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Calc 7.0 Mental u-sub Exploration

Calc 7.0 Mental u-sub Exploration

Assessment

Presentation

•

Mathematics

•

12th Grade

•

Practice Problem

•

Easy

•
CCSS
RL.2.6, HSF.TF.B.7, HSA.CED.A.1

+2

Standards-aligned

Created by

Elizabeth Mendenhall

Used 1+ times

FREE Resource

4 Slides • 23 Questions

1

Open Ended

What's your name?

2

Open Ended

What's your class period?

3

​7.0 Mental u-Sub

By Elizabeth Mendenhall

4

Caution!

Caveat:  This works if u is a first-degree polynomial
(because du = constant * dx). 

With powers greater than 1, it’s worth the time to write out the u-substitution.

5

Fill in the Blanks

You should use mental u-sub when u=x?u=x^?

has a power of _.

6

Multiple Choice

Explore, using regular u-sub. Is there a pattern/shortcut?

∫cos⁡(2x)dx = ?\int_{ }^{ }\cos\left(2x\right)dx\ =\ ?

1

−12sin⁡(2x)+C-\frac{1}{2}\sin\left(2x\right)+C

2

−2sin⁡(2x)+C-2\sin\left(2x\right)+C

3

12sin⁡(2x)+C\frac{1}{2}\sin\left(2x\right)+C

4

2sin⁡(2x)+C2\sin\left(2x\right)+C

7

Multiple Choice

Explore, using regular u-sub. Is there a pattern/shortcut?

∫cos⁡(14x)dx = ?\int_{ }^{ }\cos\left(\frac{1}{4}x\right)dx\ =\ ?

1

14sin⁡(14x)+C\frac{1}{4}\sin\left(\frac{1}{4}x\right)+C

2

4sin⁡(14x)+C4\sin\left(\frac{1}{4}x\right)+C

3

−14sin⁡(14x)+C-\frac{1}{4}\sin\left(\frac{1}{4}x\right)+C

4

−4sin⁡(14x)+C-4\sin\left(\frac{1}{4}x\right)+C

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​In u-sub, when x has a coefficient, what pattern did you observe?

9

Multiple Choice

How often does this pattern work?

∫cos⁡(2x−1)dx = ?\int_{ }^{ }\cos\left(2x-1\right)dx\ =\ ?

HINT: u = 2x -1 → du = 2 dx → constant is 1/2

1

12sin⁡(2x−1)+C\frac{1}{2}\sin\left(2x-1\right)+C

2

2sin⁡(2x−1)+C2\sin\left(2x-1\right)+C

10

Multiple Choice

What if there's an e?

∫e−2xdx = ?\int_{ }^{ }e^{-2x}dx\ =\ ?

HINT: u = -2x → du = -2 dx → constant is -1/2

1

−2e−2x+C-2e^{-2x}+C

2

−12e−2x+C-\frac{1}{2}e^{-2x}+C

11

media

Use mental u-sub for each. How?
1. Find u.
2. Then find and flip du.

​

​Practice time!

12

Multiple Choice

∫sin⁡(2x) dx =\int_{ }^{ }\sin\left(2x\right)\ dx\ =

1

−12cos⁡(2x)+C-\frac{1}{2}\cos\left(2x\right)+C

2

12cos⁡(2x)+C\frac{1}{2}\cos\left(2x\right)+C

3

−2cos⁡(2x)+C-2\cos\left(2x\right)+C

4

2cos⁡(2x)+C2\cos\left(2x\right)+C

13

Multiple Choice

∫e3x dx =\int_{ }^{ }e^{3x}\ dx\ =

1

3e3x+C3e^{3x}+C

2

13e3x+C\frac{1}{3}e^{3x}+C

3

13xe3x+C\frac{1}{3x}e^{3x}+C

4

3xe3x+C3xe^{3x}+C

14

Multiple Choice

Quick review before you try this with u-sub: ∫1x dx =\int_{ }^{ }\frac{1}{x}\ dx\ =

1

ln⁡∣x∣+C\ln\left|x\right|+C

2

x00+C\frac{x^0}{0}+C

3

−1x2+C-\frac{1}{x^2}+C

15

Fill in the Blanks

∫11+2x dx\int_{ }^{ }\frac{1}{1+2x}\ dx

For this integral, what is u?

Type answer...

16

Multiple Choice

Now do this carefully:

∫11+2xdx =\int_{ }^{ }\frac{1}{1+2x}dx\ =

1

12ln⁡∣1+2x∣+C\frac{1}{2}\ln\left|1+2x\right|+C

2

2ln⁡∣1+2x∣+C2\ln\left|1+2x\right|+C

3

ln⁡∣1+2x∣+C\ln\left|1+2x\right|+C

17

Multiple Choice

∫12+xdx =\int_{ }^{ }\frac{1}{2+x}dx\ =

1

12ln⁡∣2+x∣+C\frac{1}{2}\ln\left|2+x\right|+C

2

2ln⁡∣2+x∣+C2\ln\left|2+x\right|+C

3

ln⁡∣2+x∣+C\ln\left|2+x\right|+C

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Multiple Choice

∫12+7xdx =\int_{ }^{ }\frac{1}{2+7x}dx\ =

1

17ln⁡∣2+7x∣+C\frac{1}{7}\ln\left|2+7x\right|+C

2

7ln⁡∣2+7x∣+C7\ln\left|2+7x\right|+C

3

27ln⁡∣2+7x∣+C\frac{2}{7}\ln\left|2+7x\right|+C

19

Multiple Choice

∫72+7xdx =\int_{ }^{ }\frac{7}{2+7x}dx\ =

1

17ln⁡∣2+7x∣+C\frac{1}{7}\ln\left|2+7x\right|+C

2

7ln⁡∣2+7x∣+C7\ln\left|2+7x\right|+C

3

ln⁡∣2+7x∣+C\ln\left|2+7x\right|+C

20

Multiple Choice

∫−4sin⁡(12x) dx =\int_{ }^{ }-4\sin\left(\frac{1}{2}x\right)\ dx\ =

1

−2cos⁡(12x)+C-2\cos\left(\frac{1}{2}x\right)+C

2

2cos⁡(12x)+C2\cos\left(\frac{1}{2}x\right)+C

3

−8cos⁡(12x)+C-8\cos\left(\frac{1}{2}x\right)+C

4

8cos⁡(12x)+C8\cos\left(\frac{1}{2}x\right)+C

21

Multiple Choice

∫2e3x dx\int_{ }^{ }2e^{3x}\ dx  

1

6e3x+c6e^{3x}+c  

2

23e3x+c\frac{2}{3}e^{3x}+c  

3

2e32x2+c2e^{\frac{3}{2}x^2}+c  

4

2e32x+c2e^{\frac{3}{2}x}+c  

22

Multiple Choice

∫e6−11x dx\int_{ }^{ }e^{6-11x}\ dx

1

−11e(6x−112x2)+C-11e^{\left(6x-\frac{11}{2}x^2\right)}+C

2

−11e6−11x+C-11e^{6-11x}+C

3

−111e6−11x+C-\frac{1}{11}e^{6-11x}+C

4

−111e(6x−112x2)+C-\frac{1}{11}e^{\left(6x-\frac{11}{2}x^2\right)}+C

23

Multiple Choice

∫ 12e12x dx\int\ \frac{1}{2}e^{\frac{1}{2}x}\ dx

1

14e12x+C\frac{1}{4}e^{\frac{1}{2}x}+C

2

e12x+Ce^{\frac{1}{2}x}+C

3

12e12x+C\frac{1}{2}e^{\frac{1}{2}x}+C

24

Multiple Choice

Reminder: if x has a degree greater than 1, use traditional u-sub.

∫xcos⁡(x2)dx\int x\cos(x^2)dx

1

−2sin⁡(x2)+C-2\sin\left(x^2\right)+C

2

2sin⁡(x2)+C2\sin\left(x^2\right)+C

3

−12sin⁡(x2)+C-\frac{1}{2}\sin\left(x^2\right)+C

4

12sin⁡(x2)+C\frac{1}{2}\sin\left(x^2\right)+C

25

Multiple Choice

Reminder: if x has a degree greater than 1, use traditional u-sub.

∫cos⁡(4x) esin⁡(4x)dx\int\cos\left(4x\right)\ e^{\sin\left(4x\right)}dx

1

4esin⁡(4x)+C4e^{\sin\left(4x\right)}+C

2

14esin⁡(4x)+C\frac{1}{4}e^{\sin\left(4x\right)}+C

3

−4esin⁡(4x)+C-4e^{\sin\left(4x\right)}+C

4

−14esin⁡(4x)+C-\frac{1}{4}e^{\sin\left(4x\right)}+C

26

Multiple Choice

Write down as many steps as you need: ∫1212x+1dx\int_1^2\frac{1}{2x+1}dx

1

2 ln⁡ 22\ \ln\ 2

2

12ln⁡2\frac{1}{2}\ln2

3

2(ln⁡5−ln⁡3)2\left(\ln5-\ln3\right)

4

12(ln⁡5−ln⁡3)\frac{1}{2}\left(\ln5-\ln3\right)

27

Poll

How is mental u-sub going?

I'm confident

I have to be careful to not make mistakes

I need more practice

Help!

pattern-tertiary

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