SK025 CHAPTER 2:THERMOCHEMISTRY

SK025 CHAPTER 2:THERMOCHEMISTRY

University

10 Qs

quiz-placeholder

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SK025 CHAPTER 2:THERMOCHEMISTRY

SK025 CHAPTER 2:THERMOCHEMISTRY

Assessment

Quiz

Chemistry

University

Hard

Created by

ZUHAIZI ABDULLAH

Used 139+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Which of equation example for the definition:


"The heat release when 1 mol of substance is burned completely in excess oxygen"

C(s) + 2H2(g) → CH4(g)

HCl(aq) + NaOH(aq) → NaCl (aq) + H2O(l)

C2H6(l) + 7/2 O2(g) → 2CO2(g) + 3H2O(l)

Cl-(g) → Cl-(aq)

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Based on this equation, enthalpy of neutralization must be 1 mol of:


HCl(aq) + KOH(aq) → KCl (aq) + H2O(l)

HCl(aq)

KOH(aq)

KCl(aq)

H2O(l)

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Enthalpy combustion:


"The heat release when 1 mol of ____________ is burned completely in excess oxygen"

compound

element

substance

water

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Which of the following equation not the enthalpy of atomisation:

1/2Br2(l) → Br(g)

Al(l) → Al(g)

1/2Cl2(g) → Cl(g)

Mg(s) → Mg(g)

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Given the enthalpy of formation NO2(g)


1/2N2(g) + O2(g) → NO2(g) ΔH = +33.0 kJ

Calculate enthalpy of combustion, N2(g)

ΔH = +16.5 kJ/mol

ΔH = +33.0 kJ/mol

ΔH = -33.18 kJ/mol

ΔH = +66.0 kJ/mol

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Define enthalpy solution:

the heat absorbed when 1 mole of gaseous atoms is formed from its element

the heat released when 1 mole of gaseous ions is hydrated in water

the heat change when 1 mole of a substance is dissolves in excess water to form a very dilute solution

the heat change when 1 mole of a compound is formed from its elements

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Which of the equation correct refer to definition of formation, CH3OH (g)

CH3(g) + OH(g) ----> CH3OH (g)

C(s) + H2(g) + OH2(g) ----> CH3OH (g)

C(s) + 2H2(g) + 1/2O2(g) ----> CH3OH (g)

C(s) + H4(g) + O(g) ----> CH3OH (g)

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