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Stars

Stars

Assessment

Presentation

Science

9th Grade

Practice Problem

Hard

NGSS
HS-ESS1-1, HS-ESS1-3, HS-PS1-8

+3

Standards-aligned

Created by

Barbara White

Used 6+ times

FREE Resource

39 Slides • 31 Questions

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Stars

Middle School

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Learning Objectives

  • Explain how parallax helps measure distances to nearby stars.

  • Compare luminosity, brightness, apparent magnitude, and absolute magnitude.

  • Use the H-R diagram to classify stars and understand their life cycles.

  • Describe how stars form from molecular clouds into main-sequence stars.

  • Explain how nuclear fusion inside stars creates different chemical elements.

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Key Vocabulary

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Parallax

The apparent shift in a star's position from different views, which helps scientists measure its distance.

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Luminosity

The total amount of energy a star emits, representing its true brightness and power output.

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Apparent Magnitude

A measure of a star's brightness as it is observed from our specific location on Earth.

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Absolute Magnitude

A measure of a star's true luminosity, calculated as if viewed from a standard distance.

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Main Sequence

The stage where most stars spend their lives, fusing hydrogen atoms into helium in their cores.

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Measuring Stellar Distance

  • Parallax is the apparent shift of a star against its background.

  • A larger observed shift means the star is closer to Earth.

  • This method is not effective for measuring very distant stars.

5

Solved Example 1
A star is 7 parsecs away from Earth. How many light-years is that?

Step 1: Analyze and Sketch the Problem

  • Goal: Convert the distance of a star from parsecs to light-years.

  • Knowns: The distance to the star is 7 parsecs. The conversion factor is 1 parsec = 3.26 light-years.

  • Unknown: The distance to the star in light-years.

  • Formula: Distance in light-years = (Distance in parsecs) × 3.26

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Solved Example 1
A star is 7 parsecs away from Earth. How many light-years is that?

Step 2: Solve for the Unknown

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Solved Example 1
A star is 7 parsecs away from Earth. How many light-years is that?

Step 3: Evaluate the Answer

  • To verify, we can convert the result back to parsecs by dividing by the conversion factor.

  • 22.82 light-years / 3.26 light-years/parsec ≈ 7 parsecs. This confirms the conversion is accurate and the answer is reasonable.

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Multiple Choice

What is parallax in the context of astronomy?

1

The total distance a star travels in a year.

2

The speed at which a star moves away from Earth.

3

The change in a star's brightness over time.

4

The apparent shift in a star's position against its background.

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Multiple Choice

What is the relationship between the size of a star's parallax shift and its distance from Earth?

1

A larger shift means the star is farther away.

2

The size of the shift is not related to the star's distance.

3

A smaller shift means the star is closer to Earth.

4

A larger shift means the star is closer to Earth.

10

Multiple Choice

A star is located 10 parsecs from Earth. Using the conversion factor of 1 parsec = 3.26 light-years, what is the star's distance in light-years?

1

22.82 light-years

2

32.6 light-years

3

13.26 light-years

4

3.07 light-years

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Stellar Brightness and Magnitude

Intrinsic Brightness

  • Luminosity is the total energy a star releases each second, representing its actual power.

  • This is a fundamental property of the star, independent of an observer's specific location.

  • Absolute magnitude measures this intrinsic luminosity from a standard distance of 10 parsecs.

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Observed Brightness

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  • Apparent brightness describes how bright a star appears to an observer at their location.

  • This perceived brightness diminishes as the distance from the star increases.

  • Apparent magnitude is how bright a star looks from Earth; smaller numbers mean brighter stars.

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Solved Example 2
Star Rigel has approximately the same luminosity as Star Deneb. If Rigel is 260 parsecs from Earth and Deneb is 800 parsecs from Earth, how many times brighter does Rigel appear compared to Deneb?

Step 1: Analyze and Sketch the Problem

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Solved Example 2
Star Rigel has approximately the same luminosity as Star Deneb. If Rigel is 260 parsecs from Earth and Deneb is 800 parsecs from Earth, how many times brighter does Rigel appear compared to Deneb?

Step 2: Solve for the Unknown

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Solved Example 2
Star Rigel has approximately the same luminosity as Star Deneb. If Rigel is 260 parsecs from Earth and Deneb is 800 parsecs from Earth, how many times brighter does Rigel appear compared to Deneb?

Step 3: Evaluate the Answer

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Multiple Choice

Which of the following best defines a star's luminosity?

1

The total energy the star releases each second.

2

The star's brightness measured from a distance of 10 parsecs.

3

The decrease in brightness due to the star's distance.

4

How bright the star appears from Earth.

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Multiple Choice

What is the primary reason a star with very high luminosity might have a low apparent brightness to an observer on Earth?

1

The star is measured from a standard distance of 10 parsecs.

2

The star is located at a very large distance from Earth.

3

The star's absolute magnitude is a large number.

4

The star's energy output is inconsistent.

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Multiple Choice

Star A and Star B have the same intrinsic luminosity. If Star A is 100 parsecs from Earth and Star B is 300 parsecs from Earth, how many times brighter does Star A appear compared to Star B?

1

It appears 3 times brighter.

2

It appears 1/3 as bright.

3

It appears 9 times brighter.

4

They appear to have the same brightness.

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Brightness and Distance Equations

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Solved Example 3
An astronomer observes a star and measures its distance from Earth to be 1.5 x 1017 meters and its apparent brightness to be 2.5 x 10-8 W/m2. Using the formula L = 4πd2b, calculate the star's luminosity.

Step 1: Analyze and Sketch the Problem

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Solved Example 3
An astronomer observes a star and measures its distance from Earth to be 1.5 x 1017 meters and its apparent brightness to be 2.5 x 10-8 W/m2. Using the formula L = 4πd2b, calculate the star's luminosity.

Step 2: Solve for the Unknown

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Solved Example 3
An astronomer observes a star and measures its distance from Earth to be 1.5 x 1017 meters and its apparent brightness to be 2.5 x 10-8 W/m2. Using the formula L = 4πd2b, calculate the star's luminosity.

Step 3: Evaluate the Answer

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Multiple Choice

Which of the following are used by astronomers to establish the relationship between a star's luminosity, its apparent brightness, and its distance?

1

Mathematical equations

2

Telescopic observations alone

3

The star's age and size

4

The star's color spectrum

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Multiple Choice

On the magnitude scale used by astronomers, if Star X has a magnitude of 2 and Star Y has a magnitude of 5, what can be concluded?

1

Both stars have the same brightness

2

Star X is brighter than Star Y

3

Star Y is brighter than Star X

4

The stars are the same distance from Earth

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Multiple Choice

A star is observed to have a distance (d) of 2.0 1016 meters from Earth and an apparent brightness (b) of 5.0 10-10 W/m2. Using the formula , what is the calculated luminosity (L) of the star?

1

2.5 1042 W

2

8.0 1023 W

3

1.3 108 W

4

2.5 1024 W

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Star Color, Temperature, and Luminosity

Hot Blue Stars

  • Hotter stars emit higher-frequency light due to more active fusion, making them appear blue.

  • Their radiation output is significantly higher, which makes them much more luminous than other stars.

  • The light stars emit is blackbody radiation, which is directly related to their temperature.

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Cool Red Stars

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  • Cooler stars have less active fusion, so they emit lower-frequency light, appearing red.

  • Medium-temperature stars like our Sun fall in the middle and appear yellow-white.

  • A star's color provides a direct indication of its surface temperature and luminosity.

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Solved Example 4
Betelgeuse is a red supergiant star in the constellation of Orion, which has a peak wavelength of 956 nm. Using Wien's Displacement Law, which states that the peak wavelength (λmax) of a star is inversely proportional to its surface temperature (T), what is the surface temperature of Betelgeuse in Kelvin?

Step 1: Analyze and Sketch the Problem

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Solved Example 4
Betelgeuse is a red supergiant star in the constellation of Orion, which has a peak wavelength of 956 nm. Using Wien's Displacement Law, which states that the peak wavelength (λmax) of a star is inversely proportional to its surface temperature (T), what is the surface temperature of Betelgeuse in Kelvin?

Step 2: Solve for the Unknown

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Solved Example 4

Betelgeuse is a red supergiant star in the constellation of Orion, which has a peak wavelength of 956 nm. Using Wien's Displacement Law, which states that the peak wavelength (λmax) of a star is inversely proportional to its surface temperature (T), what is the surface temperature of Betelgeuse in Kelvin?

Step 3: Evaluate the Answer

  • The calculated surface temperature of Betelgeuse is approximately 3031 K.

  • This is a relatively low surface temperature for a star, which is consistent with its classification as a red supergiant. Red stars are cooler than yellow or blue stars, so the answer is reasonable.

  • The units of Kelvin are appropriate for measuring temperature in this context.

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Multiple Choice

What is the primary information that can be determined from a star's color?

1

Its age and distance from Earth

2

Its surface temperature and luminosity

3

Its chemical composition and mass

4

Its rotational speed and magnetic field

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Multiple Choice

What is the relationship between a star's internal fusion process and the color of light it emits?

1

Less active fusion results in higher-frequency, blue light.

2

More active fusion results in higher-frequency, blue light.

3

The level of fusion activity has no effect on the star's color.

4

More active fusion results in lower-frequency, red light.

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Multiple Choice

An astronomer observes a bright, blue-white star and determines its peak emission wavelength (λmax) is 386 nm. Using Wien's Displacement Law (T = b / λmax), what is the approximate surface temperature of this star? (Wien's constant b = 2.898 x 10-3 m⋅K)

1

7,500 K

2

9,560 K

3

2,898 K

4

3,031 K

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The Hertzsprung-Russell (H-R) Diagram

  • It classifies stars based on their luminosity and surface temperature.

  • Most stars, including the Sun, are on the main sequence.

  • Hot, massive stars are upper-left; cool, dimmer stars are lower-right.

  • As stars age, they evolve into giants or dwarfs.

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Solved Example 5
Two main-sequence stars, Star A and Star B, have the same surface temperature. However, Star A is 100 times more luminous than Star B. How many times larger is the radius of Star A compared to the radius of Star B?

Step 1: Analyze and Sketch the Problem

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Solved Example 5
Two main-sequence stars, Star A and Star B, have the same surface temperature. However, Star A is 100 times more luminous than Star B. How many times larger is the radius of Star A compared to the radius of Star B?

Step 2: Solve for the Unknown

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Solved Example 5
Two main-sequence stars, Star A and Star B, have the same surface temperature. However, Star A is 100 times more luminous than Star B. How many times larger is the radius of Star A compared to the radius of Star B?

Step 3: Evaluate the Answer

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Multiple Choice

What fundamental properties of a star are used to plot its position on the Hertzsprung-Russell diagram?

1

Age and mass

2

Luminosity and surface temperature

3

Size and chemical composition

4

Distance from Earth and brightness

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Multiple Choice

Where on the main sequence would you expect to find a star that is hot and massive?

1

In the center of the sequence

2

In the upper-left section

3

In the lower-right section

4

Spread randomly across the sequence

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Multiple Choice

Two main-sequence stars, Star X and Star Y, have the same surface temperature. If Star X is 25 times more luminous than Star Y, how many times larger is the radius of Star X compared to Star Y?

1

5 times larger

2

625 times larger

3

2.5 times larger

4

25 times larger

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Leaving the Main Sequence

  • Stars leave the main sequence after using up the hydrogen fuel in their core.

  • ​The core contracts and heats, allowing helium to fuse into heavier elements.

  • This energy expands the outer layers, turning the star into a red giant.

  • Sun-like stars later form a planetary nebula and a dense white dwarf.

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Solved Example 6
A star's apparent magnitude is +2.5 when observed from Earth. If this star were located at a standard distance of 10 parsecs, its absolute magnitude would be -1.5. Calculate the distance to this star from Earth in parsecs.

Step 1: Analyze and Sketch the Problem

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Solved Example 6
A star's apparent magnitude is +2.5 when observed from Earth. If this star were located at a standard distance of 10 parsecs, its absolute magnitude would be -1.5. Calculate the distance to this star from Earth in parsecs.

Step 2: Solve for the Unknown

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Solved Example 6
A star's apparent magnitude is +2.5 when observed from Earth. If this star were located at a standard distance of 10 parsecs, its absolute magnitude would be -1.5. Calculate the distance to this star from Earth in parsecs.

Step 3: Evaluate the Answer

  • The apparent magnitude (+2.5) is larger (dimmer) than the absolute magnitude (-1.5), so the star must be farther than 10 parsecs. Our calculated distance of 63.1 parsecs is greater than 10 parsecs, which is consistent with our analysis.

  • The answer is reasonable.

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Multiple Choice

What is the primary reason a star leaves the main sequence?

1

The star's outer layers are blown away by solar winds.

2

It begins to fuse hydrogen in its outer layers.

3

The star's core cools down and stops fusion.

4

It has exhausted the hydrogen fuel in its core.

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Multiple Choice

What process directly causes a star to expand into a red giant after leaving the main sequence?

1

The fusion of helium into heavier elements releases energy.

2

The star begins to burn the remaining hydrogen in its core.

3

The core of the star cools and absorbs energy from the outer layers.

4

The gravitational collapse of the star's outer layers.

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Multiple Choice

A Sun-like star is observed to have left the main sequence and expanded into a red giant. What can be predicted about the final stages of its evolution?

1

It will return to the main sequence after its red giant phase.

2

It will continue to expand until it dissipates completely.

3

It will explode in a supernova and become a black hole.

4

It will form a planetary nebula and a white dwarf.

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Life Cycles of Stars

Low-Mass Stars

  • Stars like our Sun burn fuel slowly and have very long lifespans, lasting for billions of years.

  • They evolve into a red giant, then release outer layers to form a beautiful planetary nebula.

  • The remaining core becomes a white dwarf, a dense star that slowly cools over a very long time.

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Supermassive Stars

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  • Stars over eight times the Sun's mass are very hot and bright but have much shorter lifespans.

  • They become a huge red supergiant before exploding in a powerful event called a Type II Supernova.

  • The core collapses to form a neutron star or, for the most massive stars, a black hole.

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Multiple Choice

What is the primary factor that determines the life cycle path a star will take?

1

Its location in the galaxy

2

Its temperature

3

Its brightness

4

Its mass

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Multiple Choice

How does a star's mass generally relate to its lifespan?

1

Massive stars have longer lifespans because they have more fuel.

2

Less massive stars have longer lifespans because they burn fuel more slowly.

3

A star's mass has no relationship to its lifespan.

4

All stars have the same lifespan regardless of their mass.

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Multiple Choice

Which sequence correctly describes the end-of-life stages for a supermassive star?

1

Type II Supernova, red supergiant, black hole

2

Red supergiant, Type II Supernova, neutron star or black hole

3

Red giant, planetary nebula, white dwarf

4

Planetary nebula, red giant, white dwarf

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The Birth of Stars

  • Stars form in vast clouds of gas and dust called molecular clouds.

  • A supernova shockwave can trigger the collapse of these stellar nurseries.

  • Gravity makes the cloud's center hotter and denser, forming a protostar.

  • Nuclear fusion in the core ignites a new main-sequence star.

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Multiple Choice

What are stars primarily formed from?

1

Solid rock and ice from asteroids

2

Pure light and energy from black holes

3

The remnants of exploded planets

4

Vast clouds of gas and dust

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Multiple Choice

What process causes a cloud of gas and dust to form a hot, dense protostar?

1

Nuclear fusion starts in the outer layers

2

The cloud begins to burn from the outside

3

A disturbance triggers gravitational collapse

4

The material cools and freezes into a solid core

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Multiple Choice

What would most likely happen if the core of a protostar never became hot and dense enough to start nuclear fusion?

1

It would immediately explode in a supernova

2

It would form a black hole instead

3

It would become a stable star more quickly

4

It would fail to become a stable star

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Nuclear Fusion in Stars

Hydrogen Fusion

  • Stellar fusion is the process that powers stars by combining atomic nuclei to create heavier elements.

  • In stars the size of our Sun, hydrogen fuses into helium via the proton-proton chain.

  • In larger stars, the carbon-nitrogen-oxygen (CNO) cycle is the dominant process for fusing hydrogen into helium.

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Heavier Element Fusion

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  • When a star's core runs out of hydrogen, it starts fusing helium nuclei to create carbon.

  • This is called the triple-alpha process, which requires temperatures over 100 million Kelvin to start.

  • In large stars, the alpha ladder fuses helium with other elements to form oxygen, neon, and silicon.

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Solved Example 7
In the triple-alpha process, three Helium-4 nuclei (alpha particles) fuse to create a Carbon-12 nucleus. Given the mass of a Helium-4 nucleus is 4.002603 amu and the mass of a Carbon-12 nucleus is exactly 12.000000 amu, calculate the energy released in Mega-electron Volts (MeV). (1 amu = 931.5 MeV/c2)

Step 1: Analyze and Sketch the Problem

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Solved Example 7
In the triple-alpha process, three Helium-4 nuclei (alpha particles) fuse to create a Carbon-12 nucleus. Given the mass of a Helium-4 nucleus is 4.002603 amu and the mass of a Carbon-12 nucleus is exactly 12.000000 amu, calculate the energy released in Mega-electron Volts (MeV). (1 amu = 931.5 MeV/c2)

Step 2: Solve for the Unknown

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Solved Example 7
In the triple-alpha process, three Helium-4 nuclei (alpha particles) fuse to create a Carbon-12 nucleus. Given the mass of a Helium-4 nucleus is 4.002603 amu and the mass of a Carbon-12 nucleus is exactly 12.000000 amu, calculate the energy released in Mega-electron Volts (MeV). (1 amu = 931.5 MeV/c2)

Step 3: Evaluate the Answer

  • The initial mass (12.007809 amu) is slightly greater than the final mass (12.000000 amu), which is a requirement for an energy-releasing (exothermic) reaction.

  • The mass defect is positive, resulting in a positive energy release, which is expected for a fusion reaction that powers a star. The units (MeV) are appropriate for measuring energy at the nuclear level, and the calculation is confirmed to be logical and correct.

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Multiple Choice

What is the fundamental process that powers stars by combining lighter atomic nuclei into heavier ones?

1

Stellar fusion

2

Gravitational collapse

3

Chemical combustion

4

Nuclear fission

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Multiple Choice

What is the primary difference in how sun-sized stars and stars larger than the sun fuse hydrogen into helium?

1

Sun-sized stars use the triple-alpha process, while larger stars use the proton-proton chain.

2

Sun-sized stars fuse helium into carbon, while larger stars fuse hydrogen into helium.

3

Sun-sized stars create heavier elements like oxygen, while larger stars only create helium.

4

Sun-sized stars use the proton-proton chain, while larger stars primarily use the CNO cycle.

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Multiple Choice

In the alpha ladder, a Carbon-12 nucleus (mass = 12.000000 amu) fuses with a Helium-4 nucleus (mass = 4.002603 amu) to form an Oxygen-16 nucleus (mass = 15.994915 amu). Given that 1 amu = 931.5 MeV/c2, calculate the approximate energy released.

1

7.27 MeV

2

7.16 MeV

3

-7.16 MeV

4

14,899 MeV

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Supernovae and the Creation of Elements

  • A supernova is a massive explosion from a large, dying star.

  • These explosions create and spread the heaviest elements across space.

  • This occurs through explosive nucleosynthesis, creating elements heavier than iron.

  • Key processes include the s-process, r-process, p-process, and rp-process.

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Solved Example 8
A star has a parallax angle of 0.772 arcseconds. How many parsecs away is it from Earth?

Step 1: Analyze and Sketch the Problem

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Solved Example 8
A star has a parallax angle of 0.772 arcseconds. How many parsecs away is it from Earth?

Step 2: Solve for the Unknown

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Solved Example 8
A star has a parallax angle of 0.772 arcseconds. How many parsecs away is it from Earth?

Step 3: Evaluate the Answer

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Multiple Choice

What is a supernova?

1

The process of two stars merging into a single, larger star

2

A massive explosion that occurs at the end of a large star's life

3

The final, quiet stage of a small, low-mass star

4

A cloud of gas and dust where new stars are born

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Multiple Choice

What is the primary outcome of explosive nucleosynthesis, which includes processes like the r-process and p-process, during a supernova?

1

It creates and spreads elements heavier than iron across space

2

It converts the star's mass entirely into light and energy

3

It causes the star to rapidly cool down and shrink

4

It breaks down all heavy elements into hydrogen and helium

67

Multiple Choice

Scientists studying a newly forming solar system detect a high abundance of elements heavier than iron. What is the most likely explanation for the presence of these elements?

1

They are a natural result of the cooling of interstellar gas clouds

2

They were created by the gravitational pull of the newly forming star

3

They were formed from the fusion of hydrogen and helium within the new star

4

They are the remnants of a previous, massive star that ended in a supernova

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Common Misconceptions About Stars

Misconception

Correction

Bigger stars live longer.

More massive stars burn fuel faster and have shorter lifespans.

A star's brightness only depends on its distance.

Brightness depends on both distance and its intrinsic luminosity.

All stars are the same color.

A star’s color indicates its surface temperature.

Heavy elements are only made when stars die.

Some heavy elements are fused during a massive star's life.

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Summary

  • Parallax measures stellar distances, while luminosity and apparent brightness describe a star's brightness.

  • The H-R diagram classifies stars by temperature and luminosity, showing the main sequence.

  • A star's mass determines its life cycle, from a protostar to its final stage.

  • Stars create energy through nuclear fusion, and supernovas distribute heavy elements into space.

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Poll

On a scale of 1-4, how confident are you about the concepts covered in today's review?

1

2

3

4

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Stars

Middle School

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