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Ice Chart and KA

Ice Chart and KA

Assessment

Presentation

Chemistry

11th Grade - University

Hard

Created by

Joseph Anderson

FREE Resource

11 Slides • 3 Questions

1

ICE Table

Determine Equilibrium Constant Using ICE Table Method

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In this video let's go through how to determine equilibrium constant Kc using the ICE table method.

Given this simple example:

2.00 moles of SO2SO_2 and 2.00 moles of O2O_2 are mixed and allowed to reach equilibrium in a 0.50 dm3dm^3 container via reaction:
 2SO22SO_2 (g) +  O2O_2 (g)  2SO32SO_3 (g)

If conversion of  SO2SO_2  is 20%, determine Kc

4

2SO2(g) + O2(g) ⇌ 2SO3(g)

  • First we have to write out the balanced equation and 3 additional rows which represents the following:

  • I - INITIAL number of moles

    C - CHANGE in number of moles

    E - EQUILIBRIUM number of moles

  • The initial moles of SO2 and O2 are both given as 2.00 moles, so we call put that info into the ICE table.

  • Also the conversion of SO2 is 20% which works out to be 0.4 moles of SO2 reacted, and we can put that in as well.

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Given this equation:

H2 + I2 ⇌ 2HI

Calculate all three equilibrium concentrations when

[H2]o = [I2]o = 0.200 M and Kc = 64.0.

7

H2 + I2 ⇌ 2HI

  • Now, let's fill in the initial row. This should be pretty easy:

  • The first two values were specified in the problem and the last value ([HI] = 0) come from the fact that the reaction has not yet started, so no HI could have been produced yet.

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Now for the change row. 

  • The minus sign comes from the fact that the H2 and I2 amounts are going to go down as the reaction proceeds.

  • x signifies that we know some H2 and I2 get used up, but we don't know how much. What we do know is that an EQUAL amount of each will be used up. We know this from the coefficients of the equation.

  • For every one H2 used up, one I2 is used up also.

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9

 H2H_{2_{ }}  +  I2I_2   ⇌  2HI2HI  

 Kc = [HI]2[H2][I2]Kc\ =\ \frac{\left[HI\right]^2}{\left[H_2\right]\left[I_2\right]}  
 64 = (2x)2(0.2  x)(0.2  x)64\ =\ \frac{\left(2x\right)^2}{\left(0.2\ -\ x\right)\left(0.2\ -\ x\right)}  
 x= 0.16 mol dm3x=\ 0.16\ mol\ dm^{-3}  

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10

Multiple Choice

Nitrogen and oxygen do not react appreciably at room temperature, as illustrated by our atmosphere. But at high temperatures, the reaction below can proceed to a measurable extent.

N2(g) + O2(g) ⇌ 2NO(g)

At 3000 K, the reaction above has Kc = 0.0153. If 0.3000 mol of pure NO is injected into an evacuated 2.000 L container and heated to 3000 K, what will be the equilibrium concentration of NO?

1

0.0096 mol dm-3

2

0.0706 mol dm-3

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Multiple Choice

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At a particular temperature, Kc = 2.0 x 10¯6 for the reaction:

2CO2(g) ⇌ 2CO(g) + O2(g)

If 2.0 mol CO2 is initially placed into a 5.0 L vessel, calculate x?

1

x = 4.3 x 10¯3 M

2

x = 4.3 x 10-2 M

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14

Poll

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ICE Table

Determine Equilibrium Constant Using ICE Table Method

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