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Bank soal limit tak hingga fungsi aljabar dan trigonometri

Bank soal limit tak hingga fungsi aljabar dan trigonometri

Assessment

Presentation

•

Mathematics

•

12th Grade

•

Hard

Created by

Kartika Dewi

FREE Resource

9 Slides • 73 Questions

1

LIMIT DI TAKHINGGAAN
BAGIAN 2

by Risna Fauzi

2

Multiple Choice

lim⁡y→∞ y sin⁡ 3y cos⁡ 5y=....\lim_{y\rightarrow\infty}\ y\ \sin\ \frac{3}{y}\ \cos\ \frac{5}{y}=....  

1

0

2

1

3

2

4

3

5

4

3

media

​Ubah sehingga dpt diselesaikan dg

sifat-sifat limit sin cos tan.

​Dst

4

Multiple Choice

Hasil dari lim⁡x→∞cot⁡(3x)sin⁡(1x) adalah....Hasil\ dari\ \lim_{x\rightarrow\infty}\cot\left(\frac{3}{x}\right)\sin\left(\frac{1}{x}\right)\ adalah....  

(penyelesaiannya serupa dengan soal sebelumnya)

1

1

2

12\frac{1}{2}  

3

13\frac{1}{3}  

4

14\frac{1}{4}  

5

15\frac{1}{5}  

5

media

6

Multiple Choice

Nilai dari lim⁡x→∞ (9x2+x−7−9x2−8x+5)\lim_{x\rightarrow\infty}\ \left(\sqrt{9x^2+x-7}-\sqrt{9x^2-8x+5}\right)  adalah...

1

-1

2

0

3

23\frac{2}{3}  

4

32\frac{3}{2}  

5

3

7

Multiple Choice

Nilai dari lim⁡x→∞ (2x2−5x+1−x2−9)\lim_{x\rightarrow\infty}\ \left(\sqrt{2x^2-5x+1}-\sqrt{x^2-9}\right) adalah... 

1

−∞-\infty  

2

-1

3

0

4

1

5

∞\infty  

8

Multiple Choice

Jumlah penduduk di desa Majusari t tahun dari sekarang ditaksir dan bisa dinyatakan oleh fungsi N=f(t)=40000+10000(t+2)2N=f\left(t\right)=40000+\frac{10000}{\left(t+2\right)^2} . Berapa perkiraan jumlah penduduk di desa Majusari dalam jangka waktu sangat lama di masa depan? 

1

10000 jiwa

2

20000 jiwa

3

30000 jiwa

4

40000 jiwa

5

50000 jiwa

9

Multiple Choice

Nilai dari lim⁡x→∞ (2x2−5x+1−x2−9)\lim_{x\rightarrow\infty}\ \left(\sqrt{2x^2-5x+1}-\sqrt{x^2-9}\right) adalah... 

1

−∞-\infty  

2

-1

3

0

4

1

5

∞\infty  

10

Multiple Choice

Nilai dari lim⁡x→∞ (4x2−9−4x2−x+6)\lim_{x\rightarrow\infty}\ \left(\sqrt{4x^2-9}-\sqrt{4x^2-x+6}\right) adalah... 

1

-2

2

−14-\frac{1}{4}  

3

0

4

14\frac{1}{4}  

5

2

11

Multiple Choice

Jumlah penduduk di desa Majusari t tahun dari sekarang ditaksir dan bisa dinyatakan oleh fungsi N=f(t)=40000+10000(t+2)2N=f\left(t\right)=40000+\frac{10000}{\left(t+2\right)^2} . Berapa perkiraan jumlah penduduk di desa Majusari dalam jangka waktu sangat lama di masa depan? 

1

10000 jiwa

2

20000 jiwa

3

30000 jiwa

4

40000 jiwa

5

50000 jiwa

12

Multiple Choice

lim⁡x→∞ (4sin⁡x−2x5x)=....\lim_{x\rightarrow\infty}\ \left(\frac{4\sin x-2x}{5x}\right)=....  

1

−35-\frac{3}{5}  

2

−85-\frac{8}{5}  

3

−25-\frac{2}{5}  

4

25\frac{2}{5}  

5

45\frac{4}{5}  

13

Multiple Choice

lim⁡x→∞x2(1−cos⁡ 2x)=....\lim_{x\rightarrow\infty}x^2\left(1-\cos\ \frac{2}{x}\right)=....  

1

2

2

−2-2  

3

0

4

∞\infty  

5

−∞-\infty  

14

Multiple Choice

lim⁡x→∞ x sec⁡ 1x (1−cos⁡ 1x)=...\lim_{x\rightarrow\infty}\ x\ \sec\ \frac{1}{x}\ \left(1-\cos\ \frac{1}{\sqrt{x}}\right)=...  

1

12\frac{1}{2}  

2

13\frac{1}{3}  

3

14\frac{1}{4}  

4

15\frac{1}{5}  

5

16\frac{1}{6}  

15

Multiple Choice

Nilai dari:
lim⁡x→∞ cos⁡ 1xx tan⁡ 2x=....\lim_{x\rightarrow\infty}\ \frac{\cos\ \frac{1}{x}}{x\ \tan\ \frac{2}{x}}=....

1

0,5

2

2

3

0

4

1

5

4

16

Multiple Choice

lim⁡x→∞ 2x sin⁡(5x)=....\lim_{x\rightarrow\infty}\ \frac{2x\ }{\sin\left(\frac{5}{x}\right)}=....  

1

25\frac{2}{5}  

2

∞\infty  

3

0

4

15\frac{1}{5}  

5

5

17

Multiple Choice

Nilai dari: lim⁡x→∞  5 sin⁡ 3xtan⁡ 43x=....\lim_{x\rightarrow\infty\ }\ 5\ \frac{\sin\ \frac{3}{x}}{\tan\ \frac{4}{3x}}=....  


1

274\frac{27}{4}  

2

154\frac{15}{4}  

3

1512\frac{15}{12}  

4

454\frac{45}{4}  

5

12

18

Multiple Choice

lim⁡x→∞  9 sin⁡2 6xsin⁡ 4x tan⁡3x=....\lim_{x\rightarrow\infty\ }\ \frac{9\ \sin^2\ \frac{6}{x}}{\sin\ \frac{4}{x}\ \tan\frac{3}{x}}=....

1

9

2

18

3

27

4

92\frac{9}{2}  

5

96\frac{9}{6}  

19

Multiple Choice

Nilai dari:
lim⁡x→∞ tan⁡ 5x. cosec⁡ 3x=....\lim_{x\rightarrow\infty\ }\tan\ \frac{5}{x}.\ \operatorname{cosec}\ \frac{3}{x}=....  

1

1

2

5

3

3

4

53\frac{5}{3}  

5

35\frac{3}{5}  

20

Multiple Choice

Nilai dari:
lim⁡x→∞ x2(1−cos⁡ 2x)=...\lim_{x\rightarrow\infty\ }x^2\left(1-\cos\ \frac{2}{x}\right)=...  

1

-1

2

0

3

1

4

2

5

∞\infty  

21

Multiple Choice

lim⁡x→∞3 sin⁡ 3xtan⁡ 43x= ....\lim_{x\rightarrow\infty}3\ \frac{\sin\ \frac{3}{x}}{\tan\ \frac{4}{3x}}=\ ....  

1

9

2

274\frac{27}{4}  

3

912\frac{9}{12}

4

4

5

129\frac{12}{9}  

22

Multiple Choice

lim⁡x→∞ sin⁡2(2x)tan⁡2(3x)=\lim_{x\rightarrow\infty}\ \frac{\sin^2\left(\frac{2}{x}\right)}{\tan^2\left(\frac{3}{x}\right)}=  ... .



1

23\frac{2}{3}  

2

32\frac{3}{2}  

3

49\frac{4}{9}  

4

94\frac{9}{4}  

5

11  

23

Multiple Choice

Selesaikan lim⁡x→∞tan⁡−1x=\lim_{x\rightarrow\infty}\tan^{-1}x=  ...

1

−π2-\frac{\pi}{2}  

2

π2\frac{\pi}{2}  

3

−∞-\infty  

4

∞\infty  

24

Multiple Choice

Selesaikan lim⁡t→01−cos⁡tsin⁡t=...\lim_{t\rightarrow0}\frac{1-\cos t}{\sin t}=...  

1

0

2

1

3

∞\infty  

4

sin⁡t\sin t  

25

Multiple Choice

Selesaikan lim⁡t→01−cos⁡tt=\lim_{t\rightarrow0}\frac{1-\cos t}{t}=  ...

1

0

2

1

3

∞\infty  

4

cos⁡t\cos t  

26

Multiple Choice

Jika lim⁡x→∞f(x)=6\lim_{x\rightarrow\infty}f\left(x\right)=6 maka garis ..... merupakan asimtot .... dari grafik  y=f(x)y=f\left(x\right)  .

1

x=∞x=\infty  , horizontal

2

x=∞x=\infty  , vertikal

3

y=6y=6  , horizontal

4

y=6y=6  , vertikal

27

Multiple Choice

Jika garis y=Ly=L  merupakan asimtot horizontal dari  y=f(x)y=f\left(x\right) , maka...

1

lim⁡x→∞f(x)=L\lim_{x\rightarrow\infty}f\left(x\right)=L  

2

lim⁡x→∞f(x)=−L\lim_{x\rightarrow\infty}f\left(x\right)=-L  

3

lim⁡x→Lf(x)=∞\lim_{x\rightarrow L}f\left(x\right)=\infty  

4

lim⁡x→−Lf(x)=−∞\lim_{x\rightarrow-L}f\left(x\right)=-\infty  

28

Multiple Choice

 Jika r > 0 merupakan bilangan rasional sedemikian hingga xrx^r  terdefinisi untuk seluruh x, maka  lim⁡x→−∞1xr=\lim_{x\rightarrow-\infty}\frac{1}{x^r}= ...

1

0

2

1

3

−∞-\infty  

4

∞\infty  

29

Multiple Choice

Nilai dari lim⁡x→∞3 sin⁡ 3xtan⁡ 43x= ....\lim_{x\rightarrow\infty}3\ \frac{\sin\ \frac{3}{x}}{\tan\ \frac{4}{3x}}=\ ....  

1

9

2

274\frac{27}{4}  

3

912\frac{9}{12}

4

4

30

 Kita akan membahas bentukyg kedua yaitu berbentuk fungsi irrasional (akar)​

 

media

31

Multiple Choice

Nilai dari lim⁡x→∞4x sin⁡ (35x)=....\lim_{x\rightarrow\infty}4x\ \sin\ \left(\frac{3}{5x}\right)=....  

1

35\frac{3}{5}  

2

1220\frac{12}{20}  

3

125\frac{12}{5}  

4

45\frac{4}{5}  

32

Multiple Choice

lim⁡x→∞ tan⁡5x . cosec⁡3x=\lim_{x\rightarrow\infty}\ \tan\frac{5}{x}\ .\ \operatorname{cosec}\frac{3}{x}=  ... .



1

11  

2

33  

3

55  

4

35\frac{3}{5}  

5

53\frac{5}{3}  

33

Multiple Choice

Nilai dari lim⁡x→∞ cot⁡ (12x)csc⁡ (3x)=....\lim_{x\rightarrow\infty}\ \frac{\cot\ \left(\frac{1}{2x}\right)}{\csc\ \left(\frac{3}{x}\right)}=....  

1

1,5

2

3

3

6

4

12\frac{1}{2}  

34

Multiple Choice

lim⁡x→∞4x sin⁡ (35x)=....\lim_{x\rightarrow\infty}4x\ \sin\ \left(\frac{3}{5x}\right)=....  

1

35\frac{3}{5}  

2

1220\frac{12}{20}  

3

125\frac{12}{5}  

4

320\frac{3}{20}  

5

45\frac{4}{5}  

35

Multiple Choice

Nilai dari lim⁡x→∞ sin⁡ (3x)x2 (1−cos⁡ 2x) sin⁡ (1x) =...\lim_{x\rightarrow\infty}\ \frac{\sin\ \left(\frac{3}{x}\right)}{x^2\ \left(1-\cos\ \frac{2}{x}\right)\ \sin\ \left(\frac{1}{x}\right)}\ =...  

1

12\frac{1}{2}  

2

11  

3

32\frac{3}{2}  

4

22  

36

Multiple Choice

lim⁡x→∞ cos⁡1x xtan⁡2x=\lim_{x\rightarrow\infty}\ \frac{\cos\frac{1}{x}\ }{x\tan\frac{2}{x}}=  ... .

1

12\frac{1}{2}  

2

11  

3

22  

4

44  

5

00  

37

Multiple Choice

Nilai dari lim⁡x→∞x2(1−cos⁡ 2x)=....\lim_{x\rightarrow\infty}x^2\left(1-\cos\ \frac{2}{x}\right)=....  

1

2

2

−2-2  

3

0

4

∞\infty  

38

media
​Contoh 1

39

Multiple Choice

Nilai dari lim⁡x→∞ 3sin⁡26xsin⁡4xtan⁡ 3x\lim_{x\rightarrow\infty}\ \frac{3\sin^2\frac{6}{x}}{\sin\frac{4}{x}\tan\ \frac{3}{x}} adalah ... 

1

9

2

3

3

92\frac{9}{2}  

4

12\frac{1}{2}  

40

Multiple Choice

lim⁡x→∞4x sin⁡ (35x)=....\lim_{x\rightarrow\infty}4x\ \sin\ \left(\frac{3}{5x}\right)=....  

1

35\frac{3}{5}  

2

1220\frac{12}{20}  

3

125\frac{12}{5}  

4

320\frac{3}{20}  

5

45\frac{4}{5}  

41

Multiple Choice

Nilai dari lim⁡x→∞ tan⁡5x . cosec⁡3x=\lim_{x\rightarrow\infty}\ \tan\frac{5}{x}\ .\ \operatorname{cosec}\frac{3}{x}= ...


1

11  

2

55  

3

35\frac{3}{5}  

4

53\frac{5}{3}  

42

Multiple Choice

Nilai dari lim⁡x→∞ 2x2tan⁡(1x)−xsin⁡(1x)+1xxcos⁡(2x)= ....\lim_{x\rightarrow\infty}\ \frac{2x^2\tan\left(\frac{1}{x}\right)-x\sin\left(\frac{1}{x}\right)+\frac{1}{x}}{x\cos\left(\frac{2}{x}\right)}=\ ....  

1

−1-1  

2

2

3

1

4

0

43

Multiple Choice

lim⁡x→∞ 2x cot⁡ 2x−3cot⁡ 2x5x2−2x=....\lim_{x\rightarrow\infty}\ \frac{2x\ \cot\ \frac{2}{x}-3\cot\ \frac{2}{x}}{5x^2-2x}=....  

1

0

2

25\frac{2}{5}  

3

15\frac{1}{5}  

4

52\frac{5}{2}  

5

210\frac{2}{10}  

44

Multiple Choice

Nilai dari lim⁡x→∞sin⁡ (1x−4π3)\lim_{x\rightarrow\infty}\sin\ \left(\frac{1}{x}-\frac{4\pi}{3}\right) adalah ...

1

−122-\frac{1}{2}\sqrt[]{2}

2

−12-\frac{1}{2}

3

12\frac{1}{2}

4

122\frac{1}{2}\sqrt[]{2}

45

​Contoh 2
media

46

Multiple Choice

Nilai dari lim⁡y→∞6y cos⁡ 3ysin⁡ 5y\lim_{y\rightarrow\infty}\sqrt[]{6y}\ \cos\ \frac{3}{\sqrt[]{y}}\sin\ \frac{5}{\sqrt[]{y}} adalah ...

1

262\sqrt[]{6}

2

363\sqrt[]{6}

3

565\sqrt[]{6}

4

15

47

Multiple Choice

lim⁡x→∞3 sin⁡ 3xtan⁡ 43x= ....\lim_{x\rightarrow\infty}3\ \frac{\sin\ \frac{3}{x}}{\tan\ \frac{4}{3x}}=\ ....  

1

9

2

274\frac{27}{4}  

3

912\frac{9}{12}

4

4

5

129\frac{12}{9}  

48

Multiple Choice

Nilai dari lim⁡x→∞2x2(1−cos⁡ 6x)\lim_{x\rightarrow\infty}2x^2\left(1-\cos\ \frac{6}{x}\right) adalah ...

1

6

2

12

3

24

4

36

49

Multiple Choice

lim⁡x→∼ sin⁡ (3x)x2 (1−cos⁡ 2x) sin⁡ (1x) =...\lim_{x\rightarrow\sim}\ \frac{\sin\ \left(\frac{3}{x}\right)}{x^2\ \left(1-\cos\ \frac{2}{x}\right)\ \sin\ \left(\frac{1}{x}\right)}\ =...  

1

12\frac{1}{2}  

2

11  

3

32\frac{3}{2}  

4

22  

5

52\frac{5}{2}  

50

Multiple Choice

Nilai dari lim⁡x→∞sin⁡2 1x+2 sin⁡ 1x−8\lim_{x\rightarrow\infty}\sin^2\ \frac{1}{x}+2\ \sin\ \frac{1}{x}-8 adalah ...

1

-8

2

-6

3

0

4

6

51

Multiple Choice

lim⁡x→∼ sin⁡3 (2x)tan⁡3 (12x)=....\lim_{x\rightarrow\sim}\ \frac{\sin^3\ \left(\frac{2}{x}\right)}{\tan^3\ \left(\frac{1}{2x}\right)}=....  

1

272^7  

2

262^6  

3

252^5  

4

242^4  

5

232^3  

52

Multiple Choice

Nilai dari lim⁡x→∞2x tan⁡ 1x sec⁡ 2x\lim_{x\rightarrow\infty}2x\ \tan\ \frac{1}{x}\ \sec\ \frac{2}{x} adalah ...

1

1

2

2

3

3

4

4

53

​Contoh 3
media

​ralat lagi, bukan p tetapi q

54

Multiple Choice

Nilai dari lim⁡x→∞ 1−cos⁡ 4x1xtan⁡ 3x\lim_{x\rightarrow\infty}\ \frac{1-\cos\ \frac{4}{x}}{\frac{1}{x}\tan\ \frac{3}{x}} adalah ...

1

23\frac{2}{3}

2

43\frac{4}{3}

3

83\frac{8}{3}

4

3 113\frac{11}{3}

55

Multiple Choice

Nilai

lim⁡x→∞ 3sin⁡26xsin⁡4xtan⁡ 3x\lim_{x\rightarrow\infty}\ \frac{3\sin^2\frac{6}{x}}{\sin\frac{4}{x}\tan\ \frac{3}{x}}  

1

9

2

3

3

92\frac{9}{2}  

4

3x\frac{3}{x}  

5

12\frac{1}{2}  

56

Multiple Choice

Nilai dari lim⁡x→∞ csc⁡1xx\lim_{x\rightarrow\infty}\ \frac{\csc\frac{1}{x}}{x} adalah ...

1

1

2

2

3

3

4

4

57

Multiple Choice

lim⁡x→∼ x sec⁡ 1x (1−cos⁡ 1x)=...\lim_{x\rightarrow\sim}\ x\ \sec\ \frac{1}{x}\ \left(1-\cos\ \frac{1}{\sqrt{x}}\right)=...  

1

12\frac{1}{2}  

2

13\frac{1}{3}  

3

14\frac{1}{4}  

4

15\frac{1}{5}  

5

16\frac{1}{6}  

58

Multiple Choice

lim⁡x→∞ tan⁡5x . cosec⁡3x=\lim_{x\rightarrow\infty}\ \tan\frac{5}{x}\ .\ \operatorname{cosec}\frac{3}{x}=  ... .



1

11  

2

33  

3

55  

4

35\frac{3}{5}  

5

53\frac{5}{3}  

59

Multiple Choice

lim⁡x→∞ ((2x−5)(2x+1)−(2x−5))=...\lim_{x\rightarrow\infty}\ \left(\sqrt{\left(2x-5\right)\left(2x+1\right)}-\left(2x-5\right)\right)=...  

1

3\sqrt{3}  

2

−3-3  

3

3

4

13\frac{1}{3}  

5

−13-\frac{1}{3}  

60

Multiple Choice

Nilai

lim⁡x→∞ 3sin⁡26xsin⁡4xtan⁡ 3x\lim_{x\rightarrow\infty}\ \frac{3\sin^2\frac{6}{x}}{\sin\frac{4}{x}\tan\ \frac{3}{x}}  

1

9

2

3

3

92\frac{9}{2}  

4

3x\frac{3}{x}  

5

12\frac{1}{2}  

61

Multiple Choice

lim⁡x→∞ 1−2x+2x3x3+x+1= ...\lim_{x\rightarrow\infty}\ \frac{1-2x+2x^3}{x^3+x+1}=\ ...  

1

- 4

2

- 2

3

1

4

2

5

∞\infty  

62

​bentuk ini harus di ubah ke bentuk umum dulu

​menjadi

​karena a = p yaitu 4 maka hasilnya:

63

Multiple Choice

Nilai dari lim⁡x→∞(x2+7x+5−x2−2x+3)\lim_{x\rightarrow\infty}\left(\sqrt{x^2+7x+5}-\sqrt{x^2-2x+3}\right)  adalah ....

1

8 128\ \frac{1}{2}  

2

7 127\ \frac{1}{2}  

3

6 126\ \frac{1}{2}  

4

5 125\ \frac{1}{2}  

5

4 124\ \frac{1}{2}  

64

Multiple Choice

lim⁡x→∞ {x2+x−x2−3x+1}=...\lim_{x\rightarrow\infty}\ \left\{\sqrt{x^2+x}-\sqrt{x^2-3x+1}\right\}=...  

1

00  

2

11  

3

22  

4

−2-2  

5

∞\infty  

65

Multiple Choice

Nilai dari lim⁡x→∞x2−4x+3−x+1Nilai\ dari\ \lim_{x\rightarrow\infty}\sqrt{x^2-4x+3}-x+1  

1

-6

2

-2

3

0

4

-1

5

6

66

​ingat

​a = 1, p = 1

​b = 1, q = -3

​c = 0, r = 1

​karena a = p maka hasilnya

67

Multiple Choice

lim⁡x→∞3 sin⁡ 3xtan⁡ 43x= ....\lim_{x\rightarrow\infty}3\ \frac{\sin\ \frac{3}{x}}{\tan\ \frac{4}{3x}}=\ ....  

1

9

2

274\frac{27}{4}  

3

912\frac{9}{12}

4

4

5

129\frac{12}{9}  

68

Multiple Choice

lim⁡x→∞{x2−4x+5−4x2−x+3}=....\lim_{x\rightarrow\infty}\left\{\sqrt{x^2-4x+5}-\sqrt{4x^2-x+3}\right\}=....  

1

0

2

12\frac{1}{2}  

3

2

4

∞\infty  

5

−∞-\infty  

69

Multiple Choice

lim⁡x→∞4x sin⁡ (35x)=....\lim_{x\rightarrow\infty}4x\ \sin\ \left(\frac{3}{5x}\right)=....  

1

35\frac{3}{5}  

2

1220\frac{12}{20}  

3

125\frac{12}{5}  

4

320\frac{3}{20}  

5

45\frac{4}{5}  

70

Multiple Choice

lim⁡x→∞ ((2x−1)−2x2−6x−5)=...\lim_{x\rightarrow\infty}\ \left(\left(2x-1\right)-\sqrt{2x^2-6x-5}\right)=...  

1

11  

2

22  

3

44  

4

∞\infty  

5

−∞-\infty  

71

Multiple Choice

lim⁡x→∞(3x−2x+5−2−xx+5)=....\lim_{x\rightarrow\infty}\left(\frac{3x-2}{x+5}-\frac{2-x}{x+5}\right)=....  

1

4

2

1

3

2

4

3

5

∞\infty  

72

Multiple Choice

lim⁡x→∼ { ax2+bx+c−px2+qx+r}=\lim_{x\rightarrow\sim}\ \left\{\ \sqrt{ax^2+bx+c}-\sqrt{px^2+qx+r}\right\}= dengan  a=pa=p   

1

b−ap−q\frac{b-a}{p-q}  

2

b−q2a\frac{b-q}{2\sqrt{a}}  

3

b−q2a\frac{b-q}{2a}  

4

2a2\sqrt{a}  

5

b−qb-q  

73

Multiple Choice

Nilai dari lim⁡x→∞(10x22x−1−5x) = ....\lim_{x\rightarrow\infty}\left(\frac{10x^2}{2x-1}-5x\right)\ =\ ....  

1

-10

2

−52-\frac{5}{2}  

3

52\frac{5}{2}  

4

5

5

10

74

Multiple Choice

lim⁡x→∞{ (3x−2)−9x2−2x+5}=...\lim_{x\rightarrow\infty}\left\{\ \left(3x-2\right)-\sqrt{9x^2-2x+5}\right\}=...  

1

00  

2

13\frac{1}{3}  

3

−1-1  

4

−43-\frac{4}{3}  

5

−53-\frac{5}{3}  

75

Multiple Choice

Nilai dari:
lim⁡x→∞ cos⁡ 1xx tan⁡ 2x=....\lim_{x\rightarrow\infty}\ \frac{\cos\ \frac{1}{x}}{x\ \tan\ \frac{2}{x}}=....

1

0,5

2

2

3

0

4

1

5

4

76

Multiple Choice

lim⁡x→∞2x sin⁡ 45x=....\lim_{x\rightarrow\infty}2x\ \sin\ \frac{4}{5x}=....  

1

4/10

2

8/5

3

10/4

4

5

5

8

77

Multiple Choice

Nilai dari:
lim⁡x→∞ tan⁡ 5x. cosec⁡ 3x=....\lim_{x\rightarrow\infty\ }\tan\ \frac{5}{x}.\ \operatorname{cosec}\ \frac{3}{x}=....  

1

1

2

5

3

3

4

53\frac{5}{3}  

5

35\frac{3}{5}  

78

Multiple Choice

Nilai dari:
lim⁡y→∞ y sin⁡8y cos⁡ 5y=...\lim_{y\rightarrow\infty\ }y\ \sin\frac{8}{y}\ \cos\ \frac{5}{y}=...  

1

8

2

4

3

2

4

1

5

18\frac{1}{8}  

79

Multiple Choice

Nilai dari:
lim⁡x→∞ cos⁡ 1xx tan⁡ 2x=....\lim_{x\rightarrow\infty}\ \frac{\cos\ \frac{1}{x}}{x\ \tan\ \frac{2}{x}}=....

1

0,5

2

2

3

0

4

1

5

4

80

Multiple Choice

lim⁡x→∞ 2x sin⁡(5x)=....\lim_{x\rightarrow\infty}\ \frac{2x\ }{\sin\left(\frac{5}{x}\right)}=....  

1

25\frac{2}{5}  

2

∞\infty  

3

0

4

15\frac{1}{5}  

5

5

81

Multiple Choice

lim⁡x→∞  9 sin⁡2 6xsin⁡ 4x tan⁡3x=....\lim_{x\rightarrow\infty\ }\ \frac{9\ \sin^2\ \frac{6}{x}}{\sin\ \frac{4}{x}\ \tan\frac{3}{x}}=....

1

9

2

18

3

27

4

92\frac{9}{2}  

5

96\frac{9}{6}  

82

Multiple Choice

Nilai dari:
lim⁡x→∞ tan⁡ 5x. cosec⁡ 3x=....\lim_{x\rightarrow\infty\ }\tan\ \frac{5}{x}.\ \operatorname{cosec}\ \frac{3}{x}=....  

1

1

2

5

3

3

4

53\frac{5}{3}  

5

35\frac{3}{5}  

pattern-tertiary
LIMIT DI TAKHINGGAAN
BAGIAN 2

by Risna Fauzi

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