Factoring by Grouping Trinomial

​student objectives

​Students will be able to:
• Find the greatest common factor of the terms of a polynomial.

• Use the structure of a polynomial, and the understanding that polynomials
form a system similar to integers, to rewrite it in factored form.

• Factor polynomials that represent real-world problems.

• Factor a trinomial in the form x2+ bx + cby finding two binomial factors whose product is equal to the trinomial.

Multiple Choice

What is the GCF? 5x²+20x

• 5
• x
• 5x
• 20x

Multiple Choice

What is the GCF? 3x²-2x

• 3
• 3x
• x
• 2

Multiple Choice

Factor: 3x³ + 9x² - 15x

• x(3x² + 9x - 15)

• 3x(x² + 3x - 5)

• 3x(x² - 9x + 15)

• x(3x² -9x + 15)

Multiple Choice

Factor completely

$$4a^3b^5\ -\ 18a^2b^3\ +\ 8a^3b^3$$  

• $$2a^2b^3\ \left(2ab^2\ -\ 9ab\ +\ 4ab^2\right)$$  

• $$2a^2b^3\ \left(2ab^2\ -\ 9\ +\ 4a\right)$$  

• $$4a^2b^3\ \left(ab^2\ -\ 14\ +\ 6a\right)$$  

• $$2ab\ \left(2a^2b^3\ -\ 9ab\ +\ 4ab\right)$$  

Multiple Choice

Factor

k² -2k - 24

• (k+4)(k-6)

• (k+4)(k+6)

• (k+6)(k-1)

• (k-4)(k+6)

Multiple Choice

Factor

k²+7x+10

• (k+2)(k+5)

• (k-2)(k-5)

• (k+10)(k+4)

• (k+2)(k-5)

Multiple Choice

Factor:
v² + 3v - 88

• (v + 11)(v - 8)
• (v + 22)(v - 4)
• (v + 8)(v - 11)
• (v - 22)(v + 4)

Multiple Choice

Factor
x² -16x + 48

• (x - 12)(x - 4)
• (x + 6)(x - 8)
• (x + 12)(x - 4)
• (x -16)(x - 3)

Multiple Choice

Factor
r² -16r + 60

• (r - 15)(r + 4)
• (r - 6)(r + 10)
• (r - 6)(r - 10)
• (r +30)(r - 2)

Multiple Choice

factor x² -16x + 48

• (x - 12)(x - 4)

• (x + 12)(x - 4)

• (x + 6)(x - 8)

• PRIME

Multiple Choice

Factor completely: 
3x² + 18x +15
Hint: Factor GCF first.

• 3(x² + 6x + 5)
• (x + 5)(x + 1)
• 3(x + 5)(x + 1)
• Prime

Open Ended

How do you feel about today's lesson? What did you learn? What do you need more help with?