Distance and Midpoint addendum Jan 15

• $\left(2\ ,\ \frac{3}{2}\right)$

• $\left(.5,\ 3\right)$

• $\left(\frac{1}{2\ },\ \frac{3}{2}\right)$

• $\left(.5,\ .3\right)$

• $\sqrt{16}$

• $\sqrt{13^2}$

• $\sqrt{13}$

• $\sqrt{15}$

• $\left(-\frac{7}{2},\ 2\right)$

• $\left(3\ \frac{1}{2\ },\ 2\right)$

• $\left(\frac{5}{2},\ 2\right)$

• $\left(\frac{5}{2},\ -2\right)$

• 9.1

• 9

• $\sqrt{101}$

• $\sqrt{131}$

3c + 5 = 23

• c = 3
• c = 6
• c = 7
• c = 18

Tags

CCSS.7.EE.B.4A

What is the first step to solve this equation:
11 - 3x = 44

• Add 3 to both sides
• Subtract 11 from both sides
• Add 11 to both sides
• Divide 3 on both sides.

Tags

CCSS.7.EE.B.4A

-4x+1=21

• x=120
• x=5
• x=30
• x=-5

Tags

CCSS.7.EE.B.4A

6p - 5 =13

• 12
• 15
• 3
• -3

Tags

CCSS.7.EE.B.4A

Solve for w:
-6w + 1 = -11

• 2
• 1.2
• 12
• -2

Tags

CCSS.7.EE.B.4A

Solve.  -3x - 12 = 15

• 9
• -1
• 27
• -9

Tags

CCSS.7.EE.B.4A