HAlg2 Midterm Review Units 1-4 SP2020

What is the first step to solving THIS equation by completing the square?
a² + 10a + 21 = 0

• Set the equation equal to zero
• Divide 10 by 2 and add the result to both sides
• Add a² and 10a together
• Subtract the 21

Tags

CCSS.HSA-REI.B.4B

(4i)(-3i)

• -12i²

• -12i

• 12

• i

Tags

CCSS.HSN.CN.A.1

CCSS.HSN.CN.A.2

(-1 + 5i) + (-2 - 3i)

• -3 + 8i

• 3 - 8i

• -3 - 2i

• -3 + 2i

Tags

CCSS.HSN.CN.A.1

CCSS.HSN.CN.A.2

Calculate(Divide, multiply by conjugate):

• 12/5 − 4/5i
• -8/10i − 4/5 
• -4/5 + 12/5i
• 12/5 + 4/5i

Tags

CCSS.HSN.CN.A.1

CCSS.HSN.CN.A.2

CCSS.HSN.CN.A.3

f(x) = 3x + 10
g(x) = x - 2
Find g(f(x))

• 3x + 8
• 3x - 2
• 3x + 4
• None of these.

Tags

CCSS.HSF-BF.A.1C

Factor by grouping:
3x³-x²+6x-2

• (x²+2)(3x+1)
•  (x²+2)(3x-1)
• (3x³+6x)(x²-2)
• none of the aboe

Multiply.
(b+3)(b²+2b+1)

• b³+6b²+6b+3
• b³+5b²+7b+3
• 4b³+8b²+3b
• 3b³+6b²+3b

Tags

CCSS.HSA.APR.A.1

(3a + 4)²

• 9a²+12a+16
• 9a²+24a+16
• 9a²+12a+8
• 9a²+24a+8

Tags

CCSS.HSA.APR.C.4

(3x³ + 5x - 1) ÷ (x + 1)

• 3x³ - 3x² + 8x - 9
• 3x² - 3x + 8 - 9/x+1
• 3x² + 3x + 8 + 7/x+1
• 3x³ + 3x² + 8x + 7

Tags

CCSS.HSA.APR.D.6

Find all the real zeros of the function 
f(x) = 2x³ - 19x² + 38x + 24 given that x-4 is a factor.

• x = 1/2, -6
• x = -1/2, 6
• x = 4, -1/2, 6
• x = -4, 1/2, -6

Tags

CCSS.HSA.APR.B.2