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The chain rule part 2

The chain rule part 2

Assessment

Presentation

•

Mathematics

•

12th Grade

•

Medium

Created by

Sahel Otoom

Used 22+ times

FREE Resource

5 Slides • 8 Questions

1

media

2

Match

Warm Up

Match the following

ddx(200)=\frac{d}{dx}\left(200\right)=  

ddx(200x)=\frac{d}{dx}\left(200x\right)=  

ddx(x200)=\frac{d}{dx}\left(x^{200}\right)=  

ddx(1200x200)=\frac{d}{dx}\left(\frac{1}{200}x^{200}\right)=  

ddx(200x2+200x)=\frac{d}{dx}\left(200x^2+200x\right)=  

0

200

200x199

x199

400x+200

3

Objectives 1.Recall the general power rule and chain rule.
2. Apply the chain rule to real-life UAE-based models (e.g., population, temperature functions).




4

media

5

Match

Match the following

ddx(20)=\frac{d}{dx}\left(20\right)=  

ddx(20x)=\frac{d}{dx}\left(20x\right)=  

ddx(x20)=\frac{d}{dx}\left(x^{20}\right)=  

ddx(120x20)=\frac{d}{dx}\left(\frac{1}{20}x^{20}\right)=  

ddx(20x2+20x)=\frac{d}{dx}\left(20x^2+20x\right)=  

0

20

20x19

x19

40x+20

6

media

7

Match

Match the following

ddx(cos⁡x)\frac{d}{dx}\left(\cos x\right)

ddx(tan⁡x)\frac{d}{dx}\left(\tan x\right)

ddx(sec⁡x)\frac{d}{dx}\left(\sec x\right)

ddx(sin⁡x)\frac{d}{dx}\left(\sin x\right)

ddx(cot⁡x)\frac{d}{dx}\left(\cot x\right)

- sin x

sec2x

secx tanx

cos x

-csc2x

8

media

9

Multiple Choice

find g′(x) for g(x)=(h(x))3find\ g'\left(x\right)\ for\ g\left(x\right)=\left(h\left(x\right)\right)^3  

1

g′(x)=3(h′(x))2g'\left(x\right)=3\left(h'\left(x\right)\right)^2  

2

g′(x)=3h′(x)2g'\left(x\right)=3h'\left(x\right)^2  

3

g′(x)=3(h(x))2⋅h′(x)g'\left(x\right)=3\left(h\left(x\right)\right)^2\cdot h'\left(x\right)  

4

g′(x)=3h(x)2⋅h′(x)g'\left(x\right)=3h\left(x\right)^2\cdot h'\left(x\right)  

10

Multiple Choice

Find drdθ if r=(sec⁡θ+tan⁡θ)−3\frac{dr}{d\theta}\ if\ r=\left(\sec\theta+\tan\theta\right)^{-3}  

1

−3(sec⁡θ+tan⁡θ)−4⋅sec⁡θ-3\left(\sec\theta+\tan\theta\right)^{-4}\cdot\sec\theta  

2

−3(sec⁡θ+tan⁡θ)−4(sec⁡θtan⁡θ+sec⁡2θ)-3\left(\sec\theta+\tan\theta\right)^{-4}\left(\sec\theta\tan\theta+\sec^2\theta\right)  

3

−3(sec⁡θ+tan⁡θ)−4-3\left(\sec\theta+\tan\theta\right)^{-4}  

4

−3(sec⁡θtan⁡θ+sec⁡2θ)−4-3\left(\sec\theta\tan\theta+\sec^2\theta\right)^{-4}  

11

Multiple Choice

ddxtan⁡2(3x)\frac{\text{d}}{\text{d}x}\tan^2\left(3x\right)  

1

2tan⁡(3x)sec⁡2(x)⋅32\tan\left(3x\right)\sec^2\left(x\right)\cdot3  

2

2tan⁡(3x)sec⁡2(3x)⋅32\tan\left(3x\right)\sec^2\left(3x\right)\cdot3  

3

2sec⁡2(3x)2\sec^2\left(3x\right)  

4

2sec⁡2(3x)⋅32\sec^2\left(3x\right)\cdot3  

12

Multiple Choice

Given the function y=5x−7y=\sqrt{5x-7}  find  dxdy\frac{\text{d}x}{\text{d}y} . 

1

525x−7\frac{5}{2\sqrt{5x-7}}  

2

125x−7\frac{1}{2\sqrt{5x-7}}  

3

55x−7\frac{5}{\sqrt{5x-7}}  

4

55x−75\sqrt{5x-7}  

13

Multiple Choice

dydt if y=cos⁡10t+12\frac{dy}{dt}\ if\ y=\cos\sqrt{10t+12}  Find

1

−510t+12sin⁡10t+12\frac{-5}{\sqrt{10t+12}}\sin\sqrt{10t+12}  

2

−1210t+12sin⁡10t+12\frac{-1}{2\sqrt{10t+12}}\sin\sqrt{10t+12}  

3

−sin⁡10t+12-\sin\sqrt{10t+12}  

4

−sin⁡(510t+12)-\sin\left(\frac{5}{\sqrt{10t+12}}\right)  

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