
30
31
32
33
34
Remember:
Complex numbers are written in the form a + bi, where a and b are real numbers; a is the real part and bi is the imaginary part.
35
36
37
38
Learning Target: I can simplify expressions with complex numbers.
39
When adding complex numbers
-Add real parts together
-Add imaginary parts together
40
Multiple Choice
Find the Sum
3i + 2i
5i
5i2
6i
-5
41
Distribute the negative
Add real parts together
Add imaginary parts together
42
Multiple Choice
Simplify:
3 + 2i + 4i + 6
9 + 6i
7i + 8
9 + 6i2
9 - 6i
43
Multiple Choice
Simplify:
4 + 7i - 3 - 2i
1 + 5i
7 + 9i
1 + 9i
-1 + 5i
44

45
46
b divided by 2
then square it
47
48
a guided tour...
49
50
I can identify a, b, and c when given a quadratic equation.
51
Match
What are the values of a, b, and c for the quadratic:
x2+7x+8
a =
b =
c =
1
7
8
1
7
8
52
Match
What are the values of a, b, and c for the quadratic:
11 − 2x +17x2
a =
b =
c =
17
-2
11
17
-2
11
53
Match
What are the values of a, b, and c for the quadratic:
−13x2+8−6x
a =
b =
c =
-13
-6
8
-13
-6
8
54
I can substitute a, b, and c into the quadratic formula.
55
Labeling
Drag and drop the values of a, b, and c into the quadratic formula for:
x2+14x−32
tip: values without ( ) go into the formula first, values with ( ) go in second.
1
(1)
(14)
-32
14
56
I can simplify what is underneath the radical (called the discriminant).
57
Math Response
Simplify:
(−5)2−4(1)(5)
58
I can solve for the zeroes of a function using the quadratic formula.
59
Multiple Choice
Solve using the Quadratic Formula:
−3x2+7x+5
x = −6−7±109
x =143±i131
x = −6−5±109
60
Multiple Choice
Solve using the Quadratic Formula:
2x2−14x+20
x = {2, 5}
x =28−2±2 281
x = −5±4 2
61
Multiple Choice
Solve using the Quadratic Formula:
x2+4x+9
x = 29±65
x =8−1±145
x = −2±i 5
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