
4.3; All Zeros of Polynomials
Presentation
•
Mathematics
•
11th Grade
•
Easy
+3
Standards-aligned
Teacher karp
Used 16+ times
FREE Resource
10 Slides • 25 Questions
1
What is i
Conjugate of a+bi is a-bi
ALL numbers are considered complex numbers as all numbers can be written in a+bi form with b = 0.
Recall
Use DeCarte's Rule of Signs to determine how many + or - real zeros AND imaginary zeros too.
Imaginary zeros MUST come in pairs.
Using Conjugate pairs & one given zero
Determine the complex zeros (this means all of the them) of a polynomial function. RECALL----------------->
Today's Goals
All Zeros of a polynomial; this includes imaginaries.
2
Multiple Choice
Recall that i=−1
Thus i2=
- 1
1
meh
Not this again
3
Multiple Choice
Determine the conjugate of 2-i
2 + i
-2 + i
- 2 - i
2 - i
4
Multiple Choice
Determine the conjugate of −3+4i
-3-4i
-3+4i
3-4i
3+4i
5
Now that we have....
...reviewed imaginary numbers with their conjugate form, lets look at how to use Decarte's beautiful Rule of Signs to determine the number of positive and negative real zeros we might have.
Then we can create a table of ALL types of zeros we might have.
6
7
Multiple Choice
Based on DeCartes' rule of signs how many positive and negative real zeros might f(x) have?
f(x)=x2+3x−18
1 positive
1 negative
0 positive
2 negative
2 positive
0 negative
0 positive
0 negative
8
Multiple Choice
One zero is given determine the other zero.
1 +2i
-1 +2i
1 - 2i
- 1 - 2i
9
Multiple Choice
(a) how many zeros?
(b) how many positive and negative real zeros?
h(x)=x3−3x2+3x−9
3 total zeros
3 positive
0 negative
3 total zeros
2 postive
1 negative
3 total zeros
1 positive
2 negative
3 total zeros
0 positive
3 negative
10
Imaginary zeros MUST come in pairs so when we multiply them out we obtain a function with real numbers. Check out this video and the table --->
Be SURE to make a chart for the next few questions.
We can list the real zeros with the imaginary zeros.
11
Multiple Choice
If you have one imaginary zero you must have...?
another; which is the conjugate of the original
no other imaginary zeros
you must have 3 more imaginary zeros
12
The next 4 slides are questions about the same polynomial function. Be sure to write it down with a chart. Keep in mind all zeros reduce by TWO
13
Dropdown
14
Dropdown
15
Multiple Choice
If the largest amount of negative real zeros is 3 the next "reduced" of negative real zeors that is possible is which choice below?
2
1
4
0
16
Dropdown
17
The next 3 slides are questions about the same polynomial function. Be sure to write it down with a chart. Keep in mind all zeros reduce by TWO
18
Dropdown
The largest number of positive real zeros is
19
Dropdown
20
Dropdown
21
Try the next one
22
Multiple Choice
If x=3i is a zero what MUST be the other zero?
x=−3i
x=3i
x=1−3i
x=1+3i
23
Using complex zeros to find depressed equation
Continued here...
NOW use long Division to obtain the "depressed" equation or other factor. First step is here. Finish this and go to the next two slides
24
Multiple Choice
Now we know that 3i and - 3i are complex zeros. What grouping below is a factor?
x2+9
x2−9
x2+3
x=1+3i
25
Multiple Choice
After finishing long division using x2+9 we get the other factor of ....
3x2−5x−2
3x2+5x+2
3x2+5x−2
−3x2+5x−2
26
Multiple Choice
Finally the "depressed" equation of 3x2+5x−2 can be further factored to the following factors.
(x−2)(3x−1)
(x+2)(3x−1)
(x−2)(3x+1)
27
Multiple Choice
of this function you can now list all of the zeros
3i, - 3i, -2, 1/3
3i, -3i, 2, 1/3
3i - 3i, -2, -1/3
28
Here comes a tougher problem. Write down the function for the next few slides
29
Multiple Choice
The listed comlex zero is - 1 +2i; what is another?
-1 - 2i
1 - 2i
- 1 +2i
1 +2i
30
Multiple Choice
Lets multiply our factors that are the imaginary zeros where
x=−1+2i & x=−1−2i
With this as our zeros add 1 to both sides and then add/subtract the imaginary portion to get the following FACTORS
(x+1−2i)(x+1+2i)
(x−1−2i)(x−1+2i)
31
Multiple Choice
Now that we have multiplied these two imaginary zeros we should have a quadratic with all real zeros.
(x+1−2i)(x+1+2i)=?
x2+2x+5
x2+2x−3
32
Multiple Choice
Take your quadratic factor (divisor) and use long division to obtain the "depressed" equation or also called quotient. BUT first factor out that x so you are actually using
h(x)=2x4+11x3+27x2+41x+15
as your dividend.
Chose the correct quotient below
2x2+7x+3
2x2−7x+3
2x2+7x−3
x2+7x−3
33
Multiple Select
Finally determine the last zeros by factoring.
2x2+7x+3
If this is not factorable use the quadratic formula to find the real irrational zeros. Choose all that are the zeros from below
x=−21
x=3
x=−3
x=21
34
Multiple Choice
In summary all zeros are....
{−3, −21, 0, −1+2i, −1−2i}
Pick the other one. ; )
35
Complex Zeros means ALL zeros; as 3 can be written as 3+0i
Imaginary zeros ALWAYS come in conjugate pairs
Decartes rule of signs is helpful to create a chart of the amount of real/imaginary zeros
When you can FACTOR
If you know one zero use division to find the depressed equation.
What else should you add to this summary?
Time for summary...
What is i
Conjugate of a+bi is a-bi
ALL numbers are considered complex numbers as all numbers can be written in a+bi form with b = 0.
Recall
Use DeCarte's Rule of Signs to determine how many + or - real zeros AND imaginary zeros too.
Imaginary zeros MUST come in pairs.
Using Conjugate pairs & one given zero
Determine the complex zeros (this means all of the them) of a polynomial function. RECALL----------------->
Today's Goals
All Zeros of a polynomial; this includes imaginaries.
Show answer
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