Modern Math Unit 7

Solve for the zeros of -x² -3x+4 = 0

• x = -1 and 4

• x = 0 and -1

• x = 1 and -4

• x = 0 and 1

Solve for the zeros of 6x² - 54 = 0

• x = -9 and 0

• x = 3 and 6

• x = -3 and 6

• x = -3 and 3

Solve for the zeros of 25x² - 9 = 0.

• x = 5 and 3

• x = -5 and 3

• x = -3/5 and 3/5

• x= -5/3 and 5/3

Solve for the x-intercepts for x² - 15x + 44 = 0

• (4, 0) and (11, 0)

• (0, 44) and (0, -4)

• (4, 0) and (0, 44)

• no real solution

For f(x) = x² + 6x -7 the vertex is

• (0, -7)

• (-3, -16)

• (1, 0)

• (-7, 0)

For f(x) = x² -3x +4 the y-intercept is

• (0, -1)

• (0, 1)

• (0, -4)

• (0, 4)

• (1.5, -6.25)

Simplify (2x²y²)³(-4xy²)

• -8x⁶y⁴

• 32x⁶y⁸

• 8x⁷y⁴

• -32x⁷y⁸

Compared with y=x² , f(x) = (x-3)² -7 is shifted

• left 3 and down 7

• right 3 and up 7

• left 3 and up 7

• right 3 and down 7

For a parabola that opens down with a vertex (-2, 5) find the possible correct quadratic equation(s).

• y= -(x-2)²+5

• y= -(x+2)² +5

• y= (x+2)(x+5)

• y=-(x+5)(x+2)

• y= -x² -4x + 1

Find the slope between (-6, -4) and (4, 0).

• 5/2

• 2/5

• -5/2

• -2/5

• undefined