Chain Rule and Implicit

Find dy/dx
xy+y²=2

• -y/(x+2y)
• y/(x+2y)
• -3y/x
• -3x/y

Find dy/dx by Implicit Differentiation
2xy³ - x²y = 2

• 2xy - 2y³
• 2y(x-y²)/x(6y²-x)
• -2y/x
• 2

Find the derivative:

y=(2^3x+4)

• 3(ln2)(2^3x+4)

• 3(2^3x+4)

• 3(2^3x+4/(ln2))

• 2^3x+4

What is the derivative?

• 1/(3x²+5)^1/4

• (3x)/(2(3x²+5))

• (2(3x²+5)^3/4)/(3x)

• (3x²+5)^1/4

Find f'(x)
f(x) = cos²(3x)/(9x⁴-6)

• [-6(9x⁴-6)cos(3x)sin(3x) - 36x³cos²(3x)]/(9x⁴-6)²
• [-6(9x⁴-6)sin(3x) - 36x³cos²(3x)]/(9x⁴-6)²
• -6cos(3x)sin(3x)/36x³
• [-2(9x⁴-6)cos(3x)sin(3x) - 36x³cos²(3x)]/(9x⁴-6)²

Tags

CCSS.HSF.TF.C.9