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Completing the Square - Day 2

Completing the Square - Day 2

Assessment

Presentation

•

Mathematics

•

9th Grade

•

Practice Problem

•

Medium

•
CCSS
HSA-REI.B.4B

Standards-aligned

Created by

Melinda Austin

Used 4+ times

FREE Resource

3 Slides • 13 Questions

1

Completing the Square
(When a > 1)

By Melinda Austin

2

Drag and Drop

Question image
The first step would be ​
Drag these tiles and drop them in the correct blank above
add 5 to both sides
divide 8 by 2
raise 4 to the 2nd power

3

Drag and Drop

Question image
What would the next step be? ​
Drag these tiles and drop them in the correct blank above
divide 8 by 2
raise 4 to the 2nd power
divide each term by 4
add 5 to both sides

4

Drag and Drop

Question image
What should the third step look like? ​​ ​
Drag these tiles and drop them in the correct blank above

5

Drag and Drop

Question image
What should the fourth step look like? ​​ ​
Drag these tiles and drop them in the correct blank above

6

Drag and Drop

Question image
What should the fifth step look like? ​​ ​
Drag these tiles and drop them in the correct blank above

7

Multiple Choice

Given the equation: 2x2−8x+6=02x^2-8x+6=0 What is the first step in solving the equation by Completing the Square?

1

2x2−8x=−62x^2-8x=-6

2

x2−4x=−3x^2-4x=-3

3

−42=(−2)2-\frac{4}{2}=\left(-2\right)^2

4

x2−4x+4=−3+4x^2-4x+4=-3+4

8

Multiple Choice

Given the equation: 2x2−8x+6=02x^2-8x+6=0 What is the second step in solving the equation by Completing the Square?

1

2x2−8x=−62x^2-8x=-6

2

x2−4x=−3x^2-4x=-3

3

−42=(−2)2-\frac{4}{2}=\left(-2\right)^2

4

x2−4x+4=−3+4x^2-4x+4=-3+4

9

Multiple Choice

Given the equation: 2x2−8x+6=02x^2-8x+6=0 What is the third step in solving the equation by Completing the Square?

1

2x2−8x=−62x^2-8x=-6

2

x2−4x=−3x^2-4x=-3

3

−42=(−2)2-\frac{4}{2}=\left(-2\right)^2

4

x2−4x+4=−3+4x^2-4x+4=-3+4

10

Multiple Choice

Given the equation: 2x2−8x+6=02x^2-8x+6=0 What is the fourth step in solving the equation by Completing the Square?

1

2x2−8x=−6\sqrt[]{2x^2-8x}=\sqrt[]{-6}

2

(x−2)2=1\sqrt[]{\left(x-2\right)^2}=\sqrt[]{1}

3

−42=(−2)2\sqrt[]{-\frac{4}{2}}=\sqrt[]{\left(-2\right)^2}

4

(x+2)2=1\sqrt[]{\left(x+2\right)^2}=\sqrt[]{1}

11

Match

3x2−18x−48=03x^2-18x-48=0

Match the correct equation to the correct step in solving the given equation by Completing the Square?

1st step

2nd step

3rd step

4th step

5th step

3x2−18x=483x^2-18x=48

x2−6x=16x^2-6x=16

x2−6x+9=16+9x^2-6x+9=16+9

(x−3)2=25\left(x-3\right)^2=25

(x−3)2=25\sqrt[]{\left(x-3\right)^2}=\sqrt[]{25}

12

Match

5x2+10x−34=65x^2+10x-34=6

Match the correct equation to the correct step in solving the given equation by Completing the Square?

1st step

2nd step

3rd step

4th step

5th step

5x2+10x=405x^2+10x=40

x2+2x=8x^2+2x=8

x2+2x+1=8+1x^2+2x+1=8+1

(x+1)2=9\left(x+1\right)^2=9

(x+1)2=9\sqrt[]{\left(x+1\right)^2}=\sqrt[]{9}

13

Complete problems 4, 5, and 6.

​Work with your table.

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14

Let's look at numbers 7 and 8.

​Regroup! Irrational Solutions

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15

Multiple Select

  1. The solution to the equation 3x2−6x−3=903x^2-6x-3=90 . Select all that apply.

1

x=3+13x=3+\sqrt[]{13}

2

x=3−13x=3-\sqrt[]{13}

3

x=−3+13x=-3+\sqrt[]{13}

4

x=−3−13x=-3-\sqrt[]{13}

16

Multiple Select

  1. The solution to the equation 5x2+30x−4=165x^2+30x-4=16 . Select all that apply.

1

x=1+4 2x=1+4\ \sqrt[]{2}

2

x=1+16 2x=1+16\ \sqrt[]{2}

3

x=1−4 2x=1-4\ \sqrt[]{2}

4

x=1−16 2x=1-16\ \sqrt[]{2}

pattern-tertiary
Completing the Square
(When a > 1)

By Melinda Austin

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