SPLTV
Quiz
•
Mathematics
•
10th Grade
•
Practice Problem
•
Hard
RARAS BUDIARTI
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5 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
1. Tentukan mana yang merupakan SPLTV …..
x + y = 10
x + 2y = 19
x - 2y + 5z = 1
-x + z = 2
y - 6 = 0
x + 2y = 12
2x + 2y =18
b + a = 6
2x + y + 4z = -5
a - z = 0
y - 2 b = 3
2x + y = 4z = -5
a = 3
y - 2b = 3
2.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Diketahui keliling segitiga ABC 70 cm, Panjang AC adalah 2 cm lebihnya dari panjang AB. Panjang BC adalah 6 cm kurangnya dari panjang AC. Jika x menyatakan panjang AB, y menyatakan panjang BC, dan z menyatakan panjang AC, maka model matematika dari hubungan panjang sisi-sisi segitiga ABC adalah….
x + y = z = 35
x - z = 3
y - z = -6
x + y + z = 35
x - z = 2
y - z = 6
x + y + z = 70
x-z = 2
y - z = 6
x + y + z = 70
x-z = 2
y - z = 6
x + y + z = 70
x - z = -2
y - z = -6
3.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Diketahui tiga bilangan a, b dan c . Rata -rata dari ketiga bilangan itu sama dengan 16. Bilangan kedua ditambah 20 sama dengan jumlah bilangan lainnya. Bilangan ketiga sama dengan jumlah bilangan lain dikurang empat. Tentukan model matematika dari permasalahan tersebut .....
3a + 3b + 3c = 48
a - b + c = 20
a + b -c = 4
3a - 3b + 3 c = 6
a - b + C = 20
a + b - c = 4
3a + 3b - 3c = 48
a + b + c = 6
a + b - c = 4
3a + 3b - 3 c = 48
a - b = 20 + c
a + b - c = 4
3a + 3b - 3c = 48
a - b = 20 - c
a + b = 4
4.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Masa kehamilan rata-rata (dalam hari) dari gajah, badak, dan unta apabila dijumlahkan adalah 1.520 hari. Masa kehamilan badak adalah 58 hari lebih lama daripada unta. Dua kali masa kehamilan unta kemudian dikurangi 162 merupakan masa kehamilan gajah.
x + y = 1.520
y - z = 58
x - 2 z = -162
x + y - z = 1.520
y - z = 58
x - 2z = -162
x + y + z = 1.520
y - z = 58
x - 2 z = -162
x + y - z = -1.520
y - z = 58
x - 2z = -162
x + y + z = -1.520
y - z = 58
x - 2z = -162
5.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Sebuah toko alat tulis menyediakan spidol aneka warna. Perbandingan antara banyak spidol biru dan spidol merah 3 : 4. Perbandingan antara banyak spidol merah dan spidol hitam adalah 4 : 5. Jumlah ketiga jenis spidol tersebut adalah 430 buah. Jika x, y, z berturut-turut menyatakan banyak spidol biru, merah, hitam, maka SPLTV yang menyatakan hubungan ketiga jenis spidol adalah …..
4x = 3y
4y = 5z
x + y + z = 430
x + y + z = 430
x + y + z = 430
4x = 3y
4y = 5z
x + y + z = 430
x =
x + y = z = 430
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