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Writing Equations of Parallel and Perpendicular Lines

Writing Equations of Parallel and Perpendicular Lines

Assessment

Presentation

•

Mathematics

•

9th Grade

•

Medium

•
CCSS
HSG.GPE.B.5, 8.EE.B.5

Standards-aligned

Created by

Tamara Capetillo

Used 2+ times

FREE Resource

7 Slides • 8 Questions

1

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2

3

Multiple Choice

Which of the following lines is PARALLEL to the graph of y = -6x + 3 and goes through the point (-1,4)?

1


y=−6x −4y=-6x\ -4

2

y=−6x+2y=-6x+2

3

y=−6x−2y=-6x-2

4

y=−6x+4y=-6x+4

4

Multiple Choice

What is the equation of a line that passes through (4,-1) and is parallel to

y=14x+7y=\frac{1}{4}x+7  ?

1

y=14xy=\frac{1}{4}x  

2

y=14x−2y=\frac{1}{4}x-2  

3

y=14x−1y=\frac{1}{4}x-1  

4

y=14 x+1y=\frac{1}{4\ }x+1  

5

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6

7

Drag and Drop

Write the equation of the line, in slope-intercept form that is parallel to the equation 2x-3y=12 and passes though (9, 4)



y = ​
x​
​
Drag these tiles and drop them in the correct blank above
2/3
-
2
-2/3
+
10
3/2
-3/2
4
9

8

Multiple Choice

Question image

Write the equation of the line, in slope-intercept form, that is parallel to the graph, and passes through the point (1, -4).

1

y = -2x + 2

2

y = -1/2x - 2

3

y = -2x - 2

4

y = 1/2x + 2

9

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(video is split into 2 slides)

10

11

12

Multiple Choice

Given the line y=23x−3y=\frac{2}{3}x-3   Write the equation of a line perpendicular to it that passes through the point (4, -1)

1

y=−32x−7y=-\frac{3}{2}x-7  

2

y=23x+4y=\frac{2}{3}x+4  

3

y=23x−1y=\frac{2}{3}x-1  

4

y=−32x+5y=-\frac{3}{2}x+5  

13

Multiple Choice

Write the equation of a line PERPENDICULAR to y=13x−9y=\frac{1}{3}x-9  and passes through the point (-6, 10).

1

y=13x−9y=\frac{1}{3}x-9

2

y=13x+10y=\frac{1}{3}x+10

3

y=−3x+6y=-3x+6

4

y=−3x−8y=-3x-8

14

Multiple Choice

What is the slope of the line that contains point (-2,2) and is perpendicular to x - 2y = 5 in standard form?

1

-2

2

2

3

1/2

4

-1/2

15

Multiple Choice

Question image

Write the equation of the line, in slope-intercept form, that is perpendicular to the graph, and passes through the point (6, 1).

1

y = -2x + 2

2

y = -1/2x - 2

3

y = -2x - 2

4

y = 1/2x + 2

pattern-tertiary
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