ALGEBRA Semester 1 REVIEW

Solve:
6(5x - 3) + 2 = 14

• 2
• .5
• -1
• 1

Tags

CCSS.7.EE.B.4A

Solve:
32 - 7x = -6(x + 3)

• 50
• 3
• -3
• -50

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

Write equation of the line containing (4,2) and (3,5)

• y = -3x + 14

• y = 3x + - 4

• y = -3x - 4

• y = -3x + 10

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

Write the equation of the line that passes through the point (1, -1) and has a slope of -4.

• y = -4x + 3

• y = -4x - 3

• y = -4x + 5

• y = -4x - 5

Write an equation using the points:
(0,3) and (2,-1)

• y = -2x + 3
• y = 2x + 3
• y = 2x - 3
• y = -2x - 3

Tags

CCSS.HSA.CED.A.2

8x + 4y= 16

• y = -8x + 16
• y = 2x -4
• y = -2x + 4
• y = -8x + 12

Tags

CCSS.6.EE.C.9

For the equation
y - 3 = 2(x + 4),
the line has a slope of 2 and contains what point?

• (-4, 3)
• (3, -4)
• (-3, -4)
• (-4, -3)

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSA.REI.D.11

For the equation
y + 1 = -3(x - 5),
the line contains the point (5, -1) and has a slope of?

• -1
• 1
• -3
• 5

Tags

CCSS.HSG.GPE.B.5

Write the equation in point-slope form of the line that passes through the given point and has the given slope.
(4, -7); m = -1/4

• y + 7 = -1/4(x - 4)
• y - 4 = -1/4(x + 7)
• y + 7 = 4(x - 4)
• y - 7 = -1/4(x - 4)

Tags

CCSS.HSA.SSE.A.2

Write the equation in point-slope form for the line that contains the points
(-2, -3), (4, 3)

• y - 3 = 1(x - 2)
• y + 3 = 1(x + 2)
• y -3 = -1(x + 2)
• y + 3 = -1(x - 2)

Tags

CCSS.HSG.GPE.B.5