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4.3; All Zeros of Polynomials

4.3; All Zeros of Polynomials

Assessment

Presentation

Mathematics

11th Grade

Easy

CCSS
HSN.CN.C.9, HSN.CN.A.3, HSA.APR.D.6

+3

Standards-aligned

Created by

Teacher karp

Used 16+ times

FREE Resource

10 Slides • 25 Questions

1

  • What is i

  • Conjugate of a+bi is a-bi

  • ALL numbers are considered complex numbers as all numbers can be written in a+bi form with b = 0.

Recall

  • Use DeCarte's Rule of Signs to determine how many + or - real zeros AND imaginary zeros too.

  • Imaginary zeros MUST come in pairs.

  • Using Conjugate pairs & one given zero

  • Determine the complex zeros (this means all of the them) of a polynomial function. RECALL----------------->

Today's Goals

All Zeros of a polynomial; this includes imaginaries.

2

Multiple Choice

Recall that i=1i=\sqrt[]{-1}

Thus i2=i^2=

1

- 1

2

1

3

meh

4

Not this again

3

Multiple Choice

Determine the conjugate of 2-i

1

2 + i

2

-2 + i

3

- 2 - i

4

2 - i

4

Multiple Choice

Determine the conjugate of 3+4i-3+4i

1

-3-4i

2

-3+4i

3

3-4i

4

3+4i

5

Now that we have....

...reviewed imaginary numbers with their conjugate form, lets look at how to use Decarte's beautiful Rule of Signs to determine the number of positive and negative real zeros we might have.

Then we can create a table of ALL types of zeros we might have.

6

7

Multiple Choice

Based on DeCartes' rule of signs how many positive and negative real zeros might f(x) have?

f(x)=x2+3x18f\left(x\right)=x^2+3x-18

1

1 positive

1 negative

2

0 positive

2 negative

3

2 positive

0 negative

4

0 positive

0 negative

8

Multiple Choice

Question image

One zero is given determine the other zero.

1

1 +2i

2

-1 +2i

3

1 - 2i

4

- 1 - 2i

9

Multiple Choice

(a) how many zeros?

(b) how many positive and negative real zeros?

h(x)=x33x2+3x9h\left(x\right)=x^3-3x^2+3x-9

1

3 total zeros

3 positive

0 negative

2

3 total zeros

2 postive

1 negative

3

3 total zeros

1 positive

2 negative

4

3 total zeros

0 positive

3 negative

10

Imaginary zeros MUST come in pairs so when we multiply them out we obtain a function with real numbers. Check out this video and the table --->

Be SURE to make a chart for the next few questions.

We can list the real zeros with the imaginary zeros.

11

Multiple Choice

If you have one imaginary zero you must have...?

1

another; which is the conjugate of the original

2

no other imaginary zeros

3

you must have 3 more imaginary zeros

12

media

The next 4 slides are questions about the same polynomial function. Be sure to write it down with a chart. Keep in mind all zeros reduce by TWO

13

Dropdown

Question image
The amount of complex zeros (that means total zeros) is ​ ​

14

Dropdown

Question image
The largest amount of positive real zeros is ​
the largest amount of negative real zeros is​
thus the amount of imaginary zeros is​

15

Multiple Choice

Question image

If the largest amount of negative real zeros is 3 the next "reduced" of negative real zeors that is possible is which choice below?

1

2

2

1

3

4

4

0

16

Dropdown

Question image
If the amount of NEGATIVE real zeros is 1, then the amount of positive real zeros REMAINS ​
and the amount of imaginary zeros must be​

17

media

The next 3 slides are questions about the same polynomial function. Be sure to write it down with a chart. Keep in mind all zeros reduce by TWO

18

Dropdown

Question image
The total amount of complex zeros is ​ ​


The largest number of positive real zeros is ​
also ​
is the number of negative real zeros with these two outcomes ​ there ​
imaginary zeros

19

Dropdown

Question image
If there are 2 positive real zeros then there must still be ​
negative real zero and ​
imaginary zeros

20

Dropdown

Question image
Finally ​
the least amount of positive real zeros,​
MUST be the amount of negative real zeros and ​
would be the number of imaginary zeros.

21

Try the next one

media

22

Multiple Choice

Question image

If x=3ix=3i is a zero what MUST be the other zero?

1

x=3ix=-3i

2

x=3ix=3i

3

x=13ix=1-3i

4

x=1+3ix=1+3i

23

Using complex zeros to find depressed equation

Continued here...

NOW use long Division to obtain the "depressed" equation or other factor. First step is here. Finish this and go to the next two slides


media

24

Multiple Choice

Question image

Now we know that 3i and - 3i are complex zeros. What grouping below is a factor?

1

x2+9x^2+9

2

x29x^2-9

3

x2+3x^2+3

4

x=1+3ix=1+3i

25

Multiple Choice

After finishing long division using x2+9 x^2+9\ we get the other factor of ....

1

3x25x23x^2-5x-2

2

3x2+5x+23x^2+5x+2

3

3x2+5x23x^2+5x-2

4

3x2+5x2-3x^2+5x-2

26

Multiple Choice

Finally the "depressed" equation of 3x2+5x23x^2+5x-2 can be further factored to the following factors.

1

(x2)(3x1)\left(x-2\right)\left(3x-1\right)

2

(x+2)(3x1)\left(x+2\right)\left(3x-1\right)

3

(x2)(3x+1)\left(x-2\right)\left(3x+1\right)

27

Multiple Choice

Question image

of this function you can now list all of the zeros

1

3i, - 3i, -2, 1/3

2

3i, -3i, 2, 1/3

3

3i - 3i, -2, -1/3

28

Here comes a tougher problem. Write down the function for the next few slides

29

Multiple Choice

Question image

The listed comlex zero is - 1 +2i; what is another?

1

-1 - 2i

2

1 - 2i

3

- 1 +2i

4

1 +2i

30

Multiple Choice

Question image

Lets multiply our factors that are the imaginary zeros where

x=1+2i & x=12ix=-1+2i\ \&\ x=-1-2i

With this as our zeros add 1 to both sides and then add/subtract the imaginary portion to get the following FACTORS

1

(x+12i)(x+1+2i)\left(x+1-2i\right)\left(x+1+2i\right)

2

(x12i)(x1+2i)\left(x-1-2i\right)\left(x-1+2i\right)

31

Multiple Choice

Question image

Now that we have multiplied these two imaginary zeros we should have a quadratic with all real zeros.

(x+12i)(x+1+2i)=?\left(x+1-2i\right)\left(x+1+2i\right)=?

1

x2+2x+5x^2+2x+5

2

x2+2x3x^2+2x-3

32

Multiple Choice

Question image

Take your quadratic factor (divisor) and use long division to obtain the "depressed" equation or also called quotient. BUT first factor out that x so you are actually using

h(x)=2x4+11x3+27x2+41x+15h\left(x\right)=2x^4+11x^3+27x^2+41x+15

as your dividend.

Chose the correct quotient below

1

2x2+7x+32x^2+7x+3

2

2x27x+32x^2-7x+3

3

2x2+7x32x^2+7x-3

4

x2+7x3x^2+7x-3

33

Multiple Select

Question image

Finally determine the last zeros by factoring.

2x2+7x+32x^2+7x+3

If this is not factorable use the quadratic formula to find the real irrational zeros. Choose all that are the zeros from below

1

x=12x=-\frac{1}{2}

2

x=3x=3

3

x=3x=-3

4

x=12x=\frac{1}{2}

34

Multiple Choice

Question image

In summary all zeros are....

1

{3, 12, 0, 1+2i, 12i}\left\{-3,\ -\frac{1}{2},\ 0,\ -1+2i,\ -1-2i\right\}

2

Pick the other one. ; )

35

  1. Complex Zeros means ALL zeros; as 3 can be written as 3+0i

  2. Imaginary zeros ALWAYS come in conjugate pairs

  3. Decartes rule of signs is helpful to create a chart of the amount of real/imaginary zeros

  4. When you can FACTOR

  5. If you know one zero use division to find the depressed equation.

  6. What else should you add to this summary?

Time for summary...

media
  • What is i

  • Conjugate of a+bi is a-bi

  • ALL numbers are considered complex numbers as all numbers can be written in a+bi form with b = 0.

Recall

  • Use DeCarte's Rule of Signs to determine how many + or - real zeros AND imaginary zeros too.

  • Imaginary zeros MUST come in pairs.

  • Using Conjugate pairs & one given zero

  • Determine the complex zeros (this means all of the them) of a polynomial function. RECALL----------------->

Today's Goals

All Zeros of a polynomial; this includes imaginaries.

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