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Trigonometric Functions

Trigonometric Functions

Assessment

Presentation

Mathematics

12th Grade

Hard

Created by

James Gonzalez

FREE Resource

8 Slides • 15 Questions

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​The next 5 questions are based on this value

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Multiple Choice

Given cotθ=2\cot\theta=-2 and tanθ=12\tan\theta=-\frac{1}{2} , Find cscθ\csc\theta ; ( π2<θ<π\frac{\pi}{2}<\theta<\pi  )

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5-5

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5\sqrt[]{5}

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52\frac{\sqrt[]{5}}{2}

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5-\sqrt[]{5}

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Multiple Choice

Given cotθ=2\cot\theta=-2 and tanθ=12\tan\theta=-\frac{1}{2} , Find secθ\sec\theta ; ( π2<θ<π\frac{\pi}{2}<\theta<\pi  )

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52-\frac{5}{2}

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5\sqrt[]{5}

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52\frac{\sqrt[]{5}}{2}

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52-\frac{\sqrt[]{5}}{2}

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Multiple Select

Given cotθ=2\cot\theta=-2 and tanθ=12\tan\theta=-\frac{1}{2} , Find sinθ\sin\theta ; ( π2<θ<π\frac{\pi}{2}<\theta<\pi  )

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52-\frac{5}{2}

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55\frac{\sqrt[]{5}}{5}

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55-\frac{\sqrt[]{5}}{5}

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15\frac{1}{\sqrt[]{5}}

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Multiple Choice

Given cotθ=2\cot\theta=-2 and tanθ=12\tan\theta=-\frac{1}{2} , Find cosθ\cos\theta ; ( π2<θ<π\frac{\pi}{2}<\theta<\pi  )

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52-\frac{5}{2}

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255\frac{2\sqrt[]{5}}{5}

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255-\frac{2\sqrt[]{5}}{5}

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25\frac{2}{\sqrt[]{5}}

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(Exam Question)

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Multiple Choice

Given tanθ=45\tan\theta=-\frac{4}{5} , and cosθ>0\cos\theta>0  ; Find sin θ. (USE Trigonometry identities)

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41\sqrt[]{41}

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41-\sqrt[]{41}

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414\frac{\sqrt[]{41}}{4}

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414-\frac{\sqrt[]{41}}{4}

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Multiple Choice

Given tanθ=45\tan\theta=-\frac{4}{5} , and cosθ>0\cos\theta>0  ; Find sec θ. (USE Trigonometry identities)

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415\frac{\sqrt[]{41}}{5}

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414-\frac{\sqrt[]{41}}{4}

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414\frac{\sqrt[]{41}}{4}

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415-\frac{\sqrt[]{41}}{5}

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