Kartojimas

Kartojimas

11th Grade

12 Qs

quiz-placeholder

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Kartojimas

Kartojimas

Assessment

Quiz

Mathematics

11th Grade

Hard

Created by

Lukas Račkauskas

Used 3+ times

FREE Resource

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Kukia tai funkcija?

Laipsninė funkcija

Šaknies funkcija

Rodiklinės funkcija

Logoritminė funkcija

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Kuris tai grafikas?

y = log2x\log_2x

y = log12x\log_{\frac{1}{2}}x

y = log2(x2)\log_2\left(x-2\right)

y = log2(x+2)\log_2\left(x+2\right)

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

funkcijos f(x) = 3x33^x-3  

 Ef =(3;+)E_{f\ }=\left(3;+\infty\right)  

 Ef =(3;+)E_{f\ }=\left(-3;+\infty\right)  

 Ef =(0;+)E_{f\ }=\left(0;+\infty\right)  

 Ef =[3;+]E_{f\ }=\left[3;+\infty\right]  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt


 kokia f(x) = x4 apibrezimo sritis?kokia\ f\left(x\right)\ =\ \sqrt{x-4}\ apibrezimo\ sritis?  

 Df=[4; +)D_f=\left[4;\ +\infty\right)  

 Df={4}D_f=\left\{4\right\}  

 Df=(; +)D_f=\left(-\infty;\ +\infty\right)  

 Df=(4; +)D_f=\left(-4;\ +\infty\right)  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Išspreskite nelygybę grafiškai

 x53x^5\le-3  

 x(0;3)x\in\left(0;-\sqrt{3}\right)  

 x(;53)x\in\left(-\infty;-^5\sqrt{3}\right)  

 x(;3)x\in\left(-\infty;-\sqrt{3}\right)  

 x(0;53)x\in\left(0;-^5\sqrt{3}\right)  

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Kuomet sinuso funkcija didėja?

x(π2+2πn;π2+2πn)x\in\left(\frac{\pi}{2}+2\pi n;-\frac{\pi}{2}+2\pi n\right)

x(π+2πn ; π+2πn)x\in\left(-\pi+2\pi n\ ;\ \pi+2\pi n\right)

x(π2+2πn;π2+2πn)x\in\left(-\frac{\pi}{2}+2\pi n;\frac{\pi}{2}+2\pi n\right)

x(π+2πn ;π+2πn)x\in\left(\pi+2\pi n\ ;-\pi+2\pi n\right)

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Kuomet mažėja cosinuso funkcija?

x(π2+2πn;π2+2πn)x\in\left(-\frac{\pi}{2}+2\pi n;\frac{\pi}{2}+2\pi n\right)

x(π+2πn ;π+2πn)x\in\left(-\pi+2\pi n\ ;\pi+2\pi n\right)

x(π+2πn ;π+2πn)x\in\left(-\pi+2\pi n\ ;\pi+2\pi n\right)

x(0+2πn ;π+2πn)x\in\left(0+2\pi n\ ;\pi+2\pi n\right)

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