Math 2 Final Exam Review

Solve for the value of x.

• 5.0

• 6.1

• 7.7

• 6.4

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Find the measure of the missing angle.

• 32°

• 44°

• 61°

• 50°

Tags

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Solve for X

• 7.5
• 4.8
• 13.33
• 5

Tags

CCSS.8.EE.B.6

Triangle ABC is translated to triangle A'B'C'. Which algebraic rule shows this translation?

• (x-2, y+5)

• (x+2, y-9)

• (x-2, y+9)

• (x-9, y+2)

Tags

CCSS.HSG.CO.A.2

CCSS.HSG.CO.A.4

CCSS.HSG.CO.A.5

CCSS.HSG.CO.B.6

What transformation is happening?
(x, y) ----> (x + 2, y - 3) 

• slide up 2, left 3
• slide right 2, up 3
• slide right 2, down 3
• slide left 3, right 2

Tags

CCSS.8.G.A.3

CCSS.HSG.CO.A.5

Reflect the point (2, -4) over the y-axis.

• (-4, 2)
• (-2, 4)
• (-2, -4)
• (2, 4)

Tags

CCSS.8.G.A.3

CCSS.HSG.CO.A.5

Find the measure of the missing angle.

(just type the number, not the degree symbol)

Tags

CCSS.HSG.CO.C.10

Determine the measure of angle S.

• A

• B

• C

• D

Tags

CCSS.HSG.CO.C.10

Determine the measure of ∠A.

• 53 degrees

• 37 degrees

• 49 degrees

• 41 degrees

Tags

CCSS.HSF.TF.A.2

A ball is thrown straight up into the air from an initial height of 49 meters with an initial velocity of 14.7 meters per second. The height of the ball in meters, h, can be modeled by the following quadratic equation, where t is the time in seconds after the ball was thrown.

h = -4.9t² + 14.7t + 49

How long after the ball was thrown did it reach its maximum height?

• 1.5 seconds

• 2 seconds

• 2.5 seconds

• 3 seconds

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.1