8G Lesson z11 - Solving a System of Equations by Substitution

Solve the System of Equations by Substitution: 4x + 6y = 16 and x = -2

• (-2, 1)

• (-2, 4)

• (-2, 2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the System of Equations by Substitution: y = -4x - 3 and y = -2x + 1

• (2, -11)

• (-2, 5)

• (2, -3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the System of Equations by Substitution: x + 4y = 13 and -2x - 4y = -18

• (2, 3)

• (5, 2)

• (1, 3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the System of Equations by Substitution: -9x + y = -8 and -3x - y = -4

• (2, 10)

• (-8, -4)

• (1, 1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using substitution:

y = 7x + 9

2y + 2x = -18

• (6.75, 2.25)

• (2.25, 6.75)

• (-2.25, -6.75)

• (-2.25, 6.75)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = 3x
2x + y = 20

• (4, 8)
• (3, 9)
• (2, 6)
• (4, 12)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = 5x 
3x - y = 10

• (-5, -25)
• (2, 10)
• (-2, -1)
• (5, 25)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

x = 4y - 10
x - 2y = -4

• (4, 6)
• (2, 3)
• (3, 2)
• (6, 2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to the system?
8x + 4y = 12
y = -2x + 3

• (0,3)
• (3,0)
• No solution(parallel lines)
• Infinitely many solutions

Tags

CCSS.8.EE.C.8B

Solve for x and y
y = 2x + 1
y = 4x - 1

• (1,3)
• (-1,-3)
• (-1,3)
• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6