Writing Equations of Circles (honors)

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x-4)²+(y-3)²=25, the radius is

• 4
• 3
• 5
• 25

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the center of the circle is at...

• (-2, 3)
• (-3, 2)
• (2, -3)
• (3, -2)

Tags

CCSS.HSG.GPE.A.1

What is the equation of the circle?

• (x+1)² + (y +1)² = 3

• (x+1)² + (y -1)² = 3

• (x+1)² + (y +1)² = 9

• (x-1)² + (y -1)² = 9

Tags

CCSS.HSG.GPE.A.1

What is the equation for this circle?

• (x+1)²+(y+1)²=9

• x²+y²=9

• x²+y²=6

• x²+y²=3

Tags

CCSS.HSG.GPE.A.1

Find the center of the circle if the endpoints of a diameter of the circle are at (-12, -7) and (3, 5)

• (-9/2, -1)

• (-15/2, -6)

• (9/2, 1)

• (15/2, 6)

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36

• (x - 5)² + (y + 2)² = 6

• (x + 5)² + (y - 2)² = 36

• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1

The endpoints of a diameter of a circle are (3,1) and (9,5).Find the equation of the circle?

• (x−6)²+(y−3)²=13
• (x−3)²+(y−6)²=13²
• (x−5)²+(y−9)²=13
• (x−9)²+(y−5)²=169/4

Tags

CCSS.HSG.GPE.A.1

What is the equation of a circle with the center at (5, -7) and a point on the circle at (-3, -1)

• (x - 5)² + (x + 7)² = 100

• (x - 5)² + (x + 7)² = 10

• (x + 5)² + (x - 7)² = 100

• (x + 5)² + (x - 7)² = 10