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Lesson 28.1

Lesson 28.1

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

CCSS
6.NS.B.3, HSG.SRT.C.6, HSG.SRT.C.8

+2

Standards-aligned

Created by

Susan Budde

Used 7+ times

FREE Resource

14 Slides • 11 Questions

1

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Lesson 28.1 p. 29-30

Use sine ratio.

2

RECALL Sides of a Right Triangle

  • The HYPOTENUSE is directly across from the right angle.

  • The OPPOSITE side is directly across from the reference angle.

  • The ADJACENT side is ONE of the sides of the reference angle, but it isn't the hypotenuse.

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3

​Another TAKEAWAY from Lesson 28

4

Multiple Choice

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What is the value of x in the diagram below?

It is a 30-60-90 triangle.

1

2.52.5

2

55

3

535\sqrt{3}

4

1010

5

Multiple Select

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Consider angle B in the diagram below.

What is the length of the leg opposite angle B?

1

6

2

8

3

10

4

not possible to determine

6

Multiple Select

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Consider angle B in the diagram.

What is the length of the leg adjacent to angle B?

1

6

2

8

3

10

4

good question

7

Multiple Choice

What is the ratio for cosine?

1

Opposite LegAdjacent Leg\frac{Opposite\ Leg}{Adjacent\ Leg}

2

Opposite LegHypotenuse\frac{Opposite\ Leg}{Hypotenuse}

3

Adjacent LegHypotenuse\frac{Adjacent\ Leg}{Hypotenuse}

4

HypotenuseAdjacent Leg\frac{Hypotenuse}{Adjacent\ Leg}

8

Multiple Choice

What is the ratio for tangent?

1

Opposite LegAdjacent Leg\frac{Opposite\ Leg}{Adjacent\ Leg}

2

Opposite LegHypotenuse\frac{Opposite\ Leg}{Hypotenuse}

3

Adjacent LegHypotenuse\frac{Adjacent\ Leg}{Hypotenuse}

4

HypotenuseAdjacent Leg\frac{Hypotenuse}{Adjacent\ Leg}

9

Multiple Choice

What is the ratio for sine?

1

Opposite LegAdjacent Leg\frac{Opposite\ Leg}{Adjacent\ Leg}

2

Opposite LegHypotenuse\frac{Opposite\ Leg}{Hypotenuse}

3

Adjacent LegHypotenuse\frac{Adjacent\ Leg}{Hypotenuse}

4

HypotenuseAdjacent Leg\frac{Hypotenuse}{Adjacent\ Leg}

10

11

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Trig Functions
on a TI-84 Plus

12

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sine and inverse sine

13

Multiple Choice

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Which trig function would you use to solve for x?

1

sin40=x19\sin40=\frac{x}{19}

2

cos40=x19\cos40=\frac{x}{19}

3

tan40=x19\tan40=\frac{x}{19}

14

Multiple Choice

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Which equation could be used to solve for the unknown angle?

1

x =sin–1(25/24)

2

x = sin–1(24/25)

3

x = sin–1(25/7)

4

x = sin–1(7/25)

15

Multiple Choice

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Which equation would you use to solve for the unknown angle?

1

x=sin1(5670)x=\sin^{-1}\left(\frac{56}{70}\right)

2

x=sin1(7056)x=\sin^{-1}\left(\frac{70}{56}\right)

3

x=sin1(7042)x=\sin^{-1}\left(\frac{70}{42}\right)

4

x=sin1(4270)x=\sin^{-1}\left(\frac{42}{70}\right)

16

Multiple Choice

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Which is the correct equation for the diagram?

1

sin(θ)=2025\sin\left(\theta\right)=\frac{20}{25}  

2

cos(θ)=2025\cos\left(\theta\right)=\frac{20}{25}  

3

tan(θ)=2025\tan\left(\theta\right)=\frac{20}{25}  

4

sin(θ)=2520\sin\left(\theta\right)=\frac{25}{20}  

17

Fill in the Blanks

Type answer...

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19

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Find the missing measurements.

20

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Find the missing measurements.

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21

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Find the missing measurements.

22

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Find the missing measurements.

23

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Find the missing measurements.

24

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Find the missing measurements.

25

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Work

p. 29-30

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Lesson 28.1 p. 29-30

Use sine ratio.

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