Algebra 1 EOC PART 5

Write the following expression in radical form:

• a.)

• b.)

• c.)

• d.)

Write the following expression in radical form:

• a.)

• b.)

• c.)

• d.)

Factor: x² + 2x – 3

• (x - 2)(x + 1)

• (x + 1)(x - 3)

• (x + 2)(x - 1)

• (x - 1)(x + 3)

Factor

3a² + 4a + 1

• (7a-10)(a-8)

• Not factorable

• (3a+1)(a+1)

• (3a-1)(a-1)

Factor:

4h² - 12h + 9

• (2h - 3)²

• 4(h + 9)(h + 1)

• (2h - 3)(2h + 3)

• (h - 9)(4h - 1)

An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation 
 $s\left(t\right)=-16t^2+64t+80$  
What will be the object's maximum height? 
HINT!!!
USE THE FORMULA  $t=-\frac{b}{2a}$  where a,b and c, are taken from the equation  $ax^2+bx+c=0$ . Then substitute back into the original function to find the height.

• 2 ft

• 80 ft

• 144 ft

• 64 ft

How fast would you reach the water if you jump of a cliff using the formula: h(t) = -16t² + 8t + 24?

HINT: USE THE QUADRATIC FORMULA

• 8 sec.

• 1 sec.

• 1.5 sec.

• 1/4 sec.

At what time would you reach 16 ft above the water if you jump of a cliff using the formula:

h = -16t² + 8t + 24?

Hint: Solve for t after substituting h =16. Set the equation equal to zero.

• 8

• 1

• 1/2

• 1/4

Solve by factoring.

x² + 13x + 12 = 0

• x = -12, -1

• x = 12, 1

• x = 13, 1

• x = -13, -1

Solve using the Quadratic Formula.

2x² + 7x − 15 = 0

• x = −1.5, 5

• No Solution

• x = −5, 1.5

• x = 0.7, 5