
Intro to and Solving Quadratics
Presentation
•
Mathematics
•
9th - 12th Grade
•
Easy
+2
Standards-aligned
Liana C
Used 4+ times
FREE Resource
8 Slides • 20 Questions
1
By Liana C
2
Multiple Choice
y = x
y = x2
y = x3
y = 2x
3
Multiple Choice
Which solid parabola, h, represents the equation y=x2+2 ?
4
The intercepts and the vertex are the points you need to fully graph a quadratic.
Each of these points are solved with one of the 3 forms of a quadratic.
Special Points
5
Multiple Choice
Which form of a quadratic function, when solved, will give you the x-intercepts?
Standard Form
y=ax2+bx+c
Factored Form
y=a(x−r1)(x−r2)
Vertex Form
y=a(x−h)2+k
6
Multiple Choice
What are the x-intercepts of this quadratic?
(2, 0) and
(4, 0)
(-2, 0) and (-5, 0)
(2, 0) and
(5, 0)
(-2, 0) and
(-4, 0)
7
Multiple Choice
8
Multiple Choice
What is the vertex of this quadratic?
Maximum;
(-4, 2)
Minimum;
(-4, 2)
Maximum;
(2, -4)
Minimum;
(2, -4)
9
Multiple Choice
10
Parabolas mimic a common phenomena: a falling object over time, t.
The function here shows the height of a ball thrown. The intercepts and vertex all have special meanings when paired with a real context.
Quadratics in the world
11
Vertex: (t, h) a maximum or minimum height of the object at a specific time.
Y-intercept: (0, h) the starting height of the object at time 0.
X-intercept: (t, 0) the time when the object is at a height of 0.
In Context using feet/time
12
Multiple Choice
The graph below shows the height, in feet, over time, in seconds, of a student's rocket launch in science class.
How long was the rocket in the air?
14 minutes
7 seconds
14 seconds
7 minutes
13
Multiple Choice
The graph below shows the height, in feet, over time, in seconds, of a student's rocket launch in science class.
What was the maximum height the rocket reached?
25 feet
45 feet
65 feet
85 feet
14
Multiple Choice
The graph below shows the height, in feet, over time, in seconds, of a student's rocket launch in science class.
What would the equation be of the function in factored form?
y=−a(x+1)(x+14)
y=−ax(x−14)
y=−a(x+0)(x+14)
y=a(x)(x−14)
15
-Set equation equal to zero.
-Factor.
-Set each factor equal to zero.
Zero Product Property
-Type the equation in the calc.
-See points in the table where y = 0.
-If not whole numbers, use [CALC] [ZERO].
Graphing
Quadratic Formula
16
By Factoring
Set y = 0.
Look for a GCF.
Factor the trinomial.
Use the __________________________ _______________________________________ Property:
("If a product of factors equals zero, then
one of those factors must be zero"). Set
factor equal to zero and solve.
17
Multiple Choice
Factor
x2+12x+20
(x+2)(x+10)
(x+4)(x+5)
(x−2)(x−10)
(x−4)(x−5)
18
Multiple Choice
Solve: x2 - 9x + 20 = 0
x = -4 and x = -5
x = 20 and x = -9
x = 4 and x = 5
x = -4 and x = 5
19
Multiple Choice
Use the Zero Product Property to solve for n.
20
Multiple Choice
Solve using the Zero-Product Property
(x −11)(5x + 1) = 0
x = 11 or x = −51
x = −11 or x = −51
x = 11 or x = 51
x = −11 or x = 51
21
Multiple Choice
Solve:
m2 − 100 = 0
m = 50 , −50
m = 10
m = 10, −10
m = −10
22
By Graphing
Press [Y = ]: Type equation into Y1.
Option 1
→[GRAPH]: Estimate the intercepts. Can use [TRACE] with these values.
→[2nd][GRAPH]: Find "_____________" value(s) for when "_____________" = 0.
Option 2
→[CALC][ZERO]: Cursor over of the zeros.
→Cursor "__________________________" of intercept, [ENTER]. Cursor "__________________________" of intercept, [ENTER].
→Do not type anything for "Guess?"; press [ENTER].
23
Multiple Choice
24
Multiple Choice
Take an educated guess!
If the graph of a quadratic does not intercept the x axis at any point, then it has:
1 Real Solution
2 Real Solutions
1 Imaginary Solution
25
By the Quadratic Formula
26
Multiple Choice
y = x2 +5x +7, match each leading coefficient with its correct letter
27
Multiple Choice
28
Multiple Choice
Select the false statement about the parabola
The vertex is at (-2,-3)
The minimum value is -3
There are no real solutions.
The y-intercept is
(0, -7).
By Liana C
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