Calculus Review 11-11

Find the slope of the tangent line to f(x) = -3x²-6x at x = 1.

• m = 0
• m = 12
• m = -9
• m = -12

Tags

CCSS.8.EE.B.5

Find the derivative of f(x) = 6x³⁰ -2x¹⁵ + 4x³ - 2x + 1

• f'(x) = 18x²⁹ + 30x¹⁵ + 12x³ 
• f'(x) = 180x²⁹ - 30x¹⁴ + 12x² 
• f'(x) = 180x²⁹ - 30x¹⁴ + 12x² - 2
• f'(x) = 180x²⁹ - 30x¹⁴ + 12x² +1

If the position function for a particle is s(t) = -t² - t, what is the velocity function for the particle? 

• v(t) = -2
• v(t) -2t - 1 
• v(t) = t³
• v(t) = -t

If the position of a particle is represented by s(t) = -t² + 1, what is its position at t = 1? 

• Position = 0
• Position = 1
• Position = 2
• Position = -1 

If the position of a particle is represented by s(t) = -t² + 1, what is its velocity at t = 1?  

• Velocity = 0
• Velocity = 1
• Velocity = -1
• Velocity = -2

Find the derivative. f(x) = -8x^-3 + 5x - cotx

• f'(x) = -24x^-4 + 5 - csc²x
• f'(x) = 24x^-4 + 5 + csc²x
• f'(x) = 24x^-2 + 5 - cscxcotx
• f'(x) = 24x^-4 + 5 + cscxcotx

Find the derivative f(x) = (x² + 2x)⁵

• f'(x) = 5(2x+2)⁴
• f'(x) = 5(x² + 2x)⁴
•  f'(x) = 5(x² + 2x)⁴(2x)
• f'(x) = 5(x² + 2x)⁴(2x + 2)

Find the derivative f(x) = (3x + 5)⁴

• f'(x) = 12(3x)³
• f'(x) = 12(3x + 5)³
• f'(x) = (3)⁴
• f'(x) = (3x + 5)³

Find the derivative of f(x) = x²sinx

• f'(x) = 2xsinx - x²cosx
• f'(x) = 2xsinx + x²sinx
• f'(x) = 2xsinx + x²cosx
• f'(x) = 2xcosx

Find the derivative f(x) = tanxcosx

• f'(x) = sec²xcosx - tanxsinx
• f'(x) = sec²xcosx + tanxsinx
• f'(x) = sec²xsinx
• f'(x) = sec²xcosx - tanxcosx