Algebra 1: Unit 3 Test Review

Identify the equations that are in slope-intercept form.

• y = 3

• y = x² + 7

• x = 2y + 3

• y = 4x + 2

• y - 1 = x + 13

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Identify the equations that are in slope-intercept form.

• 2x + 3y = 16

• y = x

• y - 5 = 2(x + 12)

• y = 17x

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Write the slope of the line that passes through the points (7, -3) and (-1,1) in simplest form.

• -4/8

• -1/2

• -2

• 8/-4

Tags

CCSS.8.EE.B.5

Write the equation of the line that passes through the point (-2, -7) and m=-3 in point-slope form.

• y - 7 = -3(x - 2)

• y + 7 = -3(x + 2)

• y + 2 = -3(x + 7)

Rearrange the equation from point-slope form into slope-intercept form.

y - 2 = -3(x - 1)

• y = 3x - 1

• y = -3x + 1

• y = -3x + 5

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Write the equation of the linear function in point-slope form using the right hand point.

• y - 2 = 3(x - 8)

• y - 8 = 3(x - 2)

• y = 3x + 2

• y = 2x + 3

Tags

CCSS.8.EE.B.6

CCSS.8.F.B.4

CCSS.8.SP.A.3

Richard owns a plumbing company. After two hours of work, a client owed him $72. If he works for five hours, the client owes him $162.

Create a linear equation in slope-intercept form that represents the total cost after "x" hours of work.

• y = 30x + 162

• y = 162x + 12

• y = 30x + 12

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

Knowing that the cost of Richard's plumbing service can be modeled by the equation y = 30x + 12, how much would it cost for seven hours of work?

• 114

• 222

• 210

Tags

CCSS.HSF.LE.B.5

Write an equation that shows the formula solved for x

y = mx + b

• x = m(y - b)

• x = $\frac{y-b}{m}$

• x = $\frac{y\ +\ b}{m}$

Tags

CCSS.HSA.CED.A.4

Write an equation that shows for formula solved for h

a = $\frac{8\left(h+19\right)}{3}$  

• h = $\frac{3a}{8}-19$  

• h = $\frac{a+3}{8}-19$  

• h = 3a - 27

Tags

CCSS.HSA.CED.A.4