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  5. 6.2.1 Substitution Methods
6.2.1 Substitution Methods

6.2.1 Substitution Methods

Assessment

Presentation

Mathematics

9th - 12th Grade

Easy

CCSS
8.EE.C.8B, RI.11-12.7, HSA.REI.C.6

+4

Standards-aligned

Created by

Ilyse Marcinkiewicz

Used 1+ times

FREE Resource

19 Slides • 12 Questions

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Categorize

Options (5)

y = -4

y = 3

x = -10

x = 7

y = 2x +4

Question image

Sort the equations into the correct categories for horizontal and vertical lines

Horizontal Lines
Vertical Lines
Neither

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Graphing

Solve the system

y = -2x-4

y=2

What is the solution?

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Draw

Solve the system

y = -2x-4

y = 2

What is the solution?

Check your answer using the graph

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Dropdown

Does the system of equations have no solution, one solution or infinitely many solutions?

y=2 and y= -3​


y= 1 and y= 1​


y= -1 and y=2x+4​

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Reorder

Order the steps to show how to solve a linear system x = 5 and y = 2x + 3.

Substitute x = 5 into the equation y = 2x + 3.

The resulting equation is y = 2(5) + 3. Solve for y.

The value of y is 13

Write the solution as the point (5,13).

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Multiple Choice

What is the solution to the system of equations y = 10 and y = 3x – 5?

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Infinitely many solutions

2

No Solution

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(5, 10)

4

(10, 5)

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Multiple Choice

Which of the following equations correctly uses the transitive property to write the two equations in slope-intercept form into a single equation?

y = 2x + 4

y = 3x – 2

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2x+4=3x-2

2

2x=3x

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y=3x-2+2x+4

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2x+3x+4-2=y

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Draw

Solve the system

y = -x+4

y = 4x-1

What is the solution?

Check your answer using the graph

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Multiple Choice

Using the substitution method, what is the solution to the system of linear equations?

y=14x+3 and y=14x6y=\frac{1}{4}x+3\ and\ y=\frac{1}{4}x-6

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(0, -6)

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No solution

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(3, -6)

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Infinitely many solutions

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Draw

Averi was asked to solve the system of equations below.

y = 8x – 6

y = 2(4x + 4) – 2

Averi found that there are infinitely many solutions. Is she correct?

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Open Ended

Did you understand today's lesson?

AND

What is something fun, interesting or new that you learned about in class today?

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Fill in the Blank

Type answer...

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