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11.3 Confidence Intervals

11.3 Confidence Intervals

Assessment

Presentation

Mathematics

12th Grade

Practice Problem

Hard

CCSS
HSS.IC.A.1, HSS.IC.B.4

Standards-aligned

Created by

Jessica James

Used 1+ times

FREE Resource

7 Slides • 13 Questions

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Multiple Choice

For an IQ the mean is 100, the standard deviation is 10. Assuming it is normally distributed, 95% of results should fit between...

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80.4 and 119.6

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80 and 120

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90.4 and 110.6

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70 and 130

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Z score reminder

99% - 2.58
95% - 1.96
90% - 1.645

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Multiple Choice

For an IQ the mean is 100, the standard deviation is 10. Assuming it is normally distributed, 99% of results should fit between...

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60.3 to 140.7

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74.2 to 125.8

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65.1 to 135.9

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Multiple Choice

For an IQ the mean is 100, the standard deviation is 10. Assuming it is normally distributed, 99% of results should fit between...

1
80 to 120
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74.24 to 125.76
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60 to 140
4
90 to 110

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lie

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Multiple Choice

What does a 90% confidence interval indicate about the population mean?

1

It means the population mean will always be in the interval.

2

It means 90% of the possible samples will have the population mean in the calculated interval.

3

It means the sample mean is always equal to the population mean.

4

It means the interval is 90% of the sample size.

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Multiple Choice

Which of the following z-scores would you use for a 99% confidence interval?

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±1.645

2

±1.96

3

±2.58

4

±2.33

13

Multiple Choice

A sample of 20 cupcakes found the interval for average calories to be (150, 350). Which is the correct interpretation of the 95% confidence interval?

1

We are 95% confident that the true mean caloric content can be found with a sample of 150 to 350 cupcakes.

2

We are 95% confident that the interval (150, 350) captures the true average caloric content.

3

We are 95% confident that a sample of 20 cupcakes will find 250 calories per cupcake.

4

None of these are correct.

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Open Ended

In Worked Example 3, the average amount spent on lunch was between $4.43 and $4.63. Determine the sample size needed to reduce the interval to ±$0.05 for a 95% confidence interval.

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